250+ TOP MCQs on Raman Effect and Answers Spectroscopy

Engineering Physics Multiple Choice Questions on “Raman Effect”. | Raman Spectroscopy

1. Raman effect is scattering of ________
a) Atoms
b) Molecules
c) Protons
d) Photons

Answer: d
Clarification: The inelastic scattering of a photon by a molecule that is raised to higher energy levels is called the Raman effect. It was discovered by C.V. Raman.

2. The elastic scattering of photons is called as ______
a) Atmospheric scattering
b) Rayleigh Scattering
c) Conserved Scattering
d) Raman Scattering

Answer: b
Clarification: The elastic scattering by a material is called the Rayleigh Scattering. The inelastically scattered photons are called as Raman scattered photons.

3. Which of the following cannot be conserved during Raman scattering?
a) Total Energy
b) Momentum
c) Kinetic Energy
d) Electronic Energy

Answer: c
Clarification: The Raman scattering is the inelastic scattering of a photon by a molecule. In inelastic scattering, the Kinetic energy is not conserved.

4. How many degrees of freedom does a chemical compound of N atoms have?
a) 2N
b) 2N + 1
c) 3N
d) 3N + 1

Answer: c
Clarification: For any given chemical compound, there are a total of 3N degrees of freedom, where N is the number of atoms in the compound.

5. In Raman spectroscopy, the radiation lies in the ________
a) Microwave Region
b) Visible Region
c) UV Region
d) X-ray Region

Answer: b
Clarification: The radiations used in the Raman spectroscopy lie in the visible region or the low infrared region. They are high intensity beams. He-Ne laser is used in Raman spectroscopy for the production of high intensity light.

6. The change in frequency is due to the transition between vibrational or rotational energy levels.
a) True
b) False

Answer: a
Clarification: In Raman effect, 99 % of the light has the same frequency while less than 1% of the light’s frequency is changed due to the transition between vibrational or rotational energy levels.

7. The Raman spectrum is said to consist of Strokes lines when ________
a) Δv > 0
b) Δv < 0
c) Δv = 0
d) Does not depend on Δv

Answer: a
Clarification: We know, Δv = vi – vs. Thus, when Δv > 0, the Raman effect is said to consist of Strokes lines and when it is negative Raman effect is said to consist of anti-strokes lines.

8. The Rama shift generally lies between ________
a) 100 – 1000 cm-1
b) 100 – 2000 cm-1
c) 100 – 3000 cm-1
d) 100 – 4000 cm-1

Answer: d
Clarification: The Rama effect generally lies between the range 100 – 4000 cm-1, which falls in far and near infrared regions of the spectrum.

9. Raman lines are ________
a) Weak
b) Strong
c) Curved
d) Blurry

Answer: a
Clarification: The lines observed in the Raman effect are generally weak. Thus, long exposures are required with conventional light source.

10. In Raman spectroscopy, the radiation lies in the——-
a) microwave region
b) visible region
c) UV region
d) x-ray region

Answer: b

11. The most commonly used laser for Raman spectroscopy is ___________
a) ND: YAG
b) Ruby laser
c) He-Ne laser
d) Semiconductor Laser

Answer: c
Clarification: The most commonly used laser in Raman spectroscopy is He-Ne laser (632.8 nm). Lasers are used as they possess the advantages of providing high intensity of light collimated in a particular direction.

12. Which of the following lines are most intense?
a) Stokes lines
b) Rayleigh-scattered lines
c) Anti-strokes lines
d) All have same intensity

Answer: b
Clarification: The Rayleigh-scattered radiations are considerably more intense than either of the other two types – Strokes lines and Anti-Strokes lines.

13. For a particular vibrational mode to appear in the Raman spectrum, what must change?
a) Frequency of radiation
b) Intensity of radiation
c) Molecule’s shape
d) Molecule’s polarizability

Answer: d
Clarification: For a particular vibrational mode to appear in the Raman spectrum, the molecule’s polarizability must change during the course of the vibration.

14. Infrared and Raman spectra are complementary to each other.
a) True
b) False

Answer: a
Clarification: The given statement is true because of their different selection rules for activity. A change in polarizability must occur for a vibration to be Raman-active, but for a vibration o be Infrared-active, there should be a change in dipole moment.

15. The Raman shift, related to force constant k and reduced mass μ, is given by ________
a) (frac{1}{2π}sqrt{frac{k}{μ}})
b) (frac{1}{2πc}sqrt{frac{k}{μ}})
c) (frac{1}{2π}sqrt{frac{μ}{k}})
d) (frac{1}{2πc}sqrt{frac{μ}{k}})

Answer: b
Clarification: The correct expression for the Raman shift is: (frac{1}{2πc}sqrt{frac{k}{μ}}). It is same as the expression for the shift in Infrared Spectroscopy. Thus, they are complementary to each other.

250+ TOP MCQs on Fresnel Diffraction and Answers

Engineering Physics Multiple Choice Questions on ” Fresnel Diffraction”.

1. How many lenses are used in Fresnel Diffraction?
a) Two Convex lenses
b) Two Concave lenses
c) One Convex lens
d) No lens used
Answer: d
Clarification: In Fresnel Diffraction, no lenses are used. The interference takes place between different light waves arriving at a point from the same wavefront. In this case, the phase of all the waves is not the same.

2. Which of the following is called the obliquity factor?
a) cosθ
b) sinθ
c) 1 + cosθ
d) 1 + sinθ
Answer: c
Clarification: The effect at a point fie to any particular zone is proportional to 1 + cosθ, called the obliquity factor. Naturally, the effect is maximum whenθ` = 0.677.

3. In Fresnel diffraction, the relative phase difference between the curved wavefront is ____________
a) Constant
b) Zero
c) Linearly increasing
d) Non=constant
Answer: d
Clarification: Since the radii of each half period zone are different, the distance traveled by each wavefront is different. Thus, the relative phase difference turns out to be non-constant.

4. What is the variation in the pattern observed for single slit Fresnel diffraction than single slit Fraunhofer Diffraction?
a) The pattern is not hyperbolic
b) The fringes are too thin
c) The region of minimum intensity is not completely dark
d) The fringes are colored
Answer: c
Clarification: The diffraction pattern due to the single slit Fresnel Diffraction is similar to single slit Fraunhofer Diffraction, except the regions of minimum intensity are not completely dark. This is so because there is never a complete destructive interference in Fresnel Diffraction.

5. The radius of the half period zone is proportional to ___________
a) The wavelength of light
b) The square root of the frequency of light
c) The square root of the wavelength light
d) The frequency of light
Answer: c
Clarification: We know that the formula for the radius of half period zone =(sqrt{nblambda}), where n is a natural number. Thus, it is proportional to the square root of wavelength light and inversely proportional to the square root of the frequency of light.

6. Intensity at O due to the entire wavefront is x times that due to the first half period zone. What is x?
a) 4
b) 2
c) 1/2
d) 1/4
Answer: d
Clarification: The formula for intensity = (frac{m_1^2}{4})
The intensity due to the first half period zone = m12
Thus, the intensity at O due to the entire wavefront is 1/4 times that due to the first half period zone.

7. Light of 5000 Å is incident on a circular hole of radius 1 cm. How many half period zones are contained in the circle if the screen is placed at a distance of 1 m?
a) 20
b) 200
c) 2000
d) 20000
Answer: d
Clarification: In this case, λ = 5000 Å = 5 X 10-5cm, b = 1m = 100cm
Therefore, Number of half period zones = (frac{1}{λ})
= 1/5 X 10-5
= 20000.

8. Light of 6000 Å is incident on a circular hole and is received on a screen 50 cm away. What is the radius of the hole, if the intensity of light on the screen is 4 times the intensity without the hole?
a) 0.025 cm
b) 0.047 cm
c) 0.054 cm
d) 0.089 cm
Answer: c
Clarification: The intensity will be 4 times than in its absence if the radius of the hole is equal to that of the first half period zone.
Therefore, radius, r = (sqrt{blambda})
Here, b = 50 cm and λ = 6000 Å = 6 X 10-5cm
r = 0.0548 cm.

9. The zone plate behaves like a ____________
a) Concave Lens with multiple foci
b) Convex Lens with multiple foci
c) Convex Lens with single foci
d) Concave Lens with single foci
Answer: b
Clarification: In a zone plate, a much brighter image of an object is obtained at the screen, which shows the converging action of a zone plate. Also, it’s equation resembles that of a lens. Thus, the zone plate behaves like a convex lens with multiple foci.

10. The radius of the first zone in a zone plate of focal length 25cm for a light of wavelength 5000 Å is ____
a) 0.01 cm
b) 0.02 cm
c) 0.03 cm
d) 0.04 cm
Answer: c
Clarification: Here, f1 = 25cm, λ=5000 Å = 5 X 10-5 cm.
Now using the formula, (f=frac{r^2}{nλ})
r1 = (sqrt{fλ})
= 0.03 cm.

11. Which graph is shown in the figure?
engineering-physics-questions-answers-fresnel-diffraction-q11
a) Amplitude variation with the number of exposed zones
b) Intensity variation with the number of exposed zones
c) Frequency variation with the number of exposed zones
d) Phase variation with the number of exposed zones
Answer: b
Clarification: The figure shows the variation of intensity with the number of exposed zones. We know, the resultant intensity at O is (frac{m_1^2}{4}). Only the first half period zone is effective in producing the illumination at O.

12. During a straight-edge diffraction experiment, a light of wavelength 400 nm was used. What would be the position of the first minimum, if the separation between the edge and the source is 10 cm while that between the edge and eyepiece is 2 m?
a) 1.01 cm
b) 2.03 cm
c) 0.57 cm
d) 1.56 cm
Answer: c
Clarification: λ = 4000 Å = 4 X 10-5cm, a = 10 cm and b = 200 cm
Location for first maximum, x1 = (sqrt{frac{2b(a+b)lambda}{a}})
= (sqrt{0.336})cm
= 0.57 cm.

250+ TOP MCQs on Retardation Plates and Answers

Engineering Physics Multiple Choice Questions on “Retardation Plates”.

1. A plate which induces the desired amount of phase difference between two rays is known as ____________
a) Polaroid
b) Phasor plates
c) Retardation Plates
d) Quartz plates
Answer: c
Clarification: Sometimes, it is required to induce a certain phase difference between E-ray and O-ray. For that, a plate with a specific thickness is chosen to induce that phase difference. This plate is known as the retardation plate as it retards the motion of one of the rays.

2. A quarter wave plate induces a phase shift of ___________
a) π/6
b) π/2
c) π/4
d) π/3
Answer: b
Clarification: A quarter wave plate is a uniaxial, doubly refracting crystal plate. It induces a phase difference of π/2 between the O-ray and the E-ray.

3. Which phenomenon is used for inducing the phase shift in the retardation plates?
a) Reflection
b) Polaroid filters
c) Double Refraction
d) Polarimeter
Answer: c
Clarification: The retardation plated uses double refraction for inducing the phase shift. They induce a phase shift between the O-ray and the E-ray.

4. If a ray is incident at 45° on a quarter-wave plate, the emergent light is ___________
a) Unpolarized
b) Linearly Polarized
c) Elliptically Polarized
d) Circularly Polarized
Answer: d
Clarification: If the light is incident at an angle of 45° on the quarter-wave plate, then the emergent light would be circularly polarized. If the angle is not 45°, then it would be elliptically polarized.

5. A Half-wave plate induces a phase difference of ____________
a) π
b) π/4
c) π/2
d) π/3
Answer: a
Clarification: A half wave plate is a uniaxial doubly refracting crystal that induces a phase difference of π or a path difference of λ/2 between the E-ray and the O-ray.

6. What should be the minimum thickness of a half-wave plate made of calcite for the light of wavelength 5500 Å? The principal refractive indices are 1.652 and 1.488.
a) 1.234 μm
b) 1.676 μm
c) 1.956 μm
d) 2.165 μm
Answer: c
Clarification: As we know, t = (frac{lambda}{2(mu_E-mu_0)})
Here, μe = 1.652 and μ0 = 1.488, λ = 5500 X 10-8 cm
Therefore, t = 5500/2 X 0.164 X 10-8 cm
= 1.676 μm.

7. If the thickness of a plate is 0.0032 cm, what shall be the phase retardation for a light of wavelength 5000 Å, given the principal refractive indices are 1.55 and 1.54?
a) 1.05π radians
b) 1.15π radians
c) 1.25π radians
d) 1.35π radians
Answer: b
Clarification: Here, t = 0.0032 cm, μe = 1.55, μ0 = 1.54 and λ = 5000 X 10-8 cm
Phase retardation = (frac{2}{pilambda})(μe – μ0)t
= 2π X 0.009 X 0.0032/5000 X 10-8
= 1.15π radians.

8.What should be the thickness of quarter-wave plate for a light of wavelength 5890 Å if μe = 1.553 and μ0 = 1.544?
a) 1.33 X 10-3 cm
b) 1.43 X 10-3 cm
c) 1.53 X 10-3 cm
d) 1.63 X 10-3 cm
Answer: d
Clarification: t = (frac{lambda}{2(mu_E-mu_0)})
λ = 5890 Å = 5890 X 10-8 cm, μe = 1.553 and μ0 = 1.544
Therefore, t = 5890a X 10-8/4 X 0.009
= 1.63 X 10-3 cm.

9. For what wavelength would a half wave plate behave as a half wave plate?
a) 2λ
b) λ/2
c) 3λ
d) Never
Answer: a
Clarification: For a half-wave plate, t = (frac{lambda}{2(mu_E-mu_0)})
Multiplying numerator and denominator with 2 we get, t = (frac{2lambda}{4(mu_E-mu_0)})
As we can see, this resembles the expression for thickness of a quarter-wave plate, t = (frac{2lambda}{4(mu_E-mu_0)}). Thus, for λ’ = 2 λ, a half wave plate would behave as a quarter-wave plate.

10. How is the emergent beam polarized?
engineering-physics-questions--answers-retardation-plates-q10
a) Linearly polarized
b) Circularly polarized
c) Elliptically polarized
d) Unpolarized
Answer: b
Clarification: As we can see, a quarter wave plate is used in the given figure. The emergent beam is circularly polarized, as is clearly visible from the figure.

250+ TOP MCQs on Applications of X-Rays and Answers

Engineering Physics Multiple Choice Questions on “Applications of X-Rays”.

1. Photographs made with X rays are known as ___________
a) X-graphs
b) Gamma-graphs
c) Radiographs
d) Scanned Photos
Answer: c
Clarification: Radiographs are the photographs that are made with the help of X-ray. It is widely used in the medical field. It can be used for diagnosis and non-destructive testing of products to identify defects in it.

2. X-rays are used with computer in __________
a) CT Scan
b) CAT Scan
c) CA Scan
d) AT Scan
Answer: b
Clarification: X-rays are used with computers for CAT Scan. They are used to produce cross-sectional images of the inside of the body.

3. Radiography can be used to identify the age of a painting.
a) True
b) False
Answer: a
Clarification: Radiography can be used to identify the age of the painting or the brushing technique used in the painting. It can be used to verify the artist of the painting.

4. Which of the following disease can be detected by X-Ray?
a) Bladder infection
b) Pneumonia
c) Diarrhea
d) Fever
Answer: b
Clarification: After taking a chest x-ray test, pneumonia can be diagnosed. If there are white spots on the lungs, it means that the person has pneumonia.

5. The therapy used to fight cancer cells is called __________
a) Cancer therapy
b) X-ray therapy
c) Brachytherapy
d) Diagnosis therapy
Answer: c
Clarification: When x-ray radiations are used to destroy the cancer cells, it is called as radiation therapy or brachytherapy. It can be dangerous.

6. The checking of bags in Airport is done via X-ray.
a) True
b) False
Answer: a
Clarification: Since, X-ray has high penetrating power, it is widely used in airport security to check the items/belongings of a person. Full body x-ray scans are also widely used.

7. The food industry uses X-ray for __________
a) Checking Purity of food
b) Sterilizing food
c) Break it into smaller pieces
d) Does not uses
Answer: b
Clarification: X-ray and Gamma rays both are used in food industries for sterilizing the food. It is a good health safety measure and has minimum side effects.

8. In photo-chemical process, the rays which provide better resolution are __________
a) Infrared
b) Visible Light
c) UV light
d) X-rays
Answer: d
Clarification: Since X-ray have much shorter wavelength comparing to the visible light, they are considered a promising option to provide better resolution in photo-chemical processes such as semiconductor etching etc.

9. The process of using X-rays for identifying atomic structure is called _________
a) X-ray Radiography
b) X-ray Crystallography
c) X-ray Diagnosis
d) X-ray Structure Identification
Answer: b
Clarification: X-ray crystallography is used to identify the molecular and atomic structure of the crystal. The crystal diffracts the incident X-ray beam. By measuring the intensities and angle of these diffracted beams, the molecular structure of the crystal can be evaluated.

10. Which phenomenon is shown by the given figure?
engineering-physics-questions-answers-applications-x-rays-q10
a) X-ray scan
b) C.T. scan
c) X-ray crystallography
d) X-ray production
Answer: c
Clarification: The given figure shows the procedure of X-ray scan. X-ray scan can be used to identify any fracture in bones, tumor, cancerous tissues and many more diseases.

250+ TOP MCQs on Characteristics of P-N Junction and Answers

Engineering Physics Multiple Choice Questions on “Characteristics of P-N Junction”.

1. In a P-N Junction, the depletion region is reduced when _________
a) P side is connected to the negative side of the terminal
b) P side is connected to the positive side of the terminal
c) N side is connected to the positive side of the terminal
d) Never reduced
Answer: b
Clarification: When the P-side of a P-N junction is connected to the positive terminal of a battery, the junction is forward biased and hence the depletion region reduces.

2. The voltage at which forward bias current increases rapidly is called as ___________
a) Breakdown Voltage
b) Forward Voltage
c) Knee Voltage
d) Voltage barrier
Answer: c
Clarification: Till the knee voltage, the current in a semiconductor increases slowly. After Knee voltage, the current increases rapidly for a small change in the voltage.

3. The Knee Voltage for germanium is _________
a) 0.1 V
b) 0.3 V
c) 0.7 V
d) 1.4 V
Answer: b
Clarification: Knee voltage or the threshold voltage is the point after which the current increases rapidly. For germanium, it is about 0.3 V while for silicon it is 0.7 V.

4. The resistance of the semiconductor decreases in forward biased.
a) True
b) False
Answer: a
Clarification: When a P-N Junction diode is forward biased, the thickness of the depletion region becomes negligibly small. Thus, the resistance of the semiconductor decreases.

5. The current produced in reverse-bias is called as __________
a) Reverse Current
b) Breakdown Current
c) Negative Current
d) Leakage Current
Answer: d
Clarification: When the diode is reverse biased, the reverse bias voltage produces an extremely small current, about a few micro amperes. This is called leakage current.

6. Which diode is designed to work under breakdown region?
a) Photodiode
b) Light Emitting Diode
c) Solar Cell
d) Zener diode
Answer: d
Clarification: Zener Diode is designed specifically to operate in the breakdown region. It is mostly used as a voltage regulator in various circuits.

7. The P-N junction is a non-ohmic device.
a) True
b) False
Answer: a
Clarification: The current-voltage curve of a P-N junction diode is not a straight line. Thus, it does not obey Ohm’s law and is a non-ohmic device.

8. The I-V characteristics of a p-n junction diode is shown. What is the resistance of the junction when a forward bias of 2 V is applied?
engineering-physics-questions-answers-characteristics-p-n-junction-q8
a) 20 Ω
b) 40 Ω
c) 60 Ω
d) 80 Ω
Answer: b
Clarification: The current at 2 V is 5 mA and at 2.2 V it is 10 mA.
The dynamic resistance is: Δ V/Δ I
= 0.5/5 X 103 Ω
= 40 Ω.

9. The leakage current is measured in ________
a) A
b) mA
c) μA
d) nA
Answer: c
Clarification: As in the reverse current, the resistance increases, the current produced is extremely low. And hence, it is measured in microamperes.

10. From the I-V characteristics, calculate the resistance of the diode at I = 15 mA.
engineering-physics-questions-answers-characteristics-p-n-junction-q10
a) 10 Ω
b) 12 Ω
c) 14 Ω
d) 15 Ω
Answer: a
Clarification: From the curve, I = 20 mA, V = 0.8 V, I = 10 mA when V = 0.7 V
Now, R = Δ V/Δ I
= 0.1 V/10 mA
= 10 Ω.

250+ TOP MCQs on Fabrication of Nanomaterials and Answers

Engineering Physics Multiple Choice Questions on “Fabrication of Nanomaterials”.

1. What’s the procedure in Top-down fabrication method?
a) Nano-particles -> Powder -> Bulk
b) Powder -> Bulk – > Nano-particles
c) Bulk -> Powder – > Nano-particles
d) Nano-particle – > Bulk -> Powder
Answer: c
Clarification: Top-down approach is the one in which a material of regular size is converted into a nano-particle. In the bottom-up approach, the atoms are joined to form nano-particles.

2. Which of the following is an example of Bottom Up approach?
a) Attrition
b) Colloidal dispersion
c) Milling
d) Etching
Answer: b
Clarification: Colloidal dispersion is an example of bottom up approach in the synthesis of Nano particles. Attrition, milling and etching are typical top down methods.

3. For milling operations, what kind of environment is preferred?
a) Acidic
b) Basic
c) Active
d) Inert
Answer: d
Clarification: Milling is the process of particle size reduction with the objective of mixing or blending and change of particle size. An inert environment is preferred for this process.

4. What kind of metals are used for milling operations?
a) Soft and brittle
b) Soft and elastic
c) Hard and brittle
d) Hard and elastic
Answer: c
Clarification: For the milling operation, normally hard brittle materials with fracture, deform and cold weld are used. The reason for choosing dense materials is the fact that the kinetic energy of balls depends upon their mass and velocity.

5. The following flow chart is for which method?
engineering-physics-questions-answers-fabrication-nanomaterials-q5
a) Milling
b) Attrition
c) Pattering
d) Microfabrication
Answer: d
Clarification: The given process is the process of microfabrication. The water is prepared and then photoresist is applied. The product is exposed to the UV light which after a series of processes, results in the fabrication of nanomaterials.

6. CVD stands for ____________
a) Carbon vapour density
b) Chemical vapour density
c) Chemical vapour deposition
d) Carbon vapour deposition
Answer: c
Clarification: Chemical vapour deposition, or CVD, is a chemical process used to produce high-purity, high-performance solid materials. The process is often used to produce carbon nanotubes.

7. Photolithography is a type of patterning technique.
a) True
b) False
Answer: a
Clarification: Photolithography has been the predominant patterning technique for a long time. It will require the use liquid immersion and a host of resolution enhancement technologies.

8. Chemical solution deposition is also known as ____________
a) Sol-gel
b) CVD
c) Plasma spraying
d) Laser pyrolysis
Answer: a
Clarification: Sol-gel, or chemical solution deposition, is used primarily for the fabrication of material starting from a chemical solution that acts as the precursor for an integrated network.

9. Typical precursor used in sol-gel are ____________
a) Metal oxides
b) Metal dioxides
c) Metal alkoxides
d) Metal fluorides
Answer: c
Clarification: Metal alkoxides and metal chlorides are basically used as precursors in sol-gel. Furthermore, a colloidal suspension is formed when they undergo hydrolysis or poly-condensation.

10. The following is a bottom-up process.
engineering-physics-questions-answers-fabrication-nanomaterials-q10
a) True
b) False
Answer: a
Clarification: Sol-gel is a bottom-up approach in which a precursor is used to for wither a network or a colloidal suspension, so as to form desired nanoparticles.

11. Particles of ZrO2, Y2O2 and Nano whiskers have been produced by __________
a) Sol-gel
b) CVC
c) Plasma spraying
d) Laser pyrolysis
Answer: b
Clarification: CVC stands for chemical vapour condensation. It involves pyrolysis of vapours of metal organic precursors in a reduced pressure atmosphere.

12. Which gas serves as buffer gas in Laser ablation?
a) Nitrogen
b) Oxygen
c) Helium
d) Neon
Answer: c
Clarification: Laser ablation has been extensively used for the preparation of nanoparticles. In the device, there is a pulsed flow of Helium gas. It serves as a buffer gas in which clusters of the target material form, thermalize.