[Physics Class Notes] on Heat Capacity Formula Pdf for Exam

When the heat is absorbed by a body, its temperature increases, and when the body discharges or loses heat, its temperature falls. The heat capacity is the heat needed for raising the temperature of an object by a calculation of one degree. It can also be calculated as a ratio of the amount of heat energy that is given to the object for the resulting increase in the temperature. The expression for the heat capacity is [c = frac{{Delta Q}}{{Delta T}}].

 

Here, ΔQ is the amount of heat that is transferred, ΔT is the increase in temperature. 

There is an equal fall in temperature when the body loses the same quantity of heat. In SI units, the heat capacity can be expressed by joule per kelvin, (J/K). In the heat capacity, the body mass can have any value, which is not specified, such as unit mass etc.

An Example of the Heat Capacity

When 6400 J of heat is supplied to the body and it raises its temperature by approximately 100 degrees, then what is its heat capacity?

Solution: [Delta Q = 6400,J,,,,Delta T = 100^circ ,,,,c = ?]

Heat capacity; c [c = frac{{Delta Q}}{{Delta T}} = frac{{6400}}{{100}} = 64,J/K,,].

Practice Questions

If you want to check out the different practice questions and their solutions, you can refer to the notes on heat capacity formulas. Here you will find a wide comprehensive explanation of the concept, a wide range of examples, and an array of practice questions with solutions including multi choice questions. The solved practice questions can help you gain an understanding of the different types of questions that are likely to be asked in the exams and the process of solving them. Referring to these notes can help you prepare thoroughly for your exams.

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