Category: Class 11 Biology Objective Questions

Biology Multiple Choice Questions on “Eukaryotic Cells and it’s Organelles – 1”.

1. Which of these are not eukaryotic?
a) Plants
b) Fungi
c) Protists
d) Monerans
Answer: d
Clarification: Eukaryotic cells possess a true nucleus. Plants, fungi and protists are eukaryotic organisms as they have a well – defined nucleus. However, monerans do not possess a well – defined nucleus and are thus, prokaryotes.

2. Which of these structures are absent in eukaryotes?
a) Organised nucleus
b) Membrane bound organelles
c) Mesosome
d) Nuclear envelope
Answer: c
Clarification: Eukaryotic organisms have a well – defined nucleus. The nucleus is surrounded by a nuclear envelope. The various organelles are membrane bound. However, only prokaryotic organisms possess mesosomes.

3. Which of these are absent in plant cell?
a) Large central vacuole
b) Cell wall
c) Centriole
d) Plastid
Answer: c
Clarification: Plants cells are differentiated from animal cells on the basis of the presence of certain organelles such as plastids, cell wall and a large central vacuole. Only animal cells possess centrioles in their cytoplasm.

4. The structure of the cell membrane was studied in detail after the invention of the _____
a) electron microscope
b) light microscope
c) magnifying glass
d) confocal microscope
Answer: a
Clarification: The structure of the cell membrane was studied in detail in the 1950s after the advent of the electron microscope. The cell membrane is a phospholipid bilayer containing various proteins in its structure.

5. Which of these structures of the phospholipid bilayer is correctly matched with its property?
a) Phosphate head – hydrophobic
b) Phosphate head – hydrophilic
c) Lipid tail – hydrophilic
d) Lipid tail – Polar
Answer: b
Clarification: The cell membrane is a phospholipid bilayer in which the polar and hydrophilic phosphate head groups face outwards, while the non-polar and hydrophilic lipid tails face each other.

6. Which of these statements is not true regarding the cell membrane?
a) The phosphate heads are polar
b) It is a phospholipid bilayer
c) The hydrophilic tails face outwards
d) It contains integral proteins
Answer: c
Clarification: The cell membrane is a phospholipid bilayer in which the polar and hydrophilic phosphate head groups face outwards, while the non-polar and hydrophilic lipid tails face each other.

7. What is the percentage of protein in the cell membrane of human erythrocytes?
a) 52%
b) 40%
c) 37%
d) 33%
Answer: a
Clarification: The cell membrane is a phospholipid bilayer. It also contains various proteins. The protein and lipid percentages vary in different cells. Human erythrocyte membranes are 52% protein.

8. What is the percentage of lipids in the cell membrane of human erythrocytes?
a) 52%
b) 44%
c) 37%
d) 40%
Answer: d
Clarification: The cell membrane is a phospholipid bilayer. It also contains various proteins. The protein and lipid percentages vary in different cells. Human erythrocyte membranes are made of 40% lipids.

9. Which of these scientists proposed the fluid mosaic model of the cell membrane?
a) Schleiden and Schwann
b) Hershey and Chase
c) Singer and Nicholson
d) Watson and Crick
Answer: c
Clarification: Singer and Nicholson proposed the fluid mosaic model of the cell membrane in 1972. According to this model, the lateral movement of proteins was enabled by the quasi-fluid nature of lipid.

10. Peripheral proteins lie on the surface of the cell membrane. True or false?
a) True
b) False
Answer: a
Clarification: The cell membrane is a phospholipid bilayer. The cell membrane has two types of proteins- peripheral proteins and integral proteins. Peripheral proteins are present on the surface of the membrane.

11. Fluidity of the cell membrane is a measure of the _____
a) ability of water to pass through the membrane
b) ability of potassium ions to pass through the membrane
c) ability of sodium ions to pass through the membrane
d) ability to move within the membrane
Answer: d
Clarification: Fluidity of the cell membrane is the measure of the ability to move within the membrane. This movement is allowed due to the quasi-fluid nature of lipid present in the cell membrane.

12. Water moves across the cell membrane by _____
a) exocytosis
b) endocytosis
c) osmosis
d) active transport
Answer: c
Clarification: The cell membrane is a phospholipid bilayer which is semi – permeable. Water moves across this membrane by the process of diffusion. The diffusion of water across a semi – permeable membrane is known as osmosis.

13. Which of these molecules require a carrier protein to pass through the cell membrane?
a) Small neutral solutes
b) Water
c) Polar molecules
d) Non – polar molecules
Answer: c
Clarification: Since the cell membrane is a phospholipid bilayer having non – polar lipid tail groups, polar molecules cannot pass through the membrane without the assistance of carrier proteins present within the membrane.

14. Identify the component of the cell membrane.

a) Hydrophilic phosphate head
b) Hydrophobic phosphate tail
c) Hydrophilic lipid tail
d) Hydrophobic lipid head
Answer: a
Clarification: The cell membrane is a phospholipid bilayer in which the polar and hydrophilic phosphate head groups face outwards, while the non-polar and hydrophilic lipid tails face each other.

15. Which of these statements is not true regarding active transport?
a) It is an energy dependent process
b) Molecules are transported along their concentration gradient
c) Sodium – potassium pump requires active transport
d) ATP is utilised
Answer: b
Clarification: Active transport is the movement of molecules or ions from a region of their lower concentration to a region of their higher concentration, against the concentration gradient. It requires energy in the form of ATP.

Biology Multiple Choice Questions on “Biomolecules – Polysaccharides – 1”.

1. Which of these is a macromolecule?
a) Vitamins
b) Minerals
c) Lipids
d) Polysaccharides
Answer: d
Clarification: Vitamins, minerals and lipids are micro-molecules. This means that they have a molecular weight of less than 800 Da. Polysaccharides are macromolecules as they have a molecular weight greater than 10,000 Da.

2. Which of these is present in the acid insoluble pool of homogenized, strained tissue?
a) Ions
b) Minerals
c) Polysaccharides
d) Vitamins
Answer: c
Clarification: After living tissue is homogenized and strained, it separates into an acid soluble pool and an acid insoluble pool. The acid insoluble pool contains macromolecules such as polysaccharides.

3. Polysaccharide chains are made of ______
a) disaccharides
b) glucose
c) sugars
d) fructose
Answer: c
Clarification: Polysaccharide chains are made of repeating units of different sugars. Hence, polysaccharides are an example of heteropolymers, in which the polymer chain is made of different monomers.

4. Which of these is not a monosaccharide?
a) Sucrose
b) Glucose
c) Fructose
d) Galactose
Answer: a
Clarification: A monosaccharide or simple sugar is the basic unit of carbohydrates. Glucose, fructose and galactose are monosaccharides. Sucrose is a disaccharide which is made of a glucose monomer and a fructose monomer.

5. Cellulose is a _____
a) heteropolymer
b) homopolymer
c) dimer
d) monomer
Answer: b
Clarification: Cellulose is a homopolymer. This means that it is made of repeating units of the same monomer, which is glucose in the case of cellulose. Cellulose is the most abundant organic polymer on Earth.

6. Cellulose is a polymer of _____
a) galactose and fructose
b) glucose and fructose
c) glucose
d) glucose and galactose
Answer: c
Clarification: Cellulose is a homopolymer. This means that its chain consists of repeating units of a single type of monomer. Repeating units of glucose joined by glycosidic bonds form the polymer cellulose.

7. Which of these is a storehouse of energy in plant tissues?
a) Starch
b) Cellulose
c) Glucose
d) Fructose
Answer: a
Clarification: Plant tissues produce glucose by the process of photosynthesis. This glucose is converted to starch which is then stored in the plant tissue. It imparts energy to the plant through the process of respiration.

8. Which of these is a storehouse of energy in animal tissues?
a) Glucose
b) Cellulose
c) Starch
d) Glycogen
Answer: d
Clarification: Glucose is the source of energy for animal tissues. It is stored in the body in polymeric form in a polysaccharide called glycogen. Glycogen can be broken down into glucose for consumption by tissues when required by the body.

9. Inulin is a polymer of ______
a) glucose and fructose
b) glucose
c) fructose
d) glucose, fructose and galactose
Answer: c
Clarification: Inulin is a homopolymer. This means that the polymeric chain is formed from repeating units of the monomer fructose. The fructose units are joined to each other by glycosidic bonds to form inulin.

10. Fructose does not form homopolymers. True or false?
a) True
b) False
Answer: b
Clarification: Fructose is a monomer and is also known as fruit sugar. It can form homopolymers of repeating units of fructose joined by glycosidic bonds. The homopolymer thus formed is known as inulin.

11. Which part of glycogen is the reducing end?
a) Second monomer from the left
b) Second monomer from the right
c) Left end
d) Right end
Answer: d
Clarification: Glycogen is a polysaccharide composed of glucose monomers that has a branched structure. The right end of polysaccharide chains is the reducing end while the left end is the non-reducing end.

12. Which part of cellulose is the non-reducing end?
a) Second monomer from the left
b) Second monomer from the right
c) Left end
d) Right end
Answer: c
Clarification: Cellulose is a polysaccharide composed of glucose monomers that has a linear structure. The right end of polysaccharide chains is the reducing end while the left end is the non-reducing end.

13. The building blocks ok polysaccharides are _____
a) glucose units
b) disaccharides
c) monosaccharides
d) carbon molecules
Answer: c
Clarification: Polysaccharides are polymers of monosaccharides. Some monosaccharides are glucose, fructose and galactose. They are linked through glycosidic bonds to form chains of various polysaccharides.

14. Which of these is not true about cellulose?
a) It is the second most abundant organic polymer
b) It has linear chains
c) It is made of glucose subunits
d) It is a homopolymer
Answer: a
Clarification: Cellulose is a homopolymer of repeating glucose units joined to each other by glycosidic bonds. Cellulose chains are linear in structure. Cellulose is the most abundant organic polymer on Earth.

15. Which of these statements is not true regarding polysaccharides?
a) Cellulose has a linear structure
b) Inulin is a heteropolymer
c) Glycogen has a branched structure
d) Polysaccharide chains have a non-reducing left end
Answer: b
Clarification: Cellulose, inulin and glycogen are polysaccharides. Cellulose has a linear structure while glycogen has a branched structure. All polysaccharide chains have a non-reducing left end. Inulin is a homopolymer of fructose.

Biology Multiple Choice Questions on “Plant-Water Relations-1”.

1. Which part of the cell contains water-like substances with dissolved molecules and suspended in them?
a) Protoplasm
b) Cytoplasm
c) Cytosol
d) Matrix
Answer: a
Clarification: Protoplasm of the cell is a fluid, similar to water, contains all the molecules in it. Cytoplasm contains all the particles inside the membrane of a cell. Cytosol is a part of cytoplasm possessing all the organelles excluding the cell nucleus. Matrix is a fluid present in different types depending upon the type of specialized structure such as stroma is the matrix of chloroplast.

2. Woody parts of plants contain relatively less water while soft parts contain more water.
a) True
b) False
Answer: a
Clarification: Woody plants have dead vascular tissue so there is no conduction of water and do not contain much water. In case of soft parts, they have functional vascular tissue hence possess sufficient amount of water.

3. Statement A: Water is the limiting factor for plant growth and productivity.
Statement B: A minute amount of water is lost to the environment by the leaves.
a) Both the statements are true
b) Both the statements are false
c) Statement A is true but Statement B is false
d) Statement B is true but Statement A is false
Answer: c
Clarification: As water is lost in a large amount to the external surroundings due to many environmental and internal factors, hence, is the most important determinant of plant growth and productivity. More than 90% of water is lost to the environment by leaves due to transpiration and evaporation.

4. The amount of water lost by plants due to transpiration and guttation?
a) 98%
b) 12%
c) 92%
d) 50%
Answer: a
Clarification: The amount of water lost by plants due to transpiration and guttation is approximately 98%. Watermelon contains 92% of water. Herbs have 12% of their fresh weight as the dry matter. Mustard plant absorbs water having 50% of their weight in 5 hours.

5. Which potential is considered of negligible value?
a) Water potential
b) Matrix potential
c) Solute potential
d) Pressure potential
Answer: b
Clarification: Matrix potential is the energy developed due the attachment of water with non-dissolved solutes such as soil. It is of negligible value whereas Water potential is the ultimate energy and Solute potential and Pressure potential are important components of water potential.

6. The value of water potential of pure water is ________
a) 1
b) -1
c) 0
d) -2
Answer: c
Clarification: The water potential of pure water is highest with the numerical value of 0. 1 cannot be the value of water potential and -1, -2 values come when solute is dissolved or pressure is applied.

7. Concentration gradient is a mandatory condition for diffusion of substances irrespective of the process involved.
a) True
b) False
Answer: a
Clarification: All the processes require a redox potential in order to transport substances from one place to another. A concentration gradient is an essential condition for the transport of molecules of substances to occur.

8. The greater concentration of water in a system leads to _________
a) increased transpiration
b) increased solute potential
c) hypertonic condition
d) greater kinetic energy
Answer: d
Clarification: Increase in concentration of water in a system leads to increase in K.E and thereby the water potential of the plant. It reduces hypertonic solution and aim to achieve isotonic condition. It decreases the solute potential as the water content increases in comparison to solutes dissolved. Transpiration doesn’t depend on amount of water present in the system.

9. The unit of water potential is_________
a) psi
b) no unit
c) pascal
d) mmole per kg
Answer: c
Clarification: Pascal is the unit of water potential as it is also a kind of pressure. Psi is the Greek symbol use to the denote water potential. It must have a unit as it is not a ratio. mmole per kg is the unit of amount of micro and macro nutrients required by the plant.

10. Statement A: Solute potential increases with dissolution of solutes.
Statement B: The value of solute potential is always negative.
a) Both the statements are true
b) Both the statements are false
c) Statement A is true but Statement B is false
d) Statement B is true but Statement A is false
Answer: a
Clarification: Solute potential is a component of water potential which alters it depending on the amount of dissolved solute added or removed as well as the amount of water present. Since maximum value of water potential is zero which contains no solutes. Addition of solute decrease the water potential, therefore, the increment of solute potential is in negative terms.

Biology Multiple Choice Questions on “Higher Plants Photosynthesis – Electron Transport”.

1. The electron transport system occurs in _____
a) Thylakoid membrane
b) Stroma
c) Cytosol
d) Mitochondria
Answer: a
Clarification: It is in the thylakoid membrane, in which the electron transport system occurs. Each thylakoid membrane is a closed compartment that gets protons from stroma by the b₆ or f complex. Also, thylakoid membrane is impermeable to protons.

2. The first electron acceptor in photosystem 1 is _____
a) Plastoquinone
b) Cytochrome b
c) A Fe-S protein
d) Water
Answer: c
Clarification: The first electron acceptor in photosystem 1 is a Fe-S protein. It is a stable complex of iron and sulfur atoms bonded to a protein. It primarily accepts the electrons and passes onto NADP⁺.

3. Water produces electrons for the reduction reactions of photosynthesis.
a) True
b) False
Answer: a
Clarification: It is a true statement. The photolysis of water (2 molecules) produces four electrons that are required for the reduction reactions of photosynthesis which is needed for non-phosphorylation.

4. How much hydrogen protons are released by twelve water molecules?
a) 48
b) 6
c) 12
d) 24
Answer: d
Clarification: By understanding the photolysis equation, one water molecule gives 2 hydrogen protons. So, 12 water molecules will give 24 hydrogen protons.

5. The name of the scheme given to the transport of electrons is called as _______
a) Z scheme
b) W scheme
c) Y scheme
d) E scheme
Answer: a
Clarification: The scheme is called Z-scheme. This name was given due to the shape of the sequence. The transfer of electrons from PS II to NADP⁺ produces this scheme when the carries are placed in the order of the redox potential scale.

6. _____ is the only product in cyclic photophosphorylation.
a) ADP
b) ATP
c) Hydrogen
d) Oxygen
Answer: b
Clarification: ATP is the only product in cyclic photophosphorylation. PS II is not involved in this process. So, there will be no creation of reducing power i.e. NADPH + H⁺. And the only source of energy is ATP in cyclic photophosphorylation.

7. In PS II, the last electron acceptor is ______
a) Plastocyanin
b) Ferredoxin
c) Cytochrome b₆
d) Cytochrome b₁₂
Answer: a
Clarification: Plastocyanin, which is a Cu protein is the last electron acceptor in PS II. It receives the electrons from cytochrome f and passes onto PS I. This is all based on non-cyclic photophosphorylation reaction.

8. _______ accepts the electrons from Pheophytin.
a) Cytochrome f
b) Cytochrome d
c) Plastoquinone
d) Ferredoxin
Answer: c
Clarification: Plastoquinone (PQ) is an electron carrier. It accepts the electrons from pheophytin. PQ gets 2 electrons and passes these to cytochrome b₆. It also plays a major role in light-dependent reactions.

9. The electrons produced in the photolysis of water enters ______
a) Fe-S protein
b) PS II
c) Plastocyanin
d) Cytochrome a
Answer: b
Clarification: During the photolysis of water, two electrons are produced. These electrons enter into PS II and it transfers the electron to Pheophytin (the primary electron acceptor). These electrons mainly help during reduction reactions.

10. The process by which the pH gradient across the membrane provides energy for the synthesis of ATP is called as ______
a) Phosphorylation
b) Transfusion
c) Diffusion
d) Chemiosmosis
Answer: d
Clarification: There is a pH gradient across the thylakoid membrane, which provides a proton motive force. This creates chemical potential energy for the production of ATP from ADP and inorganic phosphate is called chemiosmosis. Peter Mitchell proposed this theory.

11. In which process does carbon dioxide join photosynthesis?
a) Oxidation
b) PS I
c) Dark reaction
d) Reduction
Answer: c
Clarification: Carbon dioxide is entering the photosynthetic pathway through dark reaction. RuBP reacts with CO₂ to form the first unstable carbon compound. So, here 6 molecules of CO₂ are required to start dark reaction.

Biology Multiple Choice Questions on “Growth Regulators in Plants – 1”.

1. Who isolated the hormone auxin?
a) Darwin
b) Skoog
c) Went
d) Miller
Answer: c
Clarification: F.W. Went isolated hormone auxin. Charles and Francis Darwin had discovered auxin. Skoog and Miller identified and crystallized cytokinesis promoting substance and named it kinetin.

2. Movement of auxin is centripetal.
a) True
b) False
Answer: b
Clarification: Auxin is a hormone which is produced by growing apices of the plant. It is transported to other growing region in both acropetal as well as basipetal succession.

3. The hormone responsible for apical dominance is________
a) IAA
b) ABA
c) GA
d) Kinetin
Answer: a
Clarification: Indole-3-acetic acid (IAA) is the hormone responsible for apical dominance. ABA promotes abscission of older parts. GA delays senescence. Kinetin helps in removing apical dominance and aiding lateral growth.

4. Phototropic and geotropic movements are linked to________
a) ethylene
b) ABA
c) GA
d) Auxin
Answer: d
Clarification: Auxin is associated with different movement of plant stem including phototropic and geotropic movements. GA promotes early maturity of plants. ABA prevents death of plant in stressful conditions. Ethylene increases respiratory rate of plants.

5. The concentration of auxin is highest in _______
a) leaves
b) stem
c) growing tips
d) vascular bundles
Answer: c
Clarification: The concentration of auxin is found to be highest in growing tips as they are the source of the hormone. It further spreads to leaves & stem. Vascular bundles have no role in the activity of PGRs.

6. The hormone which can replace vernalization is _______
a) IAA
b) ABA
c) GA
d) Kinetin
Answer: c
Clarification: Gibberellic acid is the hormone which can be function similar to vernalisation treatment. IAA initiates rooting in stem cuttings. ABA is functional in unfavorable conditions. Kinetin is responsible for formation of new leaves, lateral shoot growth and adventitious shoot formation.

7. Foolish seeding disease of rice led to discovery of Cytokinins.
a) True
b) False
Answer: b
Clarification: Foolish seeding disease of rice was found to be caused by a fungal pathogen Gibberalla fujikori. It was reported in 1926 by Japanese scientist Eiichi Kurosawa after observing symptoms in uninfected seedlings of rice after treatment with sterile filtrates of the fungus which resulted in the discovery of Gibberellic acid (GA₃).

8. Which of the following is a terpene derivative?
a) Ethylene
b) ABA
c) Auxin
d) GA
Answer: d
Clarification: GA is a terpene derivative. Ethylene is a volatile gaseous hormone. ABA is a derivative of carotenoids. Auxin is an indole compound.

9. Which of the following hormone promotes bolting?
a) GA
b) Ethylene
c) Auxin
d) Kinetin
Answer: a
Clarification: Bolting is the elongation of internode just prior to flowering. It is seen in plants with rosette habit. GA promotes the action of bolting. Ethylene helps rapid internode elongation in deep-water seedlings of rice. Auxin promotes rooting in stems. Kinetin promotes shooting in stems.

10. The hormone responsible for speeding up of malting process in brewing industry is ________
a) Auxin
b) GA₃
c) Ethylene
d) Kinetin
Answer: b
Clarification: GA₃ is the hormone responsible for speeding up of malting process in brewing industry. Auxin is useful to prepare weed free lawns. Ethylene is responsible for quick initiation of flowering in fruit plants. Kinetin is naturally present in meristematic regions of the plant.

Biology Multiple Choice Questions on “Transport of Gases”.

1. One haemoglobin carries __________ molecules of oxygen.
a) 6
b) 3
c) 4
d) 2
Answer: c
Clarification: Haemoglobin is made up of 4 units. Each unit has 1 Fe in +2 state. Each haemoglobin molecules can carry a maximum of four molecules of oxygen. 1 gm haemoglobin transports 1.34 ml of oxygen.

2. How the majority of oxygen gets transported?
a) In dissolved form in blood plasma
b) In form of oxyhaemoglobin
c) In form of methaemoglobin
d) In form of carbamino haemoglobin
Answer: b
Clarification: Approximately 3% of oxygen dissolves in the blood plasma. Remaining 97% oxygen combines with haemoglobin to form oxyhaemoglobin. Oxygen can bind with Hb in a reversible mannner to form oxyhaemoglobin.

3. Formation of oxyhaemoglobin is a/an ________
a) oxygenation
b) oxidation
c) reduction
d) deoxygenation
Answer: a
Clarification: Oxygen does not oxidize haemoglobin. Formation of oxyhaemoglobin is a process of oxygenation. The valency of iron is 2 in oxyhaemoglobin. Some gases like ozone oxidise haemoglobin. This oxidized Hb is called methamoglobin.

4. What is the shape of Haemoglobin-oxygen dissociation curve?
a) Straight
b) Constant
c) Hyperbolic
d) Sigmoid
Answer: d
Clarification: A graph is plotted between oxygen concentration and percentage saturation of haemoglobin with this curve is called dissociation curve. Dissociation curve is sigmoid in shape.

5. Every 100 ml deoxygenated blood delivers around _______ carbon dioxide to alveoli.
a) 20 ml
b) 25 ml
c) 5 ml
d) 4 ml
Answer: d
Clarification: Every 100 ml deoxygenated blood delivers around 4 ml carbon dioxide to alveoli, whereas every 100 ml oxygenated blood can deliver around 5 ml of oxygen to tissues under physiological conditions.

6. What is chloride shift?
a) Movement of chloride ion from plasma to WBC
b) Movement of chloride ion from plasma to RBC
c) Movement of chloride ion from WBC to plasma
d) Movement of chloride ion from RBC to plasma
Answer: b
Clarification: In response of bicarbonate ion, chloride ions diffuse from plasma into the erythrocyte to maintain the ionic balance. Thus, electrochemical neutrality is maintained. This is called chloride shift or Hamburger phenomenon.

7. Chloride shift occurs in response to _____
a) H+
b) K+
c) HCO3-
d) Na+
Answer: c
Clarification: Chloride shift occurs in response to HCO3-. In response of bicarbonate ion, chloride ions diffuse from plasma into the erythrocyte to maintain the ionic balance. Thus, electrochemical neutrality is maintained. This is called chloride shift or Hamburger phenomenon.

8. Bulk of carbon dioxide is transported by __________
a) dissolved state
b) plasma as bicarbonate
c) carbamino haemoglobin
d) methamoglobin
Answer: b
Clarification: Nearly 70% carbon dioxide is transported by plasma as sodium bicarbonate. Approximately, 5-7% of carbon dioxide is transported in dissolves form in plasma. About 20-25% carbon dioxide react with the amine group of haemoglobin and form carbamino-haemoglobin.

9. Oxygen dissociation curve will shift to right on decrease of________
a) temperature
b) acidity
c) pH
d) carbon dioxide concentration
Answer: c
Clarification: Shift to the right means that decrease in affinity between oxygen and Hb and dissociation of oxyhaemoglobin. Low oxygen, high carbon dioxide, high hydrogen ion, low pH and high temperature are responsible for this.

10. What percentage of carbon dioxide transport in the form of carbamino haemoglobin?
a) 20-25%
b) 5-7%
c) 3%
d) 97%
Answer: a
Clarification: About 20-25% carbon dioxide react with the amine group of haemoglobin and form carbamino-haemoglobin. Approximately 5-7% of carbon dioxide is transported in dissolves form in plasma.