[Physics Class Notes] on Wiedemann Franz Law Pdf for Exam

Franz Law is one of the important laws in physics. This law was discovered and termed after the German physicists, Gustav Wiedemann and Rudolph Franz, in 1835. Gustav Wiedemann revealed that thermal Conductivity (κ) and electrical Conductivity (σ) are roughly having an identical value at the same temperature for dissimilar metals.

This empirical law is named after Gustav Wiedemann and Rudolph Franz, who, in 1853, described that κ / σ has about the identical value for dissimilar metals at the precise temperature. In 1872, the proportionality of κ / σ with temperature was revealed by Ludvig Lorenz.

Wiedemann Franz law

In Wiedemann Franz law

k = Thermal Conductivity. It is a degree of measurement of a material to conduct heat.

σ = Electrical Conductivity is noted as a degree of measurement of a material to conduct electricity (1/ρ).

The law formulates that the proportion of the electronic contribution of the thermal conductivity (κ) to the electrical conductivity (σ) of metal is slightly similar to the temperature (T).

[frac{K}{σ}]= LT

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Here,

L = proportionality constant, and it is named as the Lorenz number. 

L = [frac{K}{σT}]=[frac{π^{2}}{3}(frac{K_B}{e})^{2}]WΩK-2    

  • The connection in the middle of the thermal and electrical conductivity is centered on the point that heat and the electrical movement contain freely roaming electrons in the metal. 

  • The thermal conductivity raises the velocity of the average particle and also surges in the frontward energy movement. Alternatively, electrical conductivity reduces the velocity of the particle.

Thermal Conductivity of Wiedemann Franz law

Heat transfer by conduction includes the transmission of energy inside a material deprived of any movement of the material altogether. The amount of heat transfer establishes the thermal conductivity and the temperature gradient of the material. 

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Arithmetical methods can be utilized for the measurement of the conduction of heat transfer across smooth walls, but the heat transfer must be stated concerning the thermal gradient for most cases.

Theoretically, thermal conductivity can be assumed as the vessel for the medium-dependent things which describe the level of heat loss per unit range to the rate of change of temperature.

The measured gradient of a function is a direction-finding derivative, which indicates in the track of the maximum rate-of-change of the function. 

The heat transfer’s direction will be reversed to the temperature gradient in the meantime when the net energy transfer will be from high to low temperature. 

The maximum value of the heat transfer direction will be perpendicular to the equal-temperature surfaces adjacent to a heat source.

State Wiedemann and Franz law

This law depicts that “the ratio of the thermal conductivity to the electrical conductivity of a metal is relative to the temperature.” Qualitatively, this connection is centered on the detail that the heat and electrical transport contain the unrestricted electrons in the metal. 

The thermal conductivity upsurges with the average particle velocity, that rises the forward carriage of energy. 

However, the electrical conductivity cuts with particle velocity rise because the impacts distract the electrons from forwarding transportation of charge. This revenue that the ratio of thermal to electrical conductivity hangs upon the average velocity squared, which is relational to the kinetic temperature. 

The molar heat capacity of a classical mono-atomic gas is indicated as

cv = [frac{3}{2}R=frac{3}{2}N_Ak]

The Wiedemann-Franz law can be assumed by observing the electrons like a conventional gas & comparing the resultant thermal conductivity to the Electrical Conductivity. 

The thermal and electrical conductivity’s expressions are outlined here below:

Thermal conductivity k = [frac{n(v)λk}{2}]

Electrical conductivity σ = [frac{ne^{2}λ}{m(v)}]

The mean particle speed from kinetic theory can be expressed as;

(v)=[sqrt{frac{8kT}{πm}}]

The ratio of these quantities can be stated in terms of the temperature. The ratio of thermal to electrical conductivity exemplifies the Wiedemann-Franz Law as:

[frac{k}{σ}] = [frac{4k^{2}T}{πe^{2}}]

This is in the form of the Wiedemann Franz Law.

The value of the constant has an error in this conventional calculation. When the quantum mechanical conduct is done, the rate of the constant is initiated as:

L = [frac{k}{σT}] = [frac{π^{2}k^{2}}{3e^{2}}]= 2.45 × [10^{-8}WΩ/K^{2}]

The point that the ratio of thermal to electrical conductivity times the temperature is constant forms the core of the Wiedemann-Franz Law. 

Notably, it is also free of the number density of the particles and the particle mass.

Wiedemann Franz law limitations

Experimentations have uncovered that the value of L, while approximately constant, is not precisely identical for all materials. 

Kittel delivers some standards of L changing from L = 2.23×10−8 W Ω K−2 for copper at 0 °C to L = 3.2×10−8 W Ω K−2 for tungsten at 100°C. 

Rosenberg archives that the Wiedemann and Franz law is usually functional for high temperatures and low temperatures (i.e., a few Kelvins), but may not hold at in-between temperatures.

  • In many high purity metals, both the electrical and thermal conductivities increase as temperature declines. 

  • In some materials (such as aluminum or silver), however, the value of L also may fall with temperature. In the cleanest silver samples and at very little temperatures, L can drop by as much as an amount of 10.

[Physics Class Notes] on X-Ray Diffraction Pdf for Exam

X-ray diffraction is a non-destructive solid technique for delineating crystalline materials. It gives information on phases, structures, favored crystal orientations (texture), and different structural parameters, such as strain, crystallinity, medium grain size, and crystal cracks. XRD peaks are designed by the constructive intervention of a monochromatic beam of X-rays interspersed at distinct angles from each collection of lattice planes in a specimen. The peak intensities are defined by the atomic positions inside the lattice planes. 

Consequently, the XRD design is the fingerprint of periodic atomic methods in a dispensed material. A standard database of online research for X-ray powder diffraction patterns allows quick phase identification for a wide variety of crystalline samples. X-ray diffraction results from radiation being scattered by a regular array of scattering centers whose spacing is the same as the radiation. Diffraction gratings need to have spacings equivalent to the wavelength of diffracted radiation.

These are not merely two paragraphs based on the explanation of X-Ray Diffraction, but these are the total efforts of physical specialists to offer the best clarity of the topic to the students. Knowing the fact that physics demands a bit more time in comprehension and introducing new concepts is a bit challenging, ’s subject matter experts refer to the matter from the most authentic sources. So much focus is given on the explanation because once the explanation is clear in the mind, then it will be a breeze to grasp associated topics like types, processes, applications, and more. 

X-Ray Diffraction Analysis

X-ray diffraction analysis (XRD) is a method used in materials science to determine the material’s crystallographic structure. XRD operates by measuring the X-rays’ intensities and scattering angles that leave the material.

The primary use of X-ray diffraction analysis is the identification of materials based on their diffraction pattern. The x-ray diffraction method in phase identification also gives information on how the ideal structure differs from the exact one, owing to internal defects and stresses.

has shared the analysis in the simplest language as after the definition it is going to be a scoring topic. To enhance the level of comprehension, the tutors opt for a real-time session for explaining analysis as once we discuss something thoroughly while reading it, then we are likely to retain it in our minds for longer. Our aim is not confined to raising your scorebook but we primarily work on enriching your knowledge so that your thoughts have more weightage in the practical world. Plus, the students with the help of can not only dream of getting into a good college but they can also aim for a dream job. 

How Does it Work?

Crystals are periodic arrays of atoms, whilst X-rays can be deemed as waves of electromagnetic radiation. Crystal atoms scatter incident X-rays, mainly through interaction with the atoms’ electrons. This occurrence is identified as elastic scattering; the electron is known as the scatterer. A regular array of scatterers presents a constant array of orbicular waves. In the bulk of directions, these waves eliminate each other out through destructive interference; however, they combine constructively in less explicit directions, as defined by Bragg’s law:

2d sinθ = nλ

here, 

d is the space between the diffracting planes,

θ (theta) = incident angle, 

n = integer 

and 

λ = beam wavelength 

The particular directions resemble spots on the diffraction pattern called reflections. Consequently, impinging on a regular array of scatterers, the X-ray diffraction patterns emerge from the electromagnetic waves. To form the X-ray diffraction pattern x-rays are used, because their wavelength, λ, is mostly in the same order of magnitude as the spacing, d, between the crystal planes (1-100 angstroms).

Once you are clear with the explanation and analysis, it is time to know about its working. After the theory classes, teachers will show it through practical sessions. The teachers at guide the student to stay versed with the formulas otherwise it will be hard to learn all the formulas in a single go when exams will come nearer. Therefore, at , the syllabus is set in a manner that students get ample time for learning, practicing, revising, and yes clearing doubts. So, students pace your preparation with and you are going to make a difference with your mark sheet. Plus, you will be able to get an edge over your peer groups. 

X-Ray Diffraction by Crystals

X-ray diffraction by crystals can be exactly as the visible light is diffracted by a diffraction grating; in other words, we can state that crystals can be used as diffraction gratings for diffraction X-rays. Von Laue first conceived this important concept in 1912, and consequently, it was tested by Freidrich and Knipping. They confirmed that an X-ray beam passing through a single crystal was undoubtedly split up into a set of diffracted beams.

The x-ray diffraction by crystals is the only connection with the direct exploration of the crystals’ interior; that is, in connection with the fixations of the atoms’ position on the crystal lattice, the measurement of the distances between atoms and the associated internal symmetry.

Such a study is suitable because the intensities of diffracted beams and their directions are related to crystals’ atomic arrangements. Thus, measurements of their directions and intensities would present the desired information about crystals. 

X-Ray Diffraction Pattern

An X-ray diffraction pattern is the intensity plot formed when the sample scatters x-rays in question at varying degrees. There is a unique X-Ray pattern for each “phase.” In a mixture, the x-ray diffraction pattern is the addition of patterns of the individual phases. On the other hand, any observed XRD pattern is, in reality, an addition/sum of patterns generated by separate stages within a mix. Data from x-ray diffraction experiments are compared with reference pattern data to understand the phases present in a sample.

Conclusion 

Hence, you are certainly going to love the study method introduced by . You will get a chance to do a stepwise study where the classes begin with the definition. The emphasis on concept clarity will be ample before moving towards the analysis part. Once the students are clear with the basic concept, the classes progress towards working and pattern of X-Ray Diffraction. Are you impressed with the teaching style of and want to join us? It is really smooth with the help of your ID and password. You can either get to us via a website or you can simply come to us through a mobile application. The entire process is quite simple with a few clicks of the mouse. This is all up to your individual choice. So, the team is waiting to welcome you!

[Physics Class Notes] on Boyles Law Formula Pdf for Exam

There is quite a relation between pressure and volume and is provided by a formula. This formula was given by Robert Boyle in 1660. He is also rightly known as the Father of Modern Chemistry who has worked both in the fields of chemistry and physics. A book named The Spring and Weight of the Air is the one in which he had mentioned the various experiments that he had conducted using a vacuum pump and has also mentioned this relation between volume and pressure which is also called Boyle’s law.

Boyle’s Law Formula

According to this experimental gas law, the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature. An important point to note here is that the amount of ideal gas (i.e., number of moles) is kept fixed and a constant temperature is maintained. Under this condition, the pressure of the gas will tend to increase if we decrease the volume of the container and vice-versa.

 

Mathematically, it can be expressed as:

Where ‘P’ is the pressure exerted by the gas and ‘V’ is the Volume of the container.

Graphically, we can observe the behaviour of the curve as follows:

You can see how the value of Pressure decreases when the Volume is increased or vice-versa.

In order to understand it better, let us go through a simple example:

Example: If 20[c{m^3}] gas at 1 atm. is expanded to 50 [c{m^3}] at constant T, then what is the final pressure

Options:

(a) [20 times frac{1}{{50}}]

(b) [50 times frac{1}{{20}}]

(c) [1 times frac{1}{{20}} times 50]

(d) None of these

Answer: (a)

Solution:

At constant [T,{P_1}{V_1} = {P_2}{V_2}]

[1 times 20 = {P_2} times 50]; [{P_2} = frac{{20}}{{50}} times 1]

We hope you have understood, how to apply the Boyle’s Law Formula. Now in order to test your understanding, try and solve the Question by yourself.

Example: An ideal gas exerts a pressure of 3atm in a 3L container. The container is at a temperature of 298K. What will be the final pressure if the volume of the container changes to 2L?

Options:

(a) 2 atm

(b) 3.5 atm

(c) 4.5 atm

(d) 4 atm

Answer: (c)

Solution:

Boyle’s law can be written as follows:

[{P_1}{V_1} = {P_2}{V_2}]

Use the given volumes and the initial pressure to solve for the final pressure.

(3atm)(3L)=(2L)P2

P2=4.5atm

[Physics Class Notes] on Energy Density Formula Pdf for Exam

What is Energy Density?

Energy Density refers to the total amount of energy in a system per unit volume. (Even though generally energy per unit mass is also mentioned as energy density, the proper term for the same is specific energy. The term density usually measures the amount per unit spatial extension). Hence energy density is stored energy in a given system or region of space per unit volume. In this article, we will learn about the formula of calculation of the energy density of any system.

Energy Density Formula

Energy density is denoted by the letter U.

Magnetic and electric fields can also store energy.

In the case of an electric field or capacitor, the energy density is given by UE = [frac{1}{2}]εoE2

The energy density in the case of magnetic field or inductor is given by, UB =[frac{1}{2mu _0}] B2

Where UE = Electrical energy density

UB= Magnetic energy density 

εo=Permittivity

E= Electric field

B=Magnetic field

μ= magnetic permeability

For electromagnetic waves, both magnetic and electric fields are equally involved in contributing to energy density. Therefore, the energy density is the sum of the energy density of electric and magnetic fields.

i.e.,                  U = [frac{1}{2}]εoE2 + [frac{1}{2mu _0}]B2

Solved Examples

Example 1: In a certain region of space, the magnetic field has a value of 1.0 × 10–2 T, and the electric field has a value of 2.0 ×106 Vm-1. Find the combined energy density of the electric and magnetic fields.   

Solution: E = 2.0 × 106 Vm-1; B = 1.0 × 10-2 T

For the electric field, the energy density is UE = [frac{1}{2}] εoE2

=12 × 8.85 × 10−12(2.0 × 106)2 = 18Jm−3

For the magnetic field, the energy density is UB =[frac{1}{2mu _0}]B2

=[frac{1}{2} times frac{(1.0 times 10^{-2})^{2}}{4pi times 10^{-7}} = 40jm^{-3}]

The net energy density is the sum of the energy density due to the electric field and the energy density due to the magnetic field: 

U= UE + UB = 18 + 40 = 58 Jm-3

Example 2: In a certain region of space, the magnetic field has a value of 3X10-2T, and the electric field has a value of 9X107 V/m. Calculate the energy density of the electric and magnetic fields?

Solution: B = 3  X 10-2T, E = 9 X 107 V/m, ε = 8.85 X 10-12 C2 / Nm2 and μ = 4π X 10-7 N/A2.

UE = 12εoE2

UE = 8.85 X 10-12 C2 / Nm2 X (9X107V/m)2/2

UE = 35842.5 J/m3

UB =10B2

UB = (3 X 10-2T)2 / 2 X 4π X 10-7 N/A2

UB = 358.1J/m3

U = UE + UB

U = 35,842.5 J/m3 + 358.1 J/m3

U = 36200.6 J/m3

Conclusion

The formula of the energy density of a system is the sum of the energy density of electric fields and magnetic fields. The above article is useful for the students to revise the formula of energy density and the solved example will help them to understand how to apply the formula in numerical. 

[Physics Class Notes] on Equivalent Resistance Formula Pdf for Exam

Equivalent resistance formula refers to the resistance of resistors connected in series, parallel or a combination of both. This formula helps us calculate the equivalent resistance easily when two or more two circuit elements are combined together to form complex electrical circuits and the total resistance of the circuit is measured.

Importance of Studying Equivalent Resistance Formula

It is important to study equivalent resistance formulas because it is used to calculate the total equivalent circuit without drawing them physically. It helps us find out the effective value of a resistor that is connected in a series connection or parallel combination if an unknown current flows through a particular branch of a complex electrical circuit.

Ways for Studying Equivalent Resistance Formula

1)  Make flashcards-

Flashcards are one of the best ways to study. There is no better way than making your own! Get a piece of paper and label it “equivalent resistance” on one side, 𝑘 𝐿 = R in series + R parallel, then make two columns labeled “R in series”, which will be all terms that follow this formula (the left column), and “R parallel”, where you’ll solve for resistors when they’re in parallel (right column). List out each term separately including units with your first attempt at writing them down. Then go back through and try to simplify or rewrite these equations so they don’t have any variables.

2) Learn the basics-

It is important to understand the basics of equivalent resistance before you try to apply it. This includes understanding Ohm’s law ( V = IR ), series and parallel circuits, and how to solve for resistances in each scenario. Once you have a strong foundation, the concepts of equivalent resistance will be much easier to understand.

3) Practice-

Start practicing applying the equation to circuits! Try solving for resistances in a few simple series and parallel circuit problems. These are great examples of equivalent resistance because you can simply plug your numbers into the formula. If you’re feeling confident, try applying it to slightly harder circuits that have multiple branches or components connected in different ways.

4) It’s important not to be overwhelmed when practicing-

If you find yourself struggling with these equations, just take a step back and review what you know about the basics before moving forward again so these concepts don’t get too difficult all at once. When studying, make sure you understand why each step is happening rather than just memorizing everything without understanding how it works.

5) Gain practical knowledge-

It is important to gain practical knowledge along with the theory. This means working through examples and solving problems as you go. Not only will this help your understanding of the material, but it will also give you the skills you need to apply these concepts.

[Physics Class Notes] on Beat Frequency Formula Pdf for Exam

According to acoustics, a beat is an interference pattern between two sound waves of different sound frequencies or a periodical variation in volume. Here, both the waves should travel in the same direction.  The beat frequency is common in the tunning instruments, this will produce sustained beats, tones and they can readily be recognized. While tuning two tones to a unison will shows a peculiar effect. When the two sound waves, which are not identical are close in pitch will generate the beating. The volume of beats is varied like a tremolo as the sounds interfere are constructive and destructive.  When the tones gradually reach unison, the beats get slow down. If the two tones are separated, their beat frequency will approach the human pitch range perception. 

Beats are produced when the two waves of nearby frequencies are superimposed together. This will occurs when the two waves are travel in the same path. Beats also cause a periodic variation in the intensity of resultant waves.  The beat frequency is the no of beats formula produced per second. 

Beat Formula: fb =|f2−f1| 

f1 and f2 are the frequencies of the two waves. 

The value of beat frequency cannot be negative. 

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The above image shows the diagram of the beat frequency, constructive interference of beat frequency and destructive interference in beat frequency. 

Beat Frequency in Real Time 

Musicians will commonly use beats interference to check tuning at the perfect fifth, unison, or other simple harmonic intervals. Piano and organ tuners are also using this method to count beats, which are aiming to produce a particular number of specific intervals. 

Problems Based on Beat Frequency

Problem 1: Calculate the Beat Frequency if the Two Frequencies of Waves are 720Hz and 280 Hz Respectively?

Answer:

From the given data, lets consider the values of f1 and f2 as given below/ 

f2 = 700Hz and f1 = 300Hz

The formula for beat frequency 

fb = |f2−f1|

fb = |700−300|= 400Hz

Therefore, the beat frequency of the above given two waves is 400Hz. 

Problem 2: Derive the Beat Frequency of the Wave, with Frequencies are 650 Hz and 800 Hz Respectively?

Answer:

From the given data lets consider the values of f1 and f2 as given below. 

f1 = 650Hz and f2 = 800Hz

The beat frequency derivation (fb) 

 fb =|f2−f1|

fb= |800−650|= 150Hz

Therefore, the beat frequency of the above given two waves is 150Hz.