Category: Surveying Objective Questions

Surveying Multiple Choice Questions on “Photogrammetric Surveying – Aerial Camera”.

1. Both Terrestrial and aerial cameras are having the same functionality.
a) False
b) True
Answer: b
Clarification: The functionality of the terrestrial and aerial camera is the same i.e., capturing pictures. In case of aerial photogrammetry, aerial camera is mounted on top of moving aeroplane. It must satisfy the required inputs, which it must possess.

2. Which of the following doesn’t include in the lens?
a) Filter
b) Shutter
c) Diaphragm
d) Azimuth
Answer: d
Clarification: The lens which is used in aerial photogrammetry is having a certain combination. It consists of lens, diaphragm, shutter and the filter. Each one has its prominence in the process of aerial photogrammetry.

3. While using a large lens, which type of shutter is adopted?
a) Between-the –lens shutter
b) Louvre shutter
c) Focal plane shutter
d) Ideal shutter
Answer: b
Clarification: Shutter is the most important component which will capture the photographs. The number of photographs captured will depend on the shutter speed. These are of 3 types of which for the large lens, Louvre lens are adopted for high speed.

4. Which among the following specifies the use of diaphragm?
a) Adjusting focal plane
b) Managing azimuth
c) Adjusting horizon
d) Managing size of aperture
Answer: d
Clarification: Diaphragm is placed in the aerial camera in order to increase or decrease the size of the aperture. By doing this the light rays entering the camera can be controlled and the shutter speed can be controlled. If the diaphragm opening is larger, shutter speed will be high.

5. Which of the following is not an essential part of the aerial camera?
a) Shutter
b) Lens
c) Horizon
d) Magazine
Answer: c
Clarification: In general, an aerial camera consists of a lens, shutter, focal plane, magazine, drive mechanism. These are having their priorities of their own based on the time of usage. Shutter will play a prominent role while capturing the photographs.

6. Which among the following is placed in between lens elements?
a) Diaphragm
b) Lens
c) Line of sight
d) Magazine
Answer: a
Clarification: A diaphragm is placed between the lens elements. It can act as an opening of the lens. By rotating it can actually zoom the object which is been sighted and also decrease the size.

7. Filter consists of ________
a) piece of aperture
b) piece of hole
c) piece of glass
d) piece of lens
Answer: c
Clarification: Filter can be described as the piece of glass which can be placed in front of the lens. Due to the condition of the atmosphere, different filters can be adopted so that the readings can be taken exactly but not approximately.

8. Focal plane is provided at _____________
a) Point of resection
b) Point of intersection
c) Point of contraction
d) Point of collimation
Answer: b
Clarification: The provision of a focal plane is done at the point of collimation. These collimation marks are provided at the upper surface of the cone surface. It is suggested to place near nodal point.

9. Which of the following doesn’t come under drive mechanism?
a) Tripping the shutter
b) Operating vacuum system
c) Winding the film
d) Binding the film
Answer: d
Clarification: A drive mechanism is involved in the camera body and is used for tripping the shutter, operating vacuum system and winding the film. This can be done by manual operation or automatic operation.

10. Which of the following can hold the films of the focal plane?
a) Magazine
b) Convergence
c) Divergence
d) Intersection
Answer: a
Clarification: Magazine involves in holding the films and houses the film flattening device at the focal plane. It plays a major role in the drive mechanism, which can help in moving parts of the system.

Surveying Multiple Choice Questions on “GIS – Topology”.

1. Study of geometric objects will come under the category of ______________
a) Surveying
b) Cartography
c) Surface geometry
d) Topology
Answer: d
Clarification: Topology can be determined as the study of geometric objects that remain invariant under major circumstances which include bending and stretching. It can be able to determine the spatial relation between adjacent vector features.

2. Which type of data set is not used in GIS related software’s?
a) Vertex
b) Point
c) Poly line
d) polygon
Answer: a
Clarification: Data set plays a major role in the determination of the output developed in the GIS software. Point feature can be used for identification of certain area, poly line for identifying road network, pipe lines and polygon for two-dimensional features.

3. Among the available formats, which are most commonly used in case of GIS?
a) GIF
b) TIFF
c) JPEG
d) DXF
Answer: b
Clarification: TIFF format is the most commonly used format in case of GIS. It is because of the fact that most of the computers are equipped with this software and also it can be easily accessed with the help of GIS software. Other software might create any trouble, but this serve at its best.

4. The point data feature can be used to represent __________
a) Location
b) Area
c) 3D area
d) Volume
Answer: a
Clarification: The different data features like point, poly line and polygon can be used to identify different poly graphic features. Among them, the point is used to locate the feature of the object like location.

5. The polygonal data feature uses which of the following data format?
a) Scientific character
b) Math
c) Character
d) Integer
Answer: d
Clarification: The data formats which are generally used in case of GIS are integer, float, and text format. These are selected in the GIS software based on the type of work being carries out.

6. Which of the following justifies the usage of topology?
a) Terrain of the area
b) Geometry of the model
c) Climatic conditions
d) Atmospheric conditions
Answer: b
Clarification: The topology can be used for having an idea about the geometry of the model, how it can change from feature of the class on integration. This helps in the interpretation of the image.

7. Spatial relationship can be established by using GIS.
a) False
b) True
Answer: b
Clarification: The usage of GIS involves determining the spatial relationship between the object of our sight. This can be useful in data compilation and also in the analysis of the spatial relationship.

8. Which feature of GIS can share the boundary of the polygon?
a) Polygons
b) Poly lines
c) Dongle nodes
d) Silver polygons
Answer: a
Clarification: The polygons generated in the GIS software sometimes may share their boundary. This might lead to the creation of silver polygons. In this case, area feature of the polygon will be shared.

9. Which of the following indicate topological primitive?
a) Poly line
b) Point
c) Node
d) Polygon
Answer: c
Clarification: In GIS, topological primitives are used. Those include nodes, faces and edges. These are defined by representing the feature geometries in a planar graph of a topological element.

10. Which of the following acts as a key to GIS?
a) Topology
b) Platform
c) Software
d) Terrain
Answer: a
Clarification: Topology acts as a key to GIS, which can access every aspect of GIS. It is accompanied by some set of rules and determines the point, polygon and poly line features.

Surveying Multiple Choice Questions on “Flow Irrigation Survey”.

1. Which of the following is a classification of irrigation survey?
a) Direct method
b) Weir method
c) Notch method
d) River method
Answer: a
Clarification: Irrigation survey project can be classified into direct and indirect methods. Each of these classifications can be explained under certain sections. Both are applied in case of surface water schemes, sanitary water scheme etc.

2. The area that can be irrigated by a canal can be determined as ___________
a) Canal area
b) Paddy area
c) Irrigated area
d) Commanded area
Answer: d
Clarification: Commanded area is the area that can be irrigated by a canal system which can be either gross command area or culturable command area. The application of both of these depends upon the area that has to be irrigated.

3. Percentage of irrigation proposed to be irrigated annually yields ________
a) Density of irrigation
b) Intensity of irrigation
c) S.G of irrigation
d) Extent of irrigation
Answer: b
Clarification: Intensity of irrigation deals with the percentage of irrigation to be irrigated annually. In general, the area which has to be irrigated needs to be expressed in percentage of CCA which is able to represent the intensity of irrigation for the crop season.

4. Storage irrigation method is also known as __________
a) Weir method
b) Direct method
c) Indirect method
d) Notch method
Answer: c
Clarification: Indirect method or the storage irrigation method involves in the irrigation of excess water of a river during monsoon season. This is done to flow the excess water into the river which will be later filled in the reservoir or the tank.

5. Which of the following methods is adopted in case of the flow of excess water?
a) Weir method
b) Traverse irrigation method
c) Direct irrigation method
d) Storage irrigation method
Answer: d
Clarification: The usage of storage irrigation method is done in case of excess water scheme. This helps in storing the excess water in the upstream side of the dam which is constructed across the river, which is later adopted when flow of river is excess.

6. Which of the following indicates a storage structure?
a) Dam
b) Weir
c) Notch
d) Culvert
Answer: a
Clarification: A structure can be determined as a storage structure if it is having the ability to store excess water in case of floods. In general dams, spill ways and sluices are considered as the storage structures and also as appurtenant works.

7. Which of the following can be used as a diversion structure?
a) Dam
b) Barrage
c) Reservoir
d) Culvert
Answer: b
Clarification: A diversion structure involves the change in the direction of flow of stream or river, which can decrease the load or flow of water in a particular direction. Diversion structures generally include a barrage, a canal head and a river training head.

8. Which of the following can be indicated as the classification of the surface irrigation method?
a) Gradient method
b) Irrigation method
c) Flooding method
d) Drowning method
Answer: c
Clarification: Surface irrigation method generally involves flooding method in which water is allowed to cover the surface of the land in a continuous sheet of water which is sufficient to allow the field to absorb the water for increasing the field capacity.

9. A small basin is adopted in case of ____________
a) Sandy soil
b) Clay soil
c) Rocky soil
d) Metamorphic soil
Answer: a
Clarification: The usage of the basin not only depends upon slope but also on the type of soil it is placed. A small basin is adopted in case of steeper slope of the land, sandy soil, small stream size and small irrigation depth.

10. Flat land can adopt large basins.
a) False
b) True
Answer: b
Clarification: The usage of the large basin is done when the slope of the land is flat, presence of clay soil, large stream size, large depth of irrigation and in the presence of a mechanized field.

Surveying Multiple Choice Questions on “Definition”.

1. Determining the relative positions of points on above or beneath the surface of the earth by means of direct or indirect measurements of distance and direction and elevation is called as _________
a) Surveying
b) Levelling
c) Measuring
d) Contouring
Answer: a
Clarification: Surveying is defined as determining the relative positions of points above or beneath the surface of the earth by means of direct or indirect measurements of distance and direction and elevation.

2. Finding the elevations of a point with respect to a given or assumed and establish points given elevation or at different elevations with respect to given or assumed dactum is ________
a) Surveying
b) Levelling
c) Bearing
d) Contouring
Answer: b
Clarification: Finding the elevations of a point with respect to a given or assumed and establish points given elevation or at different elevations with respect to given or assumed dactum is levelling.

3. Type of surveying in which the mean surface of the earth is considered as a plane and the spheroidal shape is neglected called as ________
a) Topographic Surveying
b) Hydrographic Surveying
c) Geodetic Surveying
d) Plane Surveying
Answer: d
Clarification: Type of surveying in which the mean surface of the earth is considered as a plane and the spheroidal shape is neglected is plane surveying.

4. Type of surveying in which the shape of the earth taken into account is __________
a) Topographic Surveying
b) Hydrographic Surveying
c) Geodetic Surveying
d) Plane Surveying
Answer: c
Clarification: Type of surveying in which the shape of the earth taken into account is geodetic surveying. The survey which deals with bodies of water for purpose of navigation, water supply, harbor works or for the determination of mean sea level is hydrographic surveying.

5. Horizontal projection of an area and shows only horizontal distances of the points is __________
a) Contour lines
b) Levelling
c) Surveying
d) Plan
Answer: d
Clarification: Horizontal projection of an area and shows only horizontal distances of the points is plan or map. Finding the elevations of a point with respect to a given or assumed and establish points given elevation or at different elevations with respect to given or assumed dactum is levelling.

6. What type of surveys needs to fix the boundaries of municipalities and of state and federal jurisdictions?
a) Topographic Surveying
b) Hydrographic Surveying
c) Cadastral Surveying
d) City Surveying
Answer: c
Clarification: The surveys need to fix the boundaries of municipalities and of state and federal jurisdictions are cadastral surveying. Survey which deals with bodies of water for purpose of navigation, water supply, harbor works or for the determination of mean sea level is hydrographic surveying.

7. Determining the absolute location of any point or the absolute location and direction of any line on the surface of the earth is called _______
a) Topographic Surveying
b) Astronomical Surveying
c) Cadastral Surveying
d) Hydrographic Surveying
Answer: b
Clarification: Determining the absolute location of any point or the absolute location and direction of any line on the surface of the earth is astronomical surveying.

8. Determining different strata in the earth’s crust is called as_______
a) Mine Survey
b) Geological Survey
c) Geodetic Survey
d) Archaeological Survey
Answer: b
Clarification: Determining different strata in the earth’s crust is the Geological Survey. Type of surveying in which the shape of the earth taken into account is geodetic surveying.

9. Determining unearthing relics of antiquity is called as_______
a) Mine Survey
b) Geological Survey
c) Geodetic Survey
d) Archaeological Survey
Answer: d
Clarification: Determining the unearthing relics of antiquity is an archaeological survey. Determining different strata in the earth’s crust is the geological survey.

10. In which surveying, shape of earth is taken into consideration?
a) Plane surveying
b) Geodic surveying
c) Topographic surveying
d) Geological surveying
Answer: b
Clarification: In Geodic surveying, shape of the earth is considered for carrying out high precise work. In case of Plane surveying, spheroid shape is neglected and entire area is considered in the form of triangles. Topographic surveying consists of vertical and horizontal locations of points whereas Geological surveying determines earth’s strata.

11. Representing large scale on the surface of the earth is____________
a) Plan
b) Map
c) Scale
d) Area
Answer: a
Clarification: For any representation, if it consists large scale then it represents plan and for small scale it represents map.

12. Which of the following units measurement system is generally employed?
a) Centesimal system
b) Hours system
c) Minutes system
d) Sexagesimal system
Answer: d
Clarification: Since most surveying instruments are graduated according to this system, Sexagesimal system is widely used in India. Centesimal system is having a great approach in Europe for its adaptability in interpolation. Hours system is having its use in navigation.

13. The ratio of map distance to corresponding ground distance is called as__________
a) Representative factor
b) Representation factor
c) Reciprocating factor
d) Recurring factor
Answer: a
Clarification: This factor can be used for determining the ratio of map distance to ground distance which would be helpful for further calculations.

14. Which among the following scales is used to determine the original scale when the plan on the drawing sheet shrinks due to atmospheric conditions?
a) Vernier scale
b) Plane scale
c) Shrunk scale
d) Diagonal scale
Answer: c
Clarification: Shrunk scale is used to determine the original scale when any plan shrinks due to atmospheric conditions, which can be determined by a formula. By using the original scale further calculations can be done.

15. Which among the following methods is used for determining the precise position on the earth surface?
a) Geological surveying
b) Geodic surveying
c) Land surveying
d) Plane Surveying
Answer: b
Clarification: In Geodic surveying, spheroid surface of the earth is considered which might be possible for determining the precise position by avoiding any further assumptions.

16. Which among the following is one of the principles of surveying?
a) Taking measurements
b) Covering entire area
c) Determining the elevation differences
d) Working from whole to part
Answer: d
Clarification: By working from whole to part, it is possible to eliminate the errors and to localise the errors. Otherwise, it might expand in magnitude.

17. Design a vernier for a theodolite circle divided into degrees and one fourth degrees to read to 20ꞌꞌ.
a) 55
b) 45
c) 65
d) 35
Answer: b
Clarification: W.K.T, L.C = s/n
S = (1/4)˚= 15ꞌ and L.C=20ꞌꞌ=20/60 min.
So, 20/60 = 15/n
n = 45.

18. Horizontal angle measured clockwise from geographic meridian to the direction of progress of a line is known as _______
a) Horizontal meridian
b) Vertical meridian
c) Azimuth
d) Horizontal bearing
Answer: c
Clarification: Azimuth is the angle measured from geographic meridian which is quite different from bearing as it is measured w.r.t north direction.

19. The formula for shrunk scale can be given as___________
a) Original scale*shrinking factor
b) Shrunk scale*shrinking factor
c) Vernier scale* shrinking factor
d) Diagonal scale* shrinking factor
Answer: a
Clarification: The shrinkage factor obtained by the ratio of shrunk length to actual length multiplied by the original scale will give the shrunk scale formula.

Surveying Questions and Answers for Aptitude test on “Chain Surveying – Obstacles in Chaining”.

1. How many kinds of obstacles of chaining are there?
a) 2
b) 3
c) 4
d) 5
Answer: b
Clarification: Obstacles of chaining are of three kinds. They are obstacles to ranging, obstacles to chaining, obstacles to both chaining and ranging.

2. Which of the following is not one among the three major kinds of obstacles of chaining?
a) obstacles to ranging
b) obstacles to chaining
c) obstacles to levelling
d) obstacles to ranging and chaining
Answer: c
Clarification: Obstacles to levelling is not a kind of obstacles to chaining. Obstacles of chaining are of three kinds. They are obstacles to ranging, obstacles to chaining, obstacles to both chaining and ranging.

3. Both ends of the lines may be visible from intermediate points on the line. This case comes under which among the three kinds of obstacles to chaining?
a) obstacles to ranging but not chaining
b) obstacles to chaining but not ranging
c) obstacles to levelling
d) obstacles to ranging and chaining
Answer: a
Clarification: Obstacles to ranging but not ranging is a type of obstacle, in which the ends are not Intervisible, is quite expected in a flat country. There may be two cases of this obstacle, both ends of the lines may be visible from intermediate points on the line and both ends of the line may not be visible from intermediate points on the line.

4. When it is possible to chain round the obstacle, i.e a pond, hedge etc. This case comes under which among the three kinds of obstacles to chaining?
a) obstacles to ranging but not chaining
b) obstacles to chaining but not ranging
c) obstacles to levelling
d) obstacles to ranging and chaining
Answer: b
Clarification: There may be two cases of this obstacle i.e obstacle to chaining but not ranging, when it is possible to chain round the obstacle, i.e a pond, hedge etc and when it is not possible to chain round the obstacle e.g. a river.

5. Both ends of the line may not be visible from intermediate points on the line. This case comes under which among the three kinds of obstacles to chaining?
a) obstacles to ranging but not chaining
b) obstacles to chaining but not ranging
c) obstacles to levelling
d) obstacles to ranging and chaining
Answer: a
Clarification: There may be two cases of this obstacle, both ends of the lines may be visible from intermediate points on the line and both ends of the line may not be visible from intermediate points on the line.

6. When it is not possible to chain round the obstacle e.g. a river. This case comes under which among the three kinds of obstacles to chaining?
a) obstacles to ranging but not chaining
b) obstacles to chaining but not ranging
c) obstacles to levelling
d) obstacles to ranging and chaining
Answer: b
Clarification: There may be two cases of this obstacle i.e obstacle to chaining but not ranging, when it is possible to chain round the obstacle, i.e a pond, hedge etc and when it is not possible to chain round the obstacle e.g. a river.

7. To continue a survey line AB past an obstacle, a line BC 100 m long was set out perpendicular to AB and from C angles BCD and BCE were set out at 60° and 45° respectively. Determine the lengths which must be chained off along CD in order that ED may be in AB produced?
a) 100 m
b) 200 m
c) 300 m
d) 400 m
Answer: b
Clarification: Here angle ABC is 90°. From, ∆ BCD, CD = BC sec 60° = 100 × 2 = 200m.

8. To continue a survey line AB past an obstacle, a line BC 100 m long was set out perpendicular to AB and from C angles BCD and BCE were set out at 60° and 45° respectively. Determine the lengths which must be chained off along CE in order that ED may be in AB produced?
a) 141.42 m
b) 282.84 m
c) 140.14 m
d) 267.7 m
Answer: a
Clarification: Angle ABC is 90°. From ∆BCE, and CE = BC sec 45° = 100 × 1.4142 = 141.42 m.

9. To continue a survey line AB past an obstacle, a line BC 300 m long was set out perpendicular to AB and from C angles BCD and BCE were set out at 60° and 45° respectively. Determine the obstructed length BE?
a) 250 m
b) 600 m
c) 452.28 m
d) 300 m
Answer: d
Clarification: Here angle ABC is 90°. BE = BC tan 45° = 300 × 1 = 300 m.

10. If we select two points A and B on either side of the obstacle and equal perpendiculars AC and BD are set out. Then AB is equal to?
a) AC
b) CD
c) DA
d) BD
Answer: b
Clarification: Since AC and BD are two perpendiculars set either side of the obstacle of equal length. Therefore CD is parallel and equal to AB. Therefore, AB = CD.

To practice all areas of Surveying for Aptitude test,