7. Which of the following tautomeric form is more stable?
CH3-CH=O ↔ CH2=C-OH
(I) (II)
a) I
b) II
c) Both are equally stable
d) Both are unstable
Answer: a
Clarification: The keto–enol tautomerization chemical equilibrium is highly thermodynamically driven, and at room temperature the equilibrium heavily favors the formation of the keto form.
8. What is the stability order for the following compounds?
a) I > II > III
b) II > I > III
c) III > II > I
d) I > III > II
Answer: b
Clarification: The keto–enol tautomerization, less stable enolate ion will be formed faster as it is thermodynamically stable, so III is more stable than I.
II is most sable as it is keto form.
9. What is the stability order for the following compounds?
a) I > II > III
b) II > I > III
c) III > II > I
d) I > III > II
Answer: b
Clarification: The keto–enol tautomerization, less stable enolate ion will be formed faster as it is thermodynamically stable, so III is more stable than I.
II is most sable as it is keto form.
10. Which of the following structure can show tautomerism?
a) I
b) II
c) III
d) I and III
Answer: b
Clarification: Quinone has an α-hydrogen; however, it is a vinylic hydrogen (hydrogen attached to a carbon atom which is sp2 hybridized), it is very difficult to abstract such a hydrogen, and hence it becomes very less acidic. Therefore, no abstraction of α-hydrogen from it, by a base, hence, it does not show tautomerism, same is for III.