Mindtree Aptitude Placement Papers – Mindtree Aptitude Interview Questions with Answers

Question: 1. 8 Man Work For 6 Days To Complete A Work. What number of Men Are Required To Complete Same Work In 1/2 Day?
To finish a labor for 6 days, 8 men require

For complete a labor for 1 day = 6*8 = 48 men

For complete a work in a portion of a day(1/2) = 48*2 = 96 men.

Question: 2. Two Goats Are Tied With A Rope Of Length 40m Outside Of A Rectangular Shed Of Dimensions 50m X 30m. The Goats Are Tied To Different Corners Which Lie On The Opposite Ends Of A Diagonal Of The Shed. Wh
Given rope of length = 40m (sweep)

Area of semi circle =(pi*r^2)/2 = (1600 * pi)/2 = 800*pi – – – (1)

Area of quarter circle = (1/2 * 800 * pi) = 400*pi – – – – – (2)

Area of area is = r*r*(pi/2)/2 = 25*pi – – – – – (3)

By adding above eq. (1) (2) and (3)

Absolute region = 1225*pi

According to quesiton there are 2 goats

so region = 1225*pi*2 = 2450pi.

Question: 3. If A – B = 3 And A^2 + B^2 = 29, Find The Value Of Ab?
2ab = (a^2 + b^2) – (a – b)^2

= 29 – 9 = 20

abdominal muscle = 10.

Question: 4. A Man Employs 20 Men, 15 Women And X Children. He Pays Daily Wages Of Rs. 10 Per Men Rs. 8 Per Women And Rs. 4 Per Chil His Daily Average Wages Bill Works Out To Rs. 8.50 Per Person. What The Value Of
20*10 +15*8 +x*4/20+15+x = 8.5

x= 5 kid.

Question: 5. A Batsman Scored 110 Runs Which Included 3 Boundaries And 8 Sixes. What Percent Of His Total Score Did He Make By Running Between The Wickets?
Number of runs made by running = 110 – (3 * 4 + 8 * 6)

= 110 – (60) = 50.

Required rate = ({50/110}*100)% = 45{5/11}%.

Question: 6. If M=2-_/3 Find The Value Of: M^6+m^5+m^4+1)/m^3?
m = (2 – ?3)

=> 1/m = (2 + ?3)

(m^6+m^5+m^4+1)/m^3

= m^3 + m^2 + m + 1/m^3

= (m + 1/m)^3 – 3(m +1/m) + m(m+1)

= 4^3 – 3*4 + (2-?3)(3-?3)

= 64 – 12 + 9 – 5?3

= (61 – 5?3).

Question: 7. The Ratio Of The Ages Of Swati And Varun Is 2 : 5, After 8 Years, Their Ages Will Be In The Ratio Of 1 :
Let Swati’s age = 2X and Varun’s age = 5X

(2X + 8)/(5X + 8) = 1/2 => X = 8

Swati’s age = 16 years

what’s more, Varun’s age = 40 years

Contrast of their ages = 24 years.

Question: 8. The following Is A Pseudo Code Read X?
Given Last worth int seq. = 54.

what’s more, in each Loop result increased By 3.

So By Backward Approach

54/3=18 => 18/3=6

=> 6/3=2.

In this way, The Starting Value Is 2.

Question: 9. A, B, C And D Go For A Picnic. At the point when A Stands On A Weighing Machine, B Also Climbs On, And The Weight Shown Was 132 Kg. Whenever B Stands, C Also Climbs On, And The Machine Shows 130 Kg. Comparatively The Weig
A+B=132

B+C=130

C+D=102

B+D=116

A+2B+C=262

B+C+2D=218

A+B-2D=44

132-2D=44

D=44.

Question: 10. If M^2+m^-2=23;then What Is The Value Of M^3+m^-3?
m^2+m^-2=23

=> (m + m^-1)^2 – 2 = 23

=> (m + m^-1) = 5

m^3+m^-3 = (m + m^-1)^3 – 3(m + m^-1) = 5^3 – 3*5 = 110.

Question: 11. What Is The Simplified Result Of Following The Steps Below In Order?
X2-X-6=0

(x-3)(X+2)=0

X=3,- 2.

Question: 12. 1,40,00,000 Pencils Are Put Up Straight. Every one of the Pencils Are Of Length Range 3 To 6 Inches. 80% Of The Pencils Have Average Of Five Inches. So The Find Out The Total Length Spanned By The Pencils?
length covered by 80% of the pencils =80/100 * 14000000 * 5 = 56000000 inches

Least length covered by staying 20% of the pencils =20/100 * 14000000 * 3 = 8400000 inches

Greatest length covered by staying 20% of the pencils =20/100 * 14000000 * 6 = 16800000 inches

Thus, complete length spread over by the pencils is (56000000 +8400000) to (56000000 +16800000 )

ie, 64400000 crawls to 72800000 inches.

Question: 13. A Survey Of A Village Showed That 1/10 Of The Total Population Speak Neither Hindi Nor English. 1/5 Of Them Cannot Speak English And 3/7 Of Them Cannot Speak Hindi. Which Percentages Of People Kn
people who can communicate in English = 1 – (1/5) = 4/5

people who can communicate in Hindi = 1 – (3/7) = 4/7

people who can talk any or both = 1 – 1/10 = 9/10

so all out people talk both = 4/5 + 4/7 – 9/10 = 33/70

people talk any = 1 – 33/70 – 1/10 = 3/7

% = 300/7% = 42.86%.

Question: 14. The Letter Of The Word Labor Are Permuted In All Possible Ways And The Words Thus Formed Are Arranged As In A Dictionary. What Is The Rank Of The Word Labor?
The request for each letter in the word reference is ABLORU.

Presently, with A first and foremost, the excess letters can be permuted in 5! ways.

Essentially, with B initially, the excess letters can be permuted in 5! ways.

With L initially, the primary word will be LABORU, the subsequent will be Labor.

Subsequently, the position of the word Labor is 5!+5!+2 =242.

Question: 15. When A Square Of An Odd Number Is Divided By 8?
We should call the odd number 2a+1, where an is a whole number.

Then, at that point (2a+1)^2 = 4a^2 + 4a + 1 = 4a(a+1) + 1.

Since an is odd, a+1 is even.

Thus, 4a(a+1) must be a different of 8

In this manner 4a(a+1) + 1 should leave a rest of 1 when isolated by 8.

Question: 16. A Father Is 30 Years Older Than His Son However He Will Be Only Thrice As Old As The Son After 5 Years What Is Father’s Present Age ?
Lets expect child’s age = x

Thus, father’s age = x + 30

Following 5 years:

Child’s age = x + 5

Father’s age = x + 35

In 5 years the dad is threefold basically as old as his child so:

3(x + 5) = x + 35

x = 10

In this way, current dad’s age = 40 Years.

Question: 17. In the event that Each Of The Three Nonzero Numbers A , B , And C Is Divisible By 3, Then Abc Must Be Divisible By Which One Of The Following The Number?
Since every single one of the three numbers a, b, and c is separable by 3, the numbers can be addressed as 3p,3q, and 3r, individually, where p, q, and r are numbers.

The result of the three numbers is 3p*3q*3r =27(pqr).

Since p, q, and r are numbers, pqr is a number and in this manner abc is detachable by 27.

Question: 18. Holders Labeled An And B Are Filled With Red And Blue Marbles In Given Quantities: – compartment Red Blue?
In the event that any one pick holder A, prob = (1/2)*(4/10)=1/5

In the event that any one pick compartment A, prob = (1/2)*(40/100)=1/5.

Question: 19. A Cylinder Is 6 Cms In Diameter And 6 Cms In Height. On the off chance that Spheres Of The Same Size Are Made From The Material Obtained, What Is The Diameter Of Each Sphere?
The volume of the chamber is Pi x r^2 x h = Pi x 3^2 x 6 = 54Pi

Volume of a chamber is 4/3 x Pi x r^3

Presently 54Pi = 12 x 4/3 x Pi x r^3

54 = 16 x r^3

r^3 = 54/16 = 27/8

r = 3/2

In this manner distance across is 3 cms.

Question: 20. What number of Ways Can 360 Be Written As Product Of Two Numbers?
1*360, 2*180, 3*120, 4*90, 5*72, 6*60, 8*45, 9*40, 10*36, 12*30, 15*24, 18*20

SOL 2) 360 => 2^3 * 3^2 * 5^1 [i.e. a^x * b^y * c^z)

No. of ways can be composed as a nudge of 2 no’s is

(x+1)*(y+1)(z+1)/2

=> (3+1)*(2+1)*(1+1)/2

=> 24/2 = 12.

Question: 21. Two Students Appeared At An Examination. One Of Them Secured 9 Marks More Than The Other And His Marks Was 56% Of The Sum Of Their Marks. The Marks Obtained By Them Are?
Leave their imprints alone (x + 9) and x.

Then, at that point, x + 9 = (56/100)(x + 9 + x)

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

Along these lines, their imprints are 42 and 33.

Question: 22. A Person Travels In A Car With Uniform Speed. He Observes The Milestone,which Has 2 Digits. Following One Hour He Observes Another Milestone With Same Digits Reversed. After Another Hour He Observes Anoth
Let 10’splace digit is x and unit’s place digit y

First achievement : 10x+y

Second achievement : 10y+x

Third achievement: 100x+y

Since the speed is uniform so

Distance canvassed in first Hr = Distance shrouded in Second Hr

(10y+x)- (10x+y) = (100x+y)- (10y+x)

By addressing,

y=6x

however, since x and y are digits so just conceivable mix is x=1 and y=6,

So normal speed = 45 Kmph.

Question: 23. A Class Photograph Has To Be Taken. The Front Row Consists Of 6 Girls Who Are Sitting. 20 Boys Are Standing Behin The Two Corner Positions Are Reserved For The 2 Tallest Boys. In How Many Ways Can The
Two tallest young men can be sorted out in 2! ways, rest 18 can be set up in 18! ways.

Young ladies can be sorted out in 6! ways.

All out number of manners by which every one of the understudies can be set up = 2! * 18! * 6! = 18! *1440.

Question: 24. In A Society Of 80 Resident Families Who Subscribe Newspapers, 60% Of Them Subscribe The Hindu Newspaper, 80% Of Them Subscribe Regional Language Newspaper And 70% Of Them Subscribe Toi. The number of Fami
All out no. of families who take newspaper=80

Hindu paper = 60% = (80*60/100) = 48

Local paper = 80% = (80*80/100) = 64

TOI paper = 70% = (70*80/100) = 56

Find normal families take H.C.F (48,64,56) = 8

Therefore,(8/80)*100=10%

In this way, normal families who take all paper = 10%.

Question: 25. On the off chance that Log 0.317=0.3332 And Log 0.318=0.3364, Find Log 0.319 ?
log 0.317=0.3332 and log 0.318=0.3364

then, at that point,

log 0.319=log0.318+(log0.318-log0.317)

=0.3396.

Question: 26. A Works Thrice As Much As B. On the off chance that A Takes 60 Days Less Than B To Do A Work, Find The Number Of Days It Would Take To Complete The Work If Both Work Together?
Given A works instant as much as B

So the proportion among An and B = 3:1

so 3x-x=60

also, x = 30

so 1/90+1/30=221/2 days.