250+ TOP MCQs on Terminated Two-Port Network and Answers

Network Theory Multiple Choice Questions on “Terminated Two-Port Network”.

1. Calculate the Z –parameter Z₁₁ in the circuit shown below.
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A. 1.5
B. 2.5
C. 3.5
D. 4.5

Answer: B
Clarification: The Z–parameter Z₁₁ is V₁/I₁, port 2 is open circuited. V₁ = (1+1.5)I₁ => V₁/I₁ = 2.5 and on substituting, we get Z₁₁ = 2.5Ω.

2. Determine the Z-parameter Z₁₂ in the circuit shown below.
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A. 1
B. 2
C. 3
D. 4

Answer: A
Clarification: The Z-parameter Z₁₂ is V₂/I₁ |I₂=0. On open circuiting port 2 we obtain the equation, V₁ = (1.5) I₂ => V₁/I₁ = 1.5. On substituting we get Z₁₂ = 1.5Ω.

3. Determine the Z-parameter Z₂₁ in the circuit shown below.

A. 4
B. 3
C. 2
D. 1

Answer: D
Clarification: The Z-parameter Z₂₁ is V₂/I₁ |I₂=0. On open circuiting port 2, we get V₂ = (1.5)I₁ => V₂/I₁ = 1.5. On substituting we get Z₂₁ = 1.5Ω.

4. Determine the Z-parameter Z₂₂ in the circuit shown below.
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A. 1
B. 3
C. 2
D. 4

Answer: C
Clarification: The Z-parameter Z₂₁ is V₂/I₂ |I₁=0. This parameter is obtained by open circuiting port 1. So we get V₂ = ((2+2)||4)I₂ => V₂ = 2(I₂) => V₂/I₂ = 2. On substituting Z₂₁ = 2Ω.

5. Find the value of V₁/I₁ in the circuit shown below.
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A. 1.25
B. 2.25
C. 3.25
D. 4.25

Answer: B
Clarification: We have the relation V₁/I₁=Z₁₁– Z₁₂Z₂₁/(Z_L+Z₂₁) and Z_L is the load impedance and is equal to 2Ω. On solving V₁/I₁=2.5-1/(2+2)=2.25Ω.

6. Determine the input impedance of the network shown below.

A. 4.25
B. 3.25
C. 2.25
D. 1.25

Answer: B
Clarification: From the figure by inspection we can say that the source resistance is 1Ω. So Z_in = (V₁/I₁) + Source resistance. We had V₁/I₁ = 2.25. On substituting Z_in=1+2.25=3.25Ω.

7. Determine the value of source admittance in the circuit shown below.

A. 1
B. 2
C. 3
D. 4

Answer: A
Clarification: From the figure, the value of the admittance parallel to the current source is 1 mho and this is the value of source admittance. So Y_s = 1 mho.

8. Find the value of I₂/V₂ in the circuit shown below.

A. 7/6
B. 6/7
C. 7/12
D. 12/7

Answer: C
Clarification: The relation between I₂/V₂ and Y-parameters is
I₂/V₂=(5/8×1+5/8×1/2-1/16)/(1+1/2)=7/12 mho.

9. The value of the Y-parameter Y₂₂ in the circuit shown below.
A. 12/7
B. 6/7
C. 7/6
D. 7/12

Answer: D
Clarification: The relation between Y₂₂ and I₂/V₂ is Y₂₂ = I₂/V₂. We have the relation I₂/V₂ = (Y₂₂Y_s+Y₂₂Y₁₁-Y₂₁Y₁₂)/(Y_s+Y₁₁). On substituting their values in the equation we get Y₂₂ = 7/12 mho.

10. The value of the Z-parameter Z₂₂ in the circuit shown below.
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A. 6/7
B. 7/12
C. 12/7
D. 7/6

Answer: C
Clarification: The Z-parameter Z₂₂ is inverse of the Y-parameter Y₂₂ i.e., Z₂₂ = 1/Y₂₂. We got Y₂₂ = 7/12. So on substituting we get Z₂₂ = 12/7 mho.