250+ TOP MCQs on Collision Theory of Chemical Reactions and Answers

Chemistry Quiz for Class 12 on “Collision Theory of Chemical Reactions”.

1. When a catalyst is involved in the collision between the reactant molecules, more energy is required.
a) True
b) False
Answer: b
Clarification: When a catalyst is involved in a collision between the reactant molecules, less energy is required for the chemical reaction to take place. Catalyst brings down the activation energy of the overall chemical reactions and the reaction takes place at a lower energy state.

2. Which of the following explains the increase in the reaction rate by a catalyst?
a) Catalyst decreases the rate of backward reaction so that rate of forward reaction increases
b) Catalyst provides extra energy to reacting molecules so that they produce effective collisions
c) Catalyst provides an alternative path of lower activation energy to the reactants
d) Catalyst increases the number of collisions between the reacting molecules.
Answer: c
Clarification: It is because when the activation energy (Ea) is lower in a reaction, more number of reactant particles have enough energy to react and form products. Hence, it provides an alternative path and the reactions tend to occur faster.

3. Effective collisions are those in which molecules must acquire the energy of activation.
a) True
b) False
Answer: a
Clarification: For the collisions to be effective, molecules must collide with sufficient energy, known as activation energy so that chemical bonds can break. This causes the reaction to occur faster and to form the required products.

4. Who put forward the collision theory of chemical reactions?
a) Trautz and Lewis
b) Luigi Galvani
c) Henry Cavendish
d) Alessandro Volta
Answer: a
Clarification: In 1916, Max Trautz and William Lewis put forward the collision theory giving a better explanation about the rates of reactions. According to this theory, it is assumed that the reactant molecules are hard spheres and reaction between them occurs only when they collide with each other.

5. The proper orientation of reactant molecules leads to bond formation.
a) True
b) False
Answer: a
Clarification: Proper orientation of reactant molecules leads to bond formation because improper orientation makes the reactant molecules bounce back and hence the reaction won’t take place and the required products will not to be formed.

6. Which of the following is a drawback of collision theory?
a) Proper orientation
b) High activation energy
c) Hard spheres
d) Have energy equal to or greater than the threshold energy
Answer: c
Clarification: In Collision theory, activation energy and proper orientation of molecules together determine the criteria for an effective collision but it has a certain drawback as it considers atoms/molecules to be hard spheres and ignores their spherical aspects.

7. What is the term used to refer to the number of collisions per unit volume of the reaction mixture?
a) Collision force
b) Collision frequency
c) Collision energy
d) Collision time period
Answer: b
Clarification: The number of collisions per unit volume of the reaction mixture is known as collision frequency. According to this theory, the reactant molecules are assumed to be hard spheres and reaction is postulated to occur when molecules collide with each other.

8. What is the rate of reaction for a bimolecular elementary reaction?
a) ZAB e-Ea/RT
b) ZAB eEa/RT
c) – ZAB e-Ea/RT
d) – ZAB eEa/RT

Answer: a
Clarification: The rate of reaction is equal to the product of collision frequency of reactants and the fraction of molecules whose energies are equal to or greater than that of the energy of activation. Where ZAB represents collision frequency of reactants, A and B and e-Ea/RT represents a fraction of molecules with energies equal to or greater than E.

9. In a chemical reaction, if the reactant requires a high amount of activation energy, then what is the behaviour of the reaction?
a) Fast
b) Slow
c) Instantaneous
d) Doesn’t depend on activation energy
Answer: b
Clarification: The reaction occurs slowly only if the reactants are slow, so if the reactants are slow we have to provide a high amount of Activation energy (Ea) to the reactants. This enhances the speed of the reactants in the reaction and to form products.

10. What are the factors that determine an effective collision?
a) Translational collision and energy of activation
b) Threshold energy and proper orientation
c) Proper orientation and steric bulk of the molecule
d) Collision frequency, threshold energy and proper orientation
Answer: d
Clarification: The factors that determine an effective collision are:
Collision frequency: The number of collisions per unit volume of the reaction mixture is known as collision frequency.
Threshold energy: Threshold energy is the minimum kinetic energy the molecules must have to bring about effective collisions between two reactant molecules considered as hard spheres, resulting in a chemical reaction. Proper orientation.

Chemistry Quiz for Class 12,

250+ TOP MCQs on P-Block Elements – Dinitrogen and Answers

Chemistry Multiple Choice Questions on “P-Block Elements – Dinitrogen”.

1. Which of the following compounds can be used to obtain free nitrogen?
a) NaNO2
b) HNO2
c) HNO3
d) Ba3N2
Answer: a
Clarification: NaNO2, sodium nitriteis the only convenient compound that can be used to obtain free nitrogen, even in laboratories. Sodium nitrite can be reacted with ammonium chloride, both in aqueous form, producing NaCl and nitrogen, N2 along with water and small traces of HNO3 and NO.

2. How many stable isotopes does the nitrogen atom have?
a) 16
b) 20
c) 2
d) 3
Answer: c
Clarification: The nitrogen atom has two stable isotopes: 14N and 15N, 99.6% and 0.4% (by mass) respectively. There are also fourteen known radioisotopes with one additional nuclear isomer.

3. Nitrogen atom is represented at 147N. How many electrons does it need to attain the noble gas configuration?
a) 1
b) 2
c) 3
d) 4
Answer: c
Clarification: With five electrons in its outer most shell, it needs three more electrons to have a complete shell consisting of eight electrons which is the noble electronic configuration. The ion formed by the nitrogen atom is N3-. It attains the electronic configuration on neon.

4. Why does nitrogen show anomalous properties with respect to other elements in group 15?
a) Nitrogen has low ionization enthalpy
b) Nitrogen atomhas high inter-electronic repulsions
c) Nitrogen molecule bears a triple bond
d) Absence of vacant d-orbitals

Answer: d
Clarification: Nitrogen shows anomalous properties compared to other elements of group 15 because of the absence of vacant d-orbitals. In addition to this, anomalous properties are a result of nitrogen atom’s smaller size, highest electronegativity and highest ionization energy with respect to all the elements in group 15.

5. Why is nitrogen preferably used in welding process and cooling of substances?
a) It’s a gas and can easily be handled
b) It has an extremely low freezing point
c) It is an inert gas
d) It is non-toxic

Answer: c
Clarification: Gases like argon is also nontoxic. However, nitrogen gas is still the most preferred since it eliminates all the possibilities of unwanted oxidation and explosions. In the welding industry this prevents metals from corroding. Nitrogen is used in the food industry for packaging since it provides a pressurized atmosphere that reduces package collapse.

6. Which oxide of nitrogen is released from car engines?
a) Nitrogen dioxide
b) Nitric oxide
c) Nitrous oxide
d) Nitrogen tetroxide
Answer: b
Clarification: Car engines release only nitric oxides. Nitrogen and oxygen from the air combine at high temperatures in the engine to produce nitrogen (II) oxide by the reaction N2(g) + O2(g) → 2NO(g). Nitric oxides rise in the atmosphere and are oxidized to nitrogen dioxide, NO2 which dissolves in the precipitating water to form acid rain.

7. What is the name of the natural process that is responsible for replenishing N2 back in the atmosphere from NO3?
a) Nitrification
b) Nitrogen fixation
c) De-nitrification
d) Nitrate fixation
Answer: c
Clarification: All the mentioned steps are critical in the nitrogen cycle. However, de-nitrification is that particular step where microbes in the soil reduce nitrate ions, NO3, to free nitrogen gas, N2. It also releases few nitrogen oxides as by-products.

8. When liquid nitrogen is poured onto the hand, it slips away without affecting the hand actually. What is this phenomenon called?
a) Kaye effect
b) Kinetic isotope effect
c) Kondo effect
d) Leiden frost effect
Answer: d
Clarification: The Leiden frost effect creates a small layer of insulating vapor layer just at the instant when the liquid particle strikes a surface comparatively a lot hotter than liquid. Liquid nitrogen is at -196°C and the human body at 38°C. This insulating vapor layer prevents the liquid to further come in contact with the body which then slips away.

9. Which group does the name ‘pnictogens’ refer to?
a) Group 11
b) Group 13
c) Group 15
d) Group 14
Answer: c
Clarification: The group 15 of periodic table is better known as the ‘pnicogens’. Pnicogen means ‘to choke’. Since all the elements in this group is choking in nature, including the choking property of nitrogen. Group 11 does not have a specific name; group 13 is referred to as the Boron group. Group 14 is known as the Carbon group.

10. How many allotropes does nitrogen have?
a) Zero
b) One
c) Two
d) Three
View Answer

Answer: a
Clarification: Nitrogen atom does not exhibit allotropy. This is because of its relatively small size and high inter-electronic repulsion due to which the N – N becomes extremely weak. However, theoretically there are two predicted forms of allotropes of nitrogen. First, alpha nitrogen assumes a cubic structure and exists only below 35.6 K which is a whooping -237.55°C. Beta nitrogen exists from 35.6 K to 63.15 K. After that, it melts.

250+ TOP MCQs on P-Block – Group 17 Elements and Answers

Chemistry Multiple Choice Questions on “P-Block – Group 17 Elements”.

1. Group 17 elements are also called halogens.
a) True
b) False
Answer: a
Clarification: Group 17 elements are called halogens. The name halogen (Greek, halo = sea salts, genes = producing) meaning sea salt formers was given to them by Schweigger in 1811 because the salts (chlorides, bromides and iodides) of the first three elements occur in sea water.

2. Which of the following element is most reactive?
a) Chlorine
b) Fluorine
c) Bromine
d) Iodine
Answer: b
Clarification: Of all the halogens, fluorine is the most reactive and hence is also called super halogen. Fluorine is also the most electronegative (EN = 4.0) element in the periodic table. This indicates that fluorine has a high tendency to gain electrons from other elements with lower electronegativities.

3. Which of the following halogen is radioactive?
a) Fluorine
b) Bromine
c) Astatine
d) Chlorine
Answer: c
Clarification: Astatine (Atomic No. = 85, Symbol-At) is radioactive and hence occurs in nature only in traces. Therefore, not much is known about its chemistry, though it might be expected to be a metalloid.

4. Halogens do not occur in the free state.
a) True
b) False
Answer: a
Clarification: Halogens are highly reactive elements and hence do not occur in the free state or native state. They mainly occur in the combined state in the form of their halide (X) salts although iodine also occurs as iodate (IO3).

5. Which of the following is not a mineral of fluorine?
a) Fluorspar
b) Cryolite
c) Fluoroapatite
d) Carnallite
Answer: d
Clarification: Fluorine occurs as insoluble fluorides to the extent of 0.07% in the earth’s crust. The chief minerals of fluorine are:

  • Fluorspar, CaF2
  • Cryolite, Na3AlF6
  • Fluoroapatite, CaF2.3Ca3(PO4)2

6. What is the general electronic configuration of the halogens?
a) ns2np5
b) ns2np2
c) ns2np3
d) ns2np4
Answer: a
Clarification: The elements of group 17 have seven electrons in the valence shell and hence their general electronic configuration is ns2np5, i.e., ns2npx2npy2npz1 where n = 2-6. Thus, they contain one electron less than the nearest inert gas configuration.

7. What is the correct order of enthalpy of dissociation of halogens?
a) F2 > Cl2 > Br2 > I2
b) Cl2 > Br2 > F2 > I2
c) Cl2 > F2 > Br2 > I2
d) F2 > Br2 > Cl2 > I2
Answer: b
Clarification: Enthalpy of dissociation decreases as the bond distance increases from F2 to I2 due to a corresponding increase in the size of the atom as we move down the group from F to I. The F-F bond dissociation enthalpy is, however, smaller than that of Cl-Cl and even smaller than that of Br-Br. This is due to the reason that F atom is very small and hence the electron-electron repulsions between the lone pairs of electrons are very large.

8. What is the atomicity of halogens?
a) Monoatomic
b) Diatomic
c) Triatomic
d) Octatomic
Answer: b
Clarification: Each halogen has one electron less than the nearest inert gas. As a result, halogens are very reactive elements. They readily share their single unpaired electron with other atoms to form covalent bonds. Thus, all halogens exist as diatomic molecules.

9. Who discovered the element chlorine?
a) Joseph Priestley
b) Antoine Lavoisier
c) Humphry Davy
d) Wilhelm Scheele
Answer: d
Clarification: Chlorine was discovered in 1774 by Carl Wilhelm Scheele by heating HCl with MnO2. In 1810, Davy established its elementary nature and suggested the name chlorine on the basis of its colour (Greek, chloros = greenish yellow).

10. Which of the following halogen exists as a solid at room temperature?
a) Chlorine
b) Fluorine
c) Iodine
d) Bromine
Answer: b
Clarification: The strength of the van der Waals between molecules forces increases as the size of the halogen increases from fluorine to iodine. As a result, F2 and Cl2 are gases at room temperature, Br2 is a liquid whereas I2 is a solid.

250+ TOP MCQs on Nomenclature of Coordination Compounds and Answers

Chemistry Multiple Choice Questions on “Nomenclature of Coordination Compounds – 1”.

1. The position of ligands in the formula of a mononuclear coordination entity depends on which of the following?
a) The first letter in the name of the ligand
b) Charge on the ligand
c) Atomicity of the ligand
d) Denticity of the ligand
Answer: a
Clarification: The listing of ligands in the formula of mononuclear coordination entities is according to alphabetical order, including abbreviated ligands. It does not depend on the atomicity, denticity or the charge on the ligand.

2. Which of the following is the correct formulation of the entity according to IUPAC?
a) (Co(CN)6)3-
b) [Co(CN)6]3-
c) [Co (CN)6]3-
d) [Co(CN)6]-3
Answer: b
Clarification: The formula of the coordination entity should be enclosed within square brackets and there should be no space between the ligand and central metal. The number is written before the sign while indication the charge of the complex ion.

3. Which of the following ligands will be listed last in a coordination sphere?
a) Cl
b) CO
c) CO3
d) C2O4
Answer: d
Clarification: The ligands given are chlorine (Cl), carbonyl (CO), carbonate (CO3) and oxalate (C2O4). Of these, the one that occurs last in alphabetic order is oxalate, and hence is will be listed at the end of the coordination entity.

4. Which of the following is true regarding a charged coordination entity?
a) The charge is indicated as a subscript outside the square bracket on the right
b) The charge of the complex ion is written in parenthesis while naming the entity
c) The sign of the charge is written after the number
d) The charge on the complex ion is depicted along with the counter ion

Answer: c
Clarification: The charge of a coordination entity is written without the presence of the counter ion and is indicated outside the square brackets on the right side as a superscript with the number before the sign of charge.

5. Which of the following terms is used to indicate the number of individual ligands that do not include a numerical prefix, in the name of a coordination compound?
a) tetra
b) bis
c) tris
d) tetrakis
Answer: a
Clarification: The terms bis, tris, tetrakis are used when the names of the ligand include a numerical prefix. Else, the prefixes used are mono, di, tri, tetra, etc.

6. The correct way of naming Co in [CoCl2(en)2]+ is ________
a) cobalt(III)
b) cobalt(II)
c) cobaltate(III)
d) cobaltate(II)
Answer: a
Clarification: The complex ion given is cationic and hence the metal is named same as the element. Also, the oxidation number of cobalt is +3 as (en) is a neutral ligand and Cl has -1 charge. Thus, the correct naming for Co is cobalt(III).

7. The prefix di is used twice in the naming of [NiCl2(PPh3)2].
a) True
b) False
Answer: b
Clarification: The prefix di is used only once for chlorido. For the PPh3 ligand, the prefix bis is used instead, as PPh3 (triphenylphosphine) already includes a numerical prefix in its name.

8. What would be the formula of the hypothetical compound shown in the figure? (Assume all ligands are monoatomic)
chemistry-questions-answers-nomenclature-coordination-compounds-1-q8
a) [M(AB)2C]+
b) [M(A2B2C)]+
c) [MA2B2C]+
d) [M(A)2(B)2C]+
Answer: c
Clarification: A, B and C are distinct monoatomic ligands are simply listed in that order after the metal M, without the use of any parenthesis, and enclosed within square brackets.

9. If the complex ion is cationic, the name of the metal ends with suffix -ate.
a) True
b) False
Answer: b
Clarification: In cationic complex ions, the metal is named same as element. On the other hand, in anionic complex ions, the name of the metal is ended with -ate.

10. Identify the correct naming for K2[PdCl4].
a) Potassium tetrachlorinepalladium(II)
b) Potassium tetrachlorinepalladate(II)
c) Potassium tetrachloridopalladium(II)
d) Potassium tetrachloridopalladate(II)
Answer: d
Clarification: Since Cl is an anionic ligand, it ends in -o, hence chlorido. Also, the complex ion is anionic, and the metal must end with the suffix -ate, hence palladate.

250+ TOP MCQs on Haloalkanes & Haloarenes – Chemical Reactions and Answers

Chemistry Question Bank for Class 12 on “Haloalkanes & Haloarenes – Chemical Reactions – 2”.

1. As the stability of carbocation formed in the first step of SN1 reaction increases, the rate of the reaction _________
a) increases
b) decreases
c) remains same
d) may increase or decrease
Answer: a
Clarification: Greater the stability of the carbocation, greater will be the ease of formation from alkyl halide and faster will be the reaction rate.

2. The SN1 reaction cannot be carried out in which of the following media?
a) Acetic acid
b) Acetone
c) Ethanol
d) Water
Answer: b
Clarification: SN1 reactions are carried out in polar protic solvents like water, alcohol and acetic acid. These solvents promote the ionisation step by stabilising the ions by solvation.

3. If a compound does not affect the plane of plane polarised light when passed through it, the compound is said to be _________
a) optically active
b) optically inactive
c) dextrorotatory
d) laevorotatory
Answer: b
Clarification: When the plane of plane polarised light is rotated either to the left or right when passed through a compound, it is said to be optically active. Else, it is optically inactive.

4. Which of the following compounds does not have a stereocenter?
a) Propan-2-ol
b) Butan-2-ol
c) 2-Bromo-1-chlorobutane
d) 2-Bromopentane
Answer: a
Clarification: A stereocenter is an asymmetric carbon that has four different groups attached to it. Propan-2-ol has two methyl groups attached to the carbon.

5. Which of the following has a chiral carbon atom?
a) 2-Chloro-2-methylpentane
b) 1,1-Dibromoethane
c) Pentan-3-ol
d) 2-Bromopentane
Answer: d
Clarification: A chiral carbon atom is that which has four different substituent groups attached to it. 2-Bromopentane has one of each H, CH3, C3H7 and Br groups attached to its C atom.

6. What is the chirality of 2-Chlorobutane?
a) Chiral
b) Achiral
c) Superimposable mirror images
d) Symmetric
Answer: a
Clarification: 2-Chlorobutane has four different groups attached to the tetrahedral carbon and is chiral as it forms non-superimposable mirror images.

7. Predict the chirality of the shown compounds.
chemistry-questions-answers-chemical-reactions-2-q7
a) Both A and B are chiral
b) Both A and B are achiral
c) A is chiral and B is achiral
d) A is achiral and B is chiral
Answer: c
Clarification: The C atom that is attached to the OH group in compound A is a stereocenter and makes the compound A chiral. On the other hand, compound B does not have any asymmetric carbon.

8. A chiral compound with an ‘X’ group attached to the stereocenter has been replaced by a ‘Y’ group. The product obtained rotates the plane of polarised light in the direction opposite to that of the original compound. Name the process that has taken place.
a) Inversion
b) Retention
c) Racemisation
d) Inversion or retention
Answer: d
Clarification: Since the product rotates the plane of polarised light in some direction, it cannot be racemic. The product formed is a completely new compound from the original one and may have different or same optical behaviour as compared to the original compound.

9. The process of separation of a racemic mixture into the respective d and l optical isomers is called __________
a) racemisation
b) resolution
c) inversion
d) retention
Answer: b
Clarification: Racemisation is the process of converting optical isomers into a racemic mixture and separating them from the mixture is known as resolution.

10. What is the most suitable term for the following transformation?
chemistry-questions-answers-chemical-reactions-2-q10
a) Inversion of configuration
b) Retention of configuration
c) Racemisation
d) Elimination reaction
Answer: b
Clarification: It can be seen that the relative spatial arrangement of bonds at the stereocenter remain the same even after the transformation. Hence, this transformation is said to take place with a retention of configuration.

11. When a reaction proceeds with the retention of configuration, the optical activity of the product will remain same as that of the original reactant.
a) True
b) False
Answer: b
Clarification: For example, when (-)-2-methylbutan-1-ol is heated with conc. HCl, the product formed is (+)-1-chloro-2-methylbutane, which has opposite optical behaviour to that of the reactant.

12. What will be the effect on the plane of plane polarised light when it passes through a solution of dlbutan-2-ol?
a) Clockwise rotation
b) Anti-clockwise rotation
c) Zero rotation
d) 180° rotation
Answer: c
Clarification: dlbutan-2-ol represents a mixture of dbutan-2-ol (dextro) and lbutan-2-ol (laevo), and is called a racemic mixture. There optical rotation due to one isomer will cancel the rotation due to the other and will have no effect on the polarised light passed through it.

13. When (-)-2-bromooctane reacts with potassium hydroxide over an SN2 mechanism, what will be the product formed?
a) (-)-octan-1-ol
b) (+)-octan-1-ol
c) (-)-octan-2-ol
d) (+)-octan-2-ol
Answer: d
Clarification: The OH nucleophile attaches itself opposite to where the halide was present but one the same carbon. This results in an inversion of configuration and hence changes in the direction in which the plane of polarised light rotates.

14. The heating of 1-Chlorobutane along with alcoholic KOH results in ________
a) elimination of hydrogen from α-carbon atom
b) elimination of hydrogen from β-carbon atom
c) elimination of hydrogen from γ-carbon atom
d) no reaction
Answer: b
Clarification: When a haloalkane with a β-hydrogen atom is heated with alc. KOH, it results in a β-elimination reaction to form alkenes.

15. The major product formed from the dehydrohalogenation of 2-Bromopentane is pent-2-ene.
a) True
b) False
Answer: a
Clarification: According to Zaitsev’s rule, the major product will be that alkene which has more number of alkyl groups attached to the double bonded carbon atoms.

Chemistry Question Bank for Class 12,

250+ TOP MCQs on Aldehydes and Ketones Physical Properties and Answers

Chemistry Multiple Choice Questions on “Aldehydes and Ketones Physical Properties”.

1. Which of the following exists as a gas at 287K?
a) Formaldehyde
b) Acetaldehyde
c) Propanal
d) Acetone
Answer: a
Clarification: Methanal exists as foul-smelling gas at room temperature. Ethanal is a volatile liquid which boils at 294K. Other aldehydes and ketones exist as either liquids or solids at room temperature.

2. If the boiling points of methoxyethane and propanol are 281 K and 370 K respectively, predict the boiling point of propanal.
a) 273 K
b) 281 K
c) 322 K
d) 370 K
Answer: c
Clarification: The boiling point of aldehydes are higher than those of non-polar hydrocarbons of comparable molecular masses. However, their boiling points are lower than comparable alcohols, due to the absence of intermolecular hydrogen bonding.

3. Which of the following is the least soluble in water?
a) Methanal
b) Ethanal
c) Propanone
d) Pentanal
View Answer

Answer: d
Clarification: The lower aldehydes and ketones are miscible in water in all proportions due to the ability of the polar carbonyl group to form hydrogen bonds with water molecules. However, the solubility rapidly decreases as the length of the alkyl chain increases. Precisely, aldehydes and ketones with more than 4 carbon atoms are practically insoluble in water.

4. Propanal has a slightly higher boiling point than propanone.
a) True
b) False
Answer: b
Clarification: Propanone has two CH3 groups, one on either side of the CO group, whereas propanal has only one CH3CH2 group. This makes propanone more polar because of the higher electron releasing effect of two alkyl groups. The boiling point of propanal is 322K and that of propanone is 329K.

5. Two compounds A and B were being tested for their boiling points. It was observed that A started boiling after B, when both were subjected to same conditions. If the compound B is acetone, which of the following can be compound A?
a) n-Butane
b) Methoxyethane
c) Propanal
d) Propanol
Answer: d
Clarification: It can be inferred that B has a higher boiling point than A. Since hydrocarbons, ethers and aldehydes have lower boiling points than ketones of similar molecular masses, none of them can be compound A. Also, alcohols have a higher boiling point than similar ketones hence, the compound A is propanol.

6. Which of the following has the least pungent odour?
a) Methanal
b) Ethanal
c) Propanal
d) Butanal
Answer: d
Clarification: As the size of the aldehyde molecule increases, the odour becomes less pungent and more fragrant. Methanal is the most pungent smelling aldehyde.

7. Which of the following is used as a flavouring agent?
a) Methanal
b) Ethanal
c) Acetone
d) Acetophenone
Answer: d
Clarification: Methanal, ethanal and acetone are lower carbonyl compounds and are not much fragrant to be used as flavouring agents.

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