**Capgemini Aptitude Questions**

**1. A Man Purchased 15 Pens, 12 Books, 10 Pencils And 5 Erasers. The Cost Of Each Pen Is Rs.36, Each Book Is Rs.45, Each Pencil Is Rs.8, And The Cost Of Each Eraser Is Rs.40 Less Than The Combined Costs O**

Cost of each eraser = (36 + 8 -40) = Rs.4

Required amount = 15 * 36 + 12 * 45 + 10 * 8 + 5 * 4

540 + 540 + 80 + 20 = Rs.1180

**2. A, B And C Can Hire A Taxi For Rs. 2400 For One Day. A, B And C Utilized The Auto For 6 Hours, 8 Hours And 10 Hours Separately. What Amount Did C Pay?**

Let total fair rs.2400

C share=10/24*2400=1000

**3. A Train 125 Meter Long Is Running At 50 Km/hr. In What Time Will It Pass A Man Running At 5 Km/hr In A Similar Bearing In Which The Train Is Going?**

Distance=125 meter speed=50-5=45km/hr=>45*5/18=12.5 m/s

Time=125/12.5=10sec

**4. The Speed Of A Boat In Standing Water Is 9 Km Ph And The Speed Of The Stream Is 1.5 Km Ph. A Man Lines To A Place At A Separation Of 105 Km, And Returns To The Beginning Stage. The Aggregate Time Take**

Speed upstream = 7.5 km ph.

Speed downstream = 10.5 km ph.

Add up to time taken = 105/7.5 + 105/10.5 hours = 24 hours.

**5. A Is Twice As Fast As B Is Thrice As Fast As C. The Journey Covered By C In 42 Minutes, What Will Be Covered By A Is**

B is thrice as fast as C

C covered in 42 minutes

B covered in 42/3=14 min

**6. In A 1000 M Race, A Beats B By 200 Meters Or 25 Seconds. Find The Speed Of B ?**

Since A beats B by 200 m or 25 seconds, it implies that B covers 200 m in 25 seconds.

Hence speed of B = 200/25 = 8 m/s.

**7. In A Race Of 600 Meters, A Can Beat B By 60 Meters And In A Race Of 500 Meters; B Can Beat C By 50 Meters. By What Number Of Meters Will A Beat C In A Race Of 400 Meters ?**

A runs B runs C runs

600 meters race 600 m 540 m

500 meters race 500 m 450 m

Coming ratio A runs B runs C runs

300 meters-2700 meters-2430 meters

Unitary A runs B runs C runs

Methods 400m-360m-324m

A beat C by 400- 324=76 meters.

**8. Find The Least Number Which When Divided By 35 And 11 Leaves A Remainder Of 1 In Each Case.**

The least number which when divided by different divisors leaving the same remainder in each case

= LCM(different divisors) + remainder left in each case.

Hence the required least number

= LCM(35, 11) + 1 = 386.

**9. If 20 Men Can Construct A Divider 112 Meters In Length In 6 Days, What Length Of A Comparable Divider Can Be Worked By 25 Men In 3 Days ?**

20 men in 6 days can build 112 meters

25 men in 30 days can build=112*(25/20)*(3/6)

= 70 meters

**10. The Total Ages Of 5 Youngsters Conceived At The Interval Of 3 Years Each Is 50 Years. What Is The Age Of The Youngest Child ?**

Give the times of youngsters a chance to be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

At that point, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

**11. A 30% Loss On Cost Price Is What Percentage Loss On Selling Price ?**

Let CP=100, SP=70

Loss= 30/70*100=42.85%

**12. The Length Of A Rectangular Floor Is More Than Its Breadth By 200%. If Rs. 324 Is Required To Paint The Floor At The Rate Of Rs. 3 Per Sq M, Then What Would Be The Length Of The Floor?**

Let the length and the breadth of the floor be l m and b m respectively.

l = b + 200% of b = l + 2b = 3b

Area of the floor = 324/3 = 108 sq m

l b = 108 i.e., l * l/3 = 108

l2 = 324 => l = 18.

**13. What Was Be The Day Of The Week On Fifteenth August 2010 ?**

Fifteenth August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 jump years + 7 customary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

Jan. Feb. March April May June July Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Add up to number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.

Given day is Sunday.

**14. Five Men And Nine Women Can Do A Piece Of Work In 10 Days. Six Men And Twelve Women Can Do The Same Work In 8 Days. In How Many Days Can Three Men And Three Women Do The Work ?**

(5m + 9w)10 = (6m + 12w)8

=> 50m + 90w = 48w + 96 w => 2m = 6w => 1m = 3w 5m + 9w = 5m + 3m = 8m

8 men can do the work in 10 days.

3m +3w = 3m + 1w = 4m

So, 4 men can do the work in (10 * 8)/4 = 20 days.

**15. There Are Three Numbers. 5/7th Of The First Number Is Equal To 48% Of The Second Number. The Second Number Is 1/9th Of The Third Number. If The Third Number Is 1125, Then Find 25% Of The First Number?**

Let the first number and the second number be F and S respectively.

5/2 F = 48/100 S —-> (1)

S = 1/9 * 1125 = 125

(1) => 5/7 F = 48/100 * 125

=> F = 84

25% of F = 1/4 * 84 = 21.

**16. Merchandise Prepares Keeps Running At The Speed Of 72 Km Ph And Crosses A 250 M Long Stage In 26 Seconds. What Is The Length Of The Products Prepared ?**

Speed = 20 m/sec.

Time = 26 sec.

Then, x + 250 /26= 20

x + 250 = 520

x = 270.

**17. Three Pipes A, B And C Can Fill A Tank From Void To Full In 30 Minutes, 20 Minutes, And 10 Minutes Individually. At The Point When The Tank Is Unfilled, All The Three Funnels Are Opened. A, B And C Re**

Part filled by (A + B + C) in 3 minutes = 3 (1/30+1/20+1/10)= 3*11/60=11/20

Required proportion = 3/10 x 20/11 = 6 /11

**18. What Amount Does Kiran Get If He Invests Rs. 18000 At 15% P.a. Simple Interest For Four Years ?**

Simple interest = (18000 * 4 * 15)/100 = Rs. 10800

Amount = P + I = 18000 + 10800 = Rs. 28800

**19. A, B And C Mutually Thought Of Connecting With Themselves In A Business Wander. It Concurred That A Would Contribute Rs. 6500 For A Half Year, B, Rs. 8400 For 5 Months And C, Rs. 10,000 For 3 Months.**

For dealing with, A got = 5% of Rs. 7400 = Rs. 370.

Equalization = Rs. (7400 – 370) = Rs. 7030.

Proportion of their investment = (6500 x 6): (8400 x 5): (10000 x 3)

= 39000: 42000: 30000

= 13: 14: 10

B’s offer = Rs. 7030 x14/37= Rs. 2660.

**20. 3, 5, 11, 14, 17, 21**

Every one of the numbers aside from 14 is an odd number.

The number ’14’ is the main EVEN number.

**21. An Organic Product Vendor Had A Few Apples. He Offers 40% Apples And Still Has 420 Apples. Initially, He Had**

Assume initially he had x apples.

At that point, (100 – 40)% of x = 420.

60/100 x x = 420

x = 420 x 100 = 700.

**22. A Man Took Credit From A Bank At The Rate Of 12% P.a. Straightforward Intrigue. Following 3 Years He Needed To Pay Rs. 5400 Intrigue Just For The Period. The Essential Sum Acquired By Him Was**

Principal = Rs. 100 x 5400/1200×3 = Rs. 15000.

**23. What Sum Of Money Put At C.i Amounts In 2 Years To Rs.8820 And In 3 Years To Rs.9261?**

8820 —- 441

100 —- ? => 5%

x *105/100 * 105/100 = 8820

x*1.1025=8820

x=8820/1.1025 => 8000

**24. 16, 33, 65, 131, 261, (….)**

Each number is double the former one with 1 included or subtracted then again.

Along these lines, the following number is (2 x 261 + 1) = 523.

**25. A Shopkeeper Sells 20% Of His Stock At 10% Profit Ans Sells The Remaining At A Loss Of 5%. He Incurred An Overall Loss Of Rs. 4**

Let the total worth of the stock be Rs. x.

The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50

The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50

Total SP = 11x/50 + 38x/50 = 49x/50

Overall loss = x – 49x/50 = x/50

x/50 = 400 => x = 20000

**26. Three Fair Coins Are Tossed. What Is The Probability Of Getting At Most Two Heads ?**

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = occasion of getting at most two heads.

At that point E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P (E) = n (E)/n(S) = 7/8

**27. In An Exam, Amar Scored 64 Percent, Bhavan Scored 36 Percent And Chetan 44 Percent. The Maximum Score Awarded In The Exam Is 8**

Average mark scored by all the three boys =

[64/100 (800) + 36/100 (800) + 44/100 (800)] / 3 = 384

**28. An Entirety Of Cash At Basic Premium Adds Up To Rs. 815 Out Of 3 Years And To Rs. 854 Out Of 4 Years. The Aggregate Is**

S.I. for 1 year = Rs. (854 – 815) = Rs. 39.

S.I. for a long time = Rs.(39 x 3) = Rs. 117.

Principal = Rs. (815 – 117) = Rs. 698.

**29. Four Car Rental Agencies A, B, C And D Rented A Plot For Parking Their Cars During The Night. A Parked 15 Cars For 12 Days, B Parked 12 Cars For 20 Days, C Parked 18 Cars For 18 Days And D Parked 16 C**

The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15

= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60

Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.

The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k

It is given that A paid Rs. 1125

45k = 1125 => k = 25

246k = 246(25) = Rs. 6150

Thus the total rent paid by all the four agencies is Rs. 6150.

**30. A Man Has Rs. 480 In The Divisions Of One-rupee Notes, Five-rupee Notes And Ten-rupee Notes. The Quantity Of Notes In Every Section Is Equivalent. What Is The Aggregate Number Of Notes That He Has ?**

Give the number of notes of every division a chance to be x.

At that point x + 5x + 10x = 480

16x = 480 x = 30.

Consequently, add up to number of notes = 3x = 90

**31. A Man Pushes Downstream 30 Km And Upstream 18 Km, Taking 5 Hours Each Time. What Is The Speed Of The Stream (current)?**

Let x=speed of boat and y=speed of current

=30/ (x + y) =18/(x-y) =5 by solving y=1.2 km/hr

**32. A Man Purchases A Book For Rs.29.50 And Offers It For Rs. 31.**

So we have C.P. = 29.50

S.P. = 31.10

Gain = 31.10 – 29.50 = Rs. 1.6

Gain %=( Gain/Cost*100)%

= (1.6/29.50?100)%=5.4%

**33. 270 Meters In Length Prepare Running At The Speed Of 120 Km Ph Crosses Another Prepare Running Inverse Way At The Speed Of 80 Km Ph In 9 Seconds. What Is The Length Of The Other Prepare ?**

Relative speed = (120 + 80) km/hr

= 200 x 5/18 m/sec

= 500/9 m/sec.

**34. Tickets Numbered 1 To 20 Are Stirred Up And After That, A Ticket Is Drawn Indiscriminately. What Is The Probability Getting Ticket Drawn Has A Quantity Which Is A Difference Of 3 Or 5 ?**

Let, S = {1, 2, 3, 4, 19, 20}.

Let E = event of getting a few of 3 or 5 = {3, 6, 9, 12, 15, 18, 5, 10, 20}.

P (E) = n (E)/n(S) = 9/20

**35. A Boat Running Upstream Takes 8 Hours 48 Minutes To Cover A Specific Separation, While It Takes 4 Hours To Cover A Similar Separation Running Downstream. What Is The Proportion Between The Speed Of The**

At that point, remove canvassed upstream in 8 hrs. 48 min = Distance covered downstream in 4 hrs.

X* 8 4 /5= (y x 4)

44/5 x =4y

y = 11/5 x.

Required proportion = y + x/2: y – x /2

= 16/5 x 1/2: 6/5 x 1/2

= 8/5:3/5

= 8: 3.

**36. A Man Has Rs. 480 In The Sections Of One-rupee Notes, Five-rupee Notes, And Ten-rupee Notes. The Quantity Of Notes In Every Section Is Equivalent. What Is The Aggregate Number Of Notes That He Has?**

Give the number of notes of every group a chance to be x.

At that point x + 5x + 10x = 480

16x = 480

x = 30.

Consequently, add up to number of notes = 3x = 90.

**37. A Brick Measures 20 Cm * 10 Cm * 7.5 Cm How Many Bricks Will Be Required For A Wall 25 M * 2 M * 0.75 M?**

25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x

25 = 1/100 * x => x = 25000

**38. If A Card Is Drawn From A Well Shuffled Pack Of Cards, The Probability Of Drawing A Spade Or A King Is**

P(SnK) = P(S) + P(K) – P(SnK), where S denotes spade and K denotes king.

P(SnK) = 13/52 + 4/52 – 1/52 = 4/13

**39. What Was The Day Of The Week On 28th May 2006 ?**

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 conventional years + 1 jump year) = (4 x 1 + 1 x 2) 6 odd days

Jan. Feb. March April May

(31 + 28 + 31 + 30 + 28) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Add up to number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

**40. A Heap Of Stones Can Be Made Up Into Groups Of 2**

LCM of 16, 20, 25, 45 = 3600

1 * 3600 + 3 = 3603 not divisible by 21

2 * 3600 + 3 = 7203 is divisible by 21