250+ TOP MCQs on Transmission(ABCD) Parameters and Answers

Network Theory Multiple Choice Questions on “Transmission(ABCD) Parameters”.

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1. In the circuit shown above, find the transmission parameter C.
A. 4/5
B. 3/5
C. 2/5
D. 1/5

Answer: D
Clarification: C = I₁/V₂ |I₂=0. By open circuiting b-b^‘ we get V₂ = 5 I₁ =>I₁/V₂ = 1/5. On substituting we get C = I₁/V₂=1/5 Ω.

2. In the circuit shown above, find the transmission parameter B.
A. 15/5
B. 17/5
C. 19/5
D. 21/5

Answer: B
Clarification: The transmission parameter B is given by B = -V₁/I₂ |V₂=0. Short circuiting b-b^‘, -I₂= 5/17 V₁ => -V₁/I₂ = 17/5. On substituting we get B=17/5 Ω.

3. In the circuit shown above, find the transmission parameter D.
A. 1/5
B. 3/5
C. 7/5
D. 9/5

Answer: C
Clarification: D is a transmission parameter and is given by D = -I₁/I₂ |V₂=0. Short circuiting b-b^‘, I₁= 7/17 V₁ and-I₂= 5/17 V₁. So we get I₁/I₂ = 7/5. So D=7/5.

4. The hybrid parameter h₁₁ is called?
A. short circuit input impedance
B. short circuit forward current gain
C. open circuit reverse voltage gain
D. open circuit output admittance

Answer: A
Clarification: h₁₁=V₁/I₁ |V₂=0. So the hybrid parameter h₁₁ is called short circuit input impedance.

5. The hybrid parameter h₂₁ is called?
A. open circuit output admittance
B. open circuit reverse voltage gain
C. short circuit forward current gain
D. short circuit input impedance

Answer: C
Clarification: h₂₁=I₂/I₁ |V₂=0. So the hybrid parameter h₂₁ is called short circuit forward current gain.

6. In the circuit shown in question 7, find the h-parameter h₂₁.
A. 1
B. -1
C. 1/2
D. -1/2

Answer: D
Clarification: Short circuiting b-b^‘, h₂₁ = I₂/I₁ when V₂=0 and -I₂= I₁/2 => I₂/I₁ = -1/2. So h₂₁ = -1/2.

7. In the circuit shown in question 7, find the h-parameter h₁₂.
A. 1/2
B. -1/2
C. 1
D. -1

Answer: A
Clarification: Open circuiting a-a^‘ we get V₁=I_y×2 and
I_y=I₂/2 and V₂=I_x×4 and I_x=I₂/2. On solving and substituting, we get h₁₂ =V₁/V₂=1/2.

8. In the circuit shown in question 7, find the h-parameter h₂₂.
A. 1
B. 2
C. 1/2
D. 3/2

Answer: C
Clarification: Open circuiting a-a^‘ we get V₁=I_y×2 and I_y=I₂/2 and V₂=I_x×4 and I_x=I₂/2. On solving and substituting, we get h₂₂ =I₂/V₂=1/2 Ω.