300+ REAL TIME Organic Chemistry Objective Questions & Answers 2023

250+ TOP MCQs on Reaction Kinetics and Answers

Organic Chemistry Multiple Choice Questions on “Reaction Kinetics”.

1. For reaction system given below, volume is suddenly reduced to half of its value by increasing the pressure on it. If the reaction is of first order with respect to O₂ and second order with respect to NO, what will be the change in the rate of reaction?
2NO(g) + O₂(g) + 2NO₂(g)
a) diminish to one-fourth of its initial value
b) diminish to one-eight of its initial value
c) increase to eight times of its initial value
d) increase to four times of its initial value
Answer: c
Clarification:

2. The rate law for a reaction between the substances A and B is given by rate = K[A]n [B]m. On doubling the concentration of A and halving the concentration of B. What will be the ratio of the new rate of the earlier rate of the reaction?
a) ((frac{1}{2}))^m+n
b) m+n
c) n-m
d) 2^n-m
Answer: d
Clarification:

3. Rate = If the volume of reaction vessel is suddenly reduced to (frac{1}{4})^th of initial value. How new rate will be affected?
a) (frac{1}{10})
b) (frac{1}{8})
c) 8
d) 16
Answer: d
Clarification:

4. On which factor the rate constant of a reaction does not depend upon?
a) temperature
b) activation energy
c) catalyst
d) concentration of reactants and products
Answer: d
Clarification: The rate constant of reaction does not depend on concentration of reactant & product (only on nature of reactant & product).

5. The rate of reaction, A + B Products, is given by the equation, r = k[A][B]. If B is taken in excess, what would be the order of reaction?
a) 2
b) 1
c) zero
d) unpredictable
Answer: b
Clarification: A + B → Products
H = k[A][B] [if B is taken in large excess then according to pseudo first order reaction. B is taken as constant]. So, order = 1.

6. In a reaction, 2A₂ + B₂ → 2A₂B, when the reactant A will disappear?
a) half the rate that B will decrease
b) the same rate that B will decrease
c) double the rate that A2B will form
d) twice the rate that B will decrease
Answer: d
Clarification:

So, the reactant A will disappear when A is twice the rate that B will decrease.

7. The rate of reaction that does not involve gases, is not dependent on _____________
a) pressure
b) temperature
c) concentration
d) catalyst
Answer: a
Clarification: The rate of reaction that does not involve gases does not depend on pressure.

8. Which is not true for a second order reduction?
a) It can have rate constant 1 x 10^-2 L mol^-1 s^-1
b) Its half-life is inversely proportional to its initial concentration
c) Time to complete 75% reaction is twice of half-life
d) T₅₀ = 1/(k_a⋅A₀)
Answer: c
Clarification:

but t₇₅ = 3 * t₅₀
So, option Time to complete 75% reaction is twice of half-life is wrong statement for n = 2.

9. The rate of decomposition of a substance increases concentration of substance at same temperature. Find out order of reaction.
a) 1
b) 2
c) 3
d) 0
Answer: b
Clarification: Rate = k [A]^α
R₁ = k[A]ⁿ
R₂ = k [1.5 A]ⁿ = 2.25 R₁
k(1.5A)ⁿ = 2.25*k*[A]ⁿ
(1.5)ⁿ * [A]ⁿ = 2.25*[A]ⁿ
n log (1.5) = log (2.25)
n = 2.

10. If a reaction is n^th order the half-life period ________ of the initial concentration of the reactants.
a) is independent
b) varies inversely as (n-1)^th power
c) varies inversely as n^th power
d) varies directly as (n-1)^th power
Answer: b
Clarification: For nth order; So, varies inversely as (n – 1)^th power.

250+ TOP MCQs on Carbohydrates and Answers

Organic Chemistry Multiple Choice Questions on “Carbohydrates”.

1. Which Biomolecules simply refers as “Staff of life” in the given macromolecules?
a) Protein
b) Lipids
c) Carbohydrate
d) Vitamins
Answer: c
Clarification: Carbohydrates belong to a group of complex biomolecules commonly regarded as the “staff of life.” They are the most abundant organic compounds in living organisms and are among the four major classes of biomolecules. During photosynthesis, carbohydrates are produced from the reaction of carbon dioxide with water. Carbohydrates go by several common names, including sugars, starches, saccharides, and polysaccharides.

2. In carbohydrates which are the main functional groups are present?
a) Alcohol & Carboxyl groups
b) Aldehyde & Ketone groups
c) Hydroxyl groups & Hydrogen groups
d) Carboxyl groups & Others
Answer: a
Clarification: Carbohydrates are often represented by the chemical formula C_x(H₂O)y, where the numerical values of x and y range from 3 to 12, and functional groups are Alcohol & Carboxyl groups.

3. Majority of the monosaccharides found in the human body are of which type stereoisomer?
a) L-type
b) D-type
c) neutral
d) racemic mixture
Answer: b
Clarification: Majority of the monosaccharides found in the human body are of D-type stereoisomer. The D-isomer of glucose predominates in nature and it is for this reason that the enzymes in our body have adapted to binding this form only.

4. Which is the simplest carbohydrate?
a) Dihydroxy acetone
b) Glycerldehyde
c) Glucose
d) Gulose
Answer: b
Clarification: Glyceraldehyde (glyceral) is a triose monosaccharide with chemical formula C₃H₆O₃. It is the simplest of all common aldoses.

5. Which of the following is the examples of Epimers?
a) Glucose & Galactose
b) Glucose & Ribose
c) Mannose & Glucose
d) fructose and glucose
Answer: a
Clarification: In stereochemistry, an epimer is one of a pair of stereoisomers. The two isomers differ in configuration at only one stereogenic center. All other stereocenters in the molecules. The sugars glucose and galactose are epimers. In glucose, the -OH group on the first carbon is in the axial position, the direction opposite the -OH group on carbon C-4. In galactose, the -OH group is oriented in the same direction, the equatorial position.

6. Which of the following is true about Turanose?
a) Reducing disaccharides of glucose and fructose
b) Non-reducing disaccharide
c) 7-methyl sugar
d) a deoxy sugar
Answer: a
Clarification: Turanose educing sugar (3-O-α-D-glucosyl-D-fructose), an isomer of sucrose, naturally exists in honey.

7. Which of the following is not a disaccharide?
a) Sucrose
b) Maltose
c) Lactose
d) Galactose
Answer: d
Clarification: Sucrose, maltose and lactose are disaccharide and galactose is a monosaccaride.

8. Which sugars are present in Sucrose?
a) Fructose and glucose
b) Glucose and glucose
c) Glucose and galatose
d) Fructose and galatose
Answer: a
Clarification: Sucrose is commonly known as table sugar and is obtained from sugar cane or sugar beets contain fructose and glucose as monomers.

9. Which of the following carbohydrate do not have any essential nutritional value?
a) Sucrose
b) Cellulose
c) Dextrin
d) Glycogen
Answer: c
Clarification: Dextrins are a group of low-molecular-weight carbohydrates produced by the hydrolysis of starch or glycogen. Dextrins are mixtures of polymers of D-glucose units linked by α-(1→4) or α-(1→6) glycosidic bonds. Dextrin Function. Dextrin is a source of energy; it contains 3.8-4.1 Calories per gram. Dextrin is not an essential nutrient, so you do not need to get it from food to be healthy.

10. Which of the following will not be reactive towards seliwanoff reagent?
a) Maltose
b) Inulin
c) Fructose
d) Sucrose
Answer: a
Clarification: Maltose is an aldose sugar and only ketoses give a positive Seliwanoof’s test. Sucrose, Inulin and fructose contain a ketose, and maltose does not. Only Therefore, sucrose, Inulin and fructose will give a positive Seliwanoof’s test, but maltose will not.

250+ TOP MCQs on Tautomerism and Answers

Organic Chemistry Multiple Choice Questions on “Tautomerism”.

1. How many enolisable hydrogens are there in the following compound?

a) 4
b) 5
c) 6
d) 7
Answer: a
Clarification: The hydrogen atom present on the carbon which is adjacent to the carbon attached to the functional group, and here it is 4.

2. How many tautomers can you draw for the following ketone?

a) 1
b) 2
c) 3
d) 4
Answer: b
Clarification: Two isomers can be drawn as shown below:

3. How many tautomers can you draw for the following ketone?

a) 1
b) 2
c) 3
d) 4
Answer: b
Clarification: Two isomers can be drawn as shown below.

4. Which of the following is a tautomer of phenol?
a)
b)
c)
d)
Answer: c
Clarification: According to the tautomerism the tautomer of phenol is c.

5. Which of the following compound exhibit tautomerism?

a) I
b) II
c) I and II
d) Neither I nor II
Answer: c
Clarification: For Keto-Enol tautomerism, keto form should have α-hydrogen.

6. In keto-enol from presence of which type of hydrogen is must?
a) Alpha
b) Beta
c) Gamma
d) Any position of hydrogen
Answer: a
Clarification: For Keto-Enol tautomerism, keto form should have α-hydrogen, as shown in below example.

7. Which of the following tautomeric form is more stable?

CH₃-CH=O   ↔   CH₂=C-OH 
      (I)                         (II)

a) I
b) II
c) Both are equally stable
d) Both are unstable
Answer: a
Clarification: The keto–enol tautomerization chemical equilibrium is highly thermodynamically driven, and at room temperature the equilibrium heavily favors the formation of the keto form.

8. What is the stability order for the following compounds?

a) I > II > III
b) II > I > III
c) III > II > I
d) I > III > II
Answer: b
Clarification: The keto–enol tautomerization, less stable enolate ion will be formed faster as it is thermodynamically stable, so III is more stable than I.
II is most sable as it is keto form.

9. What is the stability order for the following compounds?

a) I > II > III
b) II > I > III
c) III > II > I
d) I > III > II
Answer: b
Clarification: The keto–enol tautomerization, less stable enolate ion will be formed faster as it is thermodynamically stable, so III is more stable than I.
II is most sable as it is keto form.

10. Which of the following structure can show tautomerism?

a) I
b) II
c) III
d) I and III
Answer: b
Clarification: Quinone has an α-hydrogen; however, it is a vinylic hydrogen (hydrogen attached to a carbon atom which is sp2 hybridized), it is very difficult to abstract such a hydrogen, and hence it becomes very less acidic. Therefore, no abstraction of α-hydrogen from it, by a base, hence, it does not show tautomerism, same is for III.

250+ TOP MCQs on Chemical Properties of Amines – 2 and Answers

Organic Chemistry online quiz on “Chemical Properties of Amines – 2”.

1. A primary amine can be converted to an alcohol by the action of which of the following?
a) Alkali
b) Nitrous acid
c) Reducing agent
d) Oxidizing agent
Answer: b
Clarification: A primary amine can be converted to an alcohol by the action nitrous acid.
R – NH₂ + HNO₂ → R – OH + N₂ + H₂O

2. The amine which can react with C₆H₅−SO₂−Cl to form a product insoluble in alkali shall be, is which of the following?
a) Primary amine
b) Secondary amine
c) Tertiary amine
d) Both primary and secondary amines
Answer: b
Clarification: C₆H₅SO₂Cl is called Hinsberg’s reagent they react with sec amine to form a product in soluble in alkalies. This reaction used to separate primary, secondary and tertiary amine from their mixture.

3. A mixture of benzene and aniline can be separated by which of the following?
a) Hot water
b) dil. HCl
c) dil. NaOH
d) Alcohol
Answer: b
Clarification: A mixture of benzene and aniline can be separated by dil. HCl. The mixture is treated with dil. HCL. Only aniline dissolves. It is then shaken with ether. Nitrobenzene goes into ether layer. It is separated.

4. An organic amino compound reacts with aqueous nitrous acid at low temperature to produce an oily nitroso amine. What is this compound?
a) CH₃NH₂
b) CH₃CH₂NH₂
c) CH₃CH₂NH.CH₂CH₃
d) (CH₃CH₂)₃
Answer: b
Clarification: Secondary amines gives oily nitrosamine with nitrous acid.
(CH₃CH₂)₂NH + HONO → (CH₃CH₂)₂N.NO + H₂O

5. Reaction of aniline with benzaldehyde is which type of reaction?
a) Polymerisation
b) Condensation
c) Addition
d) Substitution
Answer: b
Clarification: Reaction of aniline with benzaldehyde is a condensation reaction. Aniline react by initially attacking the carbonyl carbon, followed by hydrogen transfers to give an amine where the nitrogen is bonded to a carbon that also contains a hydroxy group. Under acidic conditions, the hydroxyl group is protonated, followed by loss of water to give the conjugate acid of the observed product(imine). The condensation step to give water is acid catalyzed and is the rate-determining step of the sequence.

6. In the reaction, what is the compound C₆H₅N=CHC₆H₅ is known as?
C₆H₅CHO + C₆H₅NH₂ → C₆H₅N=HCC₆H₅ + H₂O
a) Aldol
b) Schiffs reagent
c) Schiffs base
d) Benedict reagent
Answer: c
Clarification: Aniline react by initially attacking the carbonyl carbon (benzaldehyde), followed by hydrogen transfers to give an amine where the nitrogen is bonded to a carbon that also contains a hydroxy group. Under acidic conditions, the hydroxyl group is protonated, followed by loss of water to give the conjugate acid of the observed product(imine). Hydrogen ion transfer then gives the Schiff base product. The condensation step to give water is acid catalyzed and is the rate-determining step of the sequence.

7. Electrophilic substitution of aniline with bromine in presence of gacial acetic acid gives which of the following?
a) 1, 4, 6-tribromo aniline
b) 2, 4, 6-tribromo aniline
c) 4-bromo aniline
d) 3-bromo aniline
Answer: c
Clarification: In water,bromine is ionised up to greater extent to form large number of bromonium ions.Hence Br+ ions attack on aniline from either side to form 2,4,6,-tribromoaniline. In order to obtain monobromo aniline, reaction is carried out in presence of acetic acid. In glacial acetic acid, bromine is ionised to lesser extent and hence relatively less number of bromonium ions are formed.Thus interference of water is ceased.

8. During acetylation of amines what is replaced by acetyl groups?
a) Hydrogen atom attached to nitrogen atom
b) One or more hydrogen atoms attached to carbon atom
c) One or more hydrogen atoms attached to nitrogen atom
d) Hydrogen atoms attached to either carbon atom or nitrogen atom
Answer: c
Clarification: During acetylation of amines One or more hydrogen atoms attached to nitrogen atom are removed.

9. Ethyl amine on acetylation gives which of the following?
a) N-ethyl acetamide
b) Acetamide
c) Methyl acetamide
d) Propyl acetamide
Answer: a
Clarification: Ethyl amine on acetylation gives N-ethyl acetamide.
CH₃CH₂NH₂ + CH₃COCl → CH₃CH₂NHCOCH₃ + HCl

10. p-chloro aniline and anilinium hydrogen chloride can be distinguished by which of the following?
a) Sandmaeyer reaction
b) Carbyl amine reaction
c) Hinsberg’s reaction
d) AgNO₃
Answer: d
Clarification: Anilinium hydrogen chloride produces chloride ion which gives white precipitate with AgNO₃. In fact, anilium chloride is a part of aniline.

11. Identify the product Z in the following reaction.

a) p-Bromoaniline
b) p -Bromoacetophenone
c) o-Bromoacetophenone
d) o-Bromoacetanilide
Answer: a
Clarification: p-Bromoaniline is formed. For the protection of p- position for bromination, reaction of aniline with acetic anhydride is done and followed by bromination of the product (acetanilide). And then removal of protective group in p-bromoacetanilide is done by hydrolysis, and p- Bromoaniline is formed.

12. Aniline reacts with which of these to form Schiff base?
a) Acetic acid
b) Benzaldehyde
c) Acetone
d) NH₃
Answer: b
Clarification: Aniline reacts with benzaldehyde and forms Schiff’s base (benzal aniline) or anils.

13. Reaction of cyclohexanone with dimethylamine in the presence of catalytic amount of an acid forms a compound if water during the reaction is continuously removed. What is the compound formed is generally known as?
a) A Schiff’s base
b) An enamine
c) An imine
d) An amine
Answer: b
Clarification: Reaction of cyclohexanone with dimethylamine in the presence of catalytic amount of an acid forms a compound if water during the reaction is continuously removed. This compound is known as enamine.

14. Nitration of aniline also gives m-nitro aniline, in strong acidic medium because of which of the following reasons?
a) In electrophilic substitution reaction amino group is meta directive
b) Inspite of substituents nitro group always goes to m- position
c) In strong acidic medium, nitration of aniline is a nucleophic substitution reaction
d) In strong acidic medium aniline present as anilinium ion
Answer: b
Clarification: The reason for this is that, in acidic condition protonation of −NH₂ group gives anilinium ion (+NH₃), which is of deactivating nature and of m-directive nature.

15. The reductive amination of an aldehyde (e.g. the reaction of propanal with ethylamine) can be carried out in the laboratory using which of the following as a reducing agent?
a) NaBH₃CN
b) LiAlH₄
c) BH₃
d) NaBH₄
Answer: a
Clarification: The reductive amination of an aldehyde (e.g. the reaction of propanal with ethylamine) can be carried out in the laboratory by using NaBH₃CN reagent.

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250+ TOP MCQs on Source of Pyridine Compounds and Answers

Organic Chemistry Multiple Choice Questions on “Source of Pyridine Compounds”.

1. Which of the following plant is the natural source of pyridine?
a) Atropa belladonna
b) Ocimum tenuiflorum
c) Azadirachta indica
d) Ficus religiose
Answer: a
Clarification: Pyridine is not abundant in nature, it is present in the leaves and roots of belladonna (Atropa belladonna).

2. Why is extraction of pyridine from coal tar or as a byproduct of coal gasification ineffective?
a) Less concentration of desired compound
b) This method is expensive
c) Reactive is rare
d) Dangerous procedure
Answer: a
Clarification: The process was labor-consuming and inefficient because coal tar contains only about 0.1% pyridine, and therefore a multi-stage purification was required, which further reduced the output.

3. Which of the following derivative of pyridine is mostly found in mycobacterium tuberculosis?
a) Niacin
b) Nicotinamide
c) Nicotinic acid
d) Strychnine
Answer: c
Clarification: The bacteria Mycobacterium tuberculosis and Escherichia coli produce nicotinic acid by condensation.

4. Mycobacterium tuberculosis and Escherichia coli produce nicotinic acid by condensation of which of the following compounds?
a) Glyceraldehyde 3-phosphate
b) Amino acid
c) Pyrrole
d) acetylene
Answer: c
Clarification: The bacteria Mycobacterium tuberculosis and Escherichia coli produce nicotinic acid by condensation by glyceraldehyde 3-phosphate and aspartic acid.

5. Which of the following derivative of pyridine is mostly found in mammals?
a) Nicotinamide
b) Vitamin B6
c) Nicotinic acid
d) Strychnine
Answer: c
Clarification: Mammals synthesize nicotinic acid through oxidation. The coenzyme forms of nicotinic acid are nicotinamide adenine dinucleotide (NAD). These compounds assist dehydrogenase enzymes in the catabolism of fat, carbohydrates, and amino acids, and in the enzymes involved in synthesis of fats and steroids and other vital metabolites.

6. Mycobacterium tuberculosis and Escherichia coli produce nicotinic acid by condensation of which of the following compounds?
a) Glyceraldehyde 3-phosphate
b) Kynurenine
c) Pyrrole
d) Tryptophan
Answer: c
Clarification: Mammals synthesize nicotinic acid through oxidation of the amino acid ‘tryptophan’, where an intermediate product, aniline, creates a pyridine derivative, kynurenine.

7. What is the name of the reaction given below when condensation of acrolein and acetaldehyde take place?

a) Chichibabin synthesis
b) Dealkylation of alkylpyridine
c) Hantzsch pyridine synthesis
d) Bonnemann cyclisation
Answer: a
Clarification: The reaction can be described as a condensation reaction of aldehydes, ketones, α, β-unsaturated carbonyl compounds, or any combination of the above, in ammonia. In particular, unsubstituted pyridine is produced from acetaldehyde, which are inexpensive and widely available.

8. In the synthesis of pyridine by Chichibabin synthesis, synthesis of acroloien is done which method?
a) Knoevenagel Condensation
b) Aldol condensation
c) Dieckmann condensation
d) Claisen condensation
Answer: a
Clarification: Acrolein is formed in a Knoevenagel condensation from the acetaldehyde and formaldehyde. It is then condensed with acetaldehyde and ammonia into dihydropyridine.

9. Which of the following reagent can’t be used as the reagent in the dealkylation of alkylpyridines in the pyridine synthesis?
a) Vanadium oxide
b) Nickel based catalyst
c) Silver or platinum-based catalyst
d) Copper catalyst
Answer: d
Clarification: The oxidative dealkylation is carried out either using air over vanadium(V) oxide catalyst, by vapor-dealkylation on nickel-based catalyst, or hydrodealkylation with a silver- or platinum-based catalyst. There are no evidences found when copper is used as catalyst in this reaction.

10. What is the name reaction of the following reaction?

a) Chichibabin synthesis
b) Dealkylation of alkylpyridines
c) Hantzsch pyridine synthesis
d) Bönnemann cyclization
Answer: c
Clarification: The Hantzsch pyridine synthesis typically uses a 2:1:1 mixture of a β-keto acid (often acetoacetate), an aldehyde (often formaldehyde), and ammonia or its salt as the nitrogen donor.

11. Which of the following catalyst can be used in the synthesis of pyridine by Bönnemann cyclization?
a) Vanadium oxide
b) Nickel based catalyst
c) Silver or platinum-based catalyst
d) Cobalt catalyst
Answer: d
Clarification: The trimerization of a part of a nitrile molecule and two parts of acetylene into pyridine is done with CoCp2(cod) (Cp = cyclopentadienyl, cod = 1,5-cyclooctadiene) as a catalyst, and can be performed even in water.

12. What is the name reaction of the following reaction?

a) Chichibabin synthesis
b) Dealkylation of alkylpyridines
c) Hantzsch pyridine synthesis
d) Bönnemann cyclization
Answer: d
Clarification: The trimerization of a part of a nitrile molecule and two parts of acetylene into pyridine is called Bönnemann cyclization.

13. What is the name reaction of the following reaction?

a) Chichibabin synthesis
b) Ciamician–Dennstedt rearrangement
c) Kröhnke pyridine synthesis
d) Bönnemann cyclization
Answer: b
Clarification: The Ciamician–Dennstedt rearrangement entails the ring-expansion of pyrrole with dichlorocarbene to 3-chloropyridine.

250+ TOP MCQs on Organic Reactions and Answers

Organic Chemistry Multiple Choice Questions on “Organic Reactions”.

1. Identify the one which does not come under the organic addition reaction?
a) Hydration
b) Dehydration
c) Halogenation
d) Hydrohalogenation
Answer: b
Clarification: Dehydration comes under elimination reaction and hence it does not come under addition reaction.

2. Choose the correct one which will react faster in the SN2 nucleophilic substitution reaction?
a) CH₂ – CH = CH₂ = Br
b) CH₂ = CH – CH₂ – Br
c) CH₂ = CH – CH₂ = Br
d) CH = CH₂ – CH₂ – Br
Answer: b
Clarification: The carbocation character in the transition state causes stabilization of the resonance and hence CH₂ = CH – CH₂ – Br (2- bromobutane) is the one which will react faster compared to the others.

3. What will be the reactivity of chlorobenzene in an electrophilic substitution reaction with benzene?
a) Reacts very slowly than benzene
b) Reacts in the same way as benzene
c) Reacts faster than benzene
d) Does not react with benzene
Answer: a
Clarification: The rate of the reaction depends on the electron density in the ring and here in this case resonance is not favorable and the electronegativity dipole dominates. This slows down the reactivity of chlorobenzene.

4. Alcohol on refluxing with Cr₂O₇ gives ____________
a) Ester
b) Aldehyde
c) Sugar
d) Carboxylic acid
Answer: d
Clarification: Alcohol (R-OH), when it is refluxed with Cr₂O₇, it forms carboxylic acid (R-COOH).

5. Alkene under high temperature and high-pressure forms ___________
a) Alcohol
b) Polyalkyne
c) Polyalkane
d) Polyalkene
Answer:c
Clarification: Alkenes undergoes polymerization reaction under high temperature and pressure to form poly alkanes -(C-C)-n.

6. Identify the one which on reaction with carboxylic acid at high temperature gives Ester?
a) Ketone
b) Alcohol
c) Aldehyde
d) Sugars
Answer: b
Clarification: Alcohols on reaction with carboxylic acid at high temperature, in the presence of sulphuric acid gives Ester.

7. Select the correct statement regarding carboxylic acids.
a) They form acyl chlorides on reaction with PCl₅
b) Aldehydes in the presence of H⁺/Cr₂O₇ forms carboxylic acids
c) They combine with alcohols to form esters
d) Upon polymerization, they form polymers
Answer: d
Clarification: Carboxylic acids do not undergo polymerization reaction.

8. Primary alcohols undergo what reaction to form alkenes?
a) Elimination
b) Oxidation
c) Reduction
d) Hydrolysis
Answer: a
Clarification: Upon elimination or dehydration, the primary alcohols form alkenes.

9. Carbonyl compounds especially ketones undergo reduction to form __________
a) Primary alcohols
b) Secondary alcohols
c) Alkanes
d) Alkenes
Answer: b
Clarification: Ketones in the presence of NaBH₄ undergoes reduction to form secondary alcohols.

10. Primary amides get converted into primary amines by _________
a) Addition
b) Oxidation
c) Reduction
d) Acylation
Answer: b
Clarification: Primary amides upon heating in the presence of hydrogen and nickel catalyst, gets reduced to form primary amines.