250+ TOP MCQs on Radiation – Basic Maxwell Equations and Answers

Antennas Multiple Choice Questions & Answers on “Radiation – Basic Maxwell Equations”.

1. The Maxwell equation ∇×E=(frac{-partial B}{partial t}) is derived from which law?
a) Amperes law
b) Faradays Law
c) Lens law
d) Gauss law
Answer: b
Clarification: Faradays law states that emf generated around a loop of wire in magnetic field is proportional to the rate of change of time-varying magnetic field through the loop.
Amperes law gives ∇×H=J
Lens law gives only the reason for the negative sign in the Faradays law of induction.
Gauss’s law states that the net flux of an electricfield in a closed surface is directly proportional to the enclosed electric charge.

2. The minus sign in the Faradays law of induction is given by ______
a) Lens Law
b) Gauss law
c) Amperes Law
d) Gauss law
Answer: a
Clarification:Lens law gives only the reason for the negative sign in the Faradays law of induction
emf=(-frac{partial phi}{partial t})
The minus sign indicates the direction of induced current.

3. Which of the following Maxwell equation is obtained from Amperes law?
a) ∇×H=J
b) emf=(-frac{partial phi}{partial t})
c) ∇×E=(frac{-partial B}{partial t})
d) ∇×D=ρv
Answer: a
Clarification:

  • Faradays Law                : ∇×E=(-frac{partial B}{partial t})
  • Amperes Law                : ∇×H=J+(frac{partial D}{partial t})
  • Gauss Law for electric field     : D=ρv
  • Gauss law for magnetic field  : ∇.B=0

4. Gauss for the Magnetic Field is given by ______
a) ∇.B=0
b) ∇×B=ρv
c) ∇×B=0
d) ∇.B=ρv
Answer: a
Clarification: Gauss law for magnetic field states that the net flux out of any closed surface is zero.
∇.B=0
This Maxwell equation is one of the equation used to determine the boundary conditions.

5. Gauss for the Electric Field is given by ______
a) ∇.D=0
b) ∇×D=ρv
c) ∇×D=0
d) ∇.D=ρv
Answer: d
Clarification:Gauss’s law for electric field states that the net flux of an electricfield in a closed surface is directly proportional to the enclosed electric charge. ∇.D=ρv
This Maxwell equation is one of the equation used to determine the boundary conditions.

6. Which of the Following Maxwell equation is for nonexistence of isolated magnetic charge?
a) ∇×E=-(-frac{partial B}{partial t})
b) ∇×H=J
c) ∇.D=ρv
d) ∇.B=0
Answer: d
Clarification: Gauss law for magnetic field states that the net flux out of any closed surface is zero.
∇.B=0
This is satisfied only when two different poles of magnet exist. So this Maxwell equation proves for the nonexistence of the isolated magnetic charge.

  • Faradays Law : ∇×E=(-frac{partial B}{partial t})
  • Amperes Law : ∇×H=J
  • Gauss Law for electric field : ∇.D=ρv

7. In which of the following Integral form of Maxwell equations, the surface is closed?
a) Amperes law
b) Gauss Law
c) Faradays Law
d) Both Amperes and Faraday law
Answer: b
Clarification: The surface integral is closed for the Gauss laws of magnetic and electric fields. It is open for the amperes and Faradays law.
Maxwell Equations:

  • Gauss law electric field : (oint_sD.ds =int_vrho_v dv )
  • Gauss law magnetic field : (oint_sB.ds =0)
  • Faradays law : (int_cE.dl =-int_sfrac{partial B}{partial t}.dS)
  • Amperes law : (int_cH.dl =int_s(frac{partial D}{partial t} + J).dS)

8. Divergence of Magnetic field is ______
a) volume charge density ρv
b) zero
c) infinite
d) dependent on magnetic field vector
Answer: b
Clarification: The Divergence of Magnetic is always zero.It is obtained from the Maxwell equation ∇.B=0 which is derived from the Gauss law of magnetic field.Gauss law for magnetic field states that the net flux out of any closed surface is zero. ∇.D=ρv.

9. Which of the following Maxwell equation is correct for a non-conducting and lossless medium?
a) ∇.D=ρv
b) ∇.D=0
c) ∇×D=ρv
d) ∇×E=0
Answer: b
Clarification: Since it is given non-conducting medium, the charge density ρv=0 and current density J=0. The Maxwell equations are:

  • Faradays Law                : ∇×E=(-frac{partial B}{partial t})
  • Amperes Law                : ∇×H=(frac{partial D}{partial t})
  • Gauss Law for electric field     : ∇.D=0
  • Gauss law for magnetic field  : ∇.B=0

10. Find skin depth of 5GHz for silver with a conductivity 6.1×107s/m and relative permittivity 1.
a) 0.00091m
b) 0.9113μm
c) 0.319μm
d) 0.1913μm
Answer: b
Clarification: The skin depth is given by (δ = sqrt{frac{1}{pi fμσ}})
Given f=5GHz
Conductivity σ= 6.1×107 s/m
And μr = 1 =>μ=4π ×10-7
⇨ (δ = sqrt{frac{1}{pi fμσ}}=0.9113mu m.)