[Physics Class Notes] on Value of g Pdf for Exam

Value of g in fps

The acceleration felt by a free-falling object due to the gravitational force of the mass body is called gravitational acceleration and is expressed by g calculated using SI unit m/s². The value of g depends on the mass of the body and its size, and its value varies from body to body. The value of g on the moon is constant. 

Acceleration Due to the Gravity of the Moon

The acceleration due to the gravity of the moon or the magnitude of g on the moon is 1,625 m/s². 

Calculate the acceleration due to the gravity of the moon 

The acceleration due to the formula of gravity is indicated by

G = GM / R²

Where,

• G is the universal gravitational constant, G = 6.674 x 10^-11 m³ kg^-1 s^-2. 

• M is the mass of the body measured using kg. 

• R is the mass body radius measured by m. 

• g is the acceleration due to the gravity determined by m/s².

The mass of the moon is  7.35 × 10²²Kg.

The radius of the moon is 1.74×10⁶m

Substituting the values in the formula we get-

g= 6.67×10⁻¹¹ × 7.35 × 10²² / (1.74×10⁶)²

Thus, the value of g on the moon is g=1.625m/s².

The Acceleration Due to Gravity also Follows the Unit of Acceleration 

Newton’s Law of Gravitation as applied to the Earth is F = G m M / r², where F is the gravitational force acting on the body of mass m, G is the universal gravitational constant, M is the mass of the Moon, and r is the distance of the body from the centre of the Sun. g is the factor in equation F = m g, so g is given as follows:

g = G M / r²

Both G and M are empiric constants, and g has an inverse-square relationship to r, the distance from the centre of the earth’s mass. 

There are two consequences of this: 

• Since the Earth is an ellipsoid, the distance from the centre of a point on the surface decreases with the latitude, increasing g. 

• The rotation of the planet creates an anti-gravity centrifugal effect, which is at the highest at the equator and zero at the poles.

These two effects are conspiring to generate a g rise in latitude. Their magnitudes are easily determined by simple geometry. 

The effect of latitude is calculated on the basis of the standard surface of the geoid, which is the spheroid at sea level. Points above sea level are progressively further away from the centre of the earth, so g decreases with altitude in a predictable manner. 

In practice, the value of g varies somewhat from the geometrically predicted value to latitude and altitude. Positive variation is caused by the following:

The components of the structure of the Earth have a variety of densities. The geometric model of gravity conceives the Earth as a collection of onion-skin layers, each with a uniform density (and this is almost the case). Each individual sheet, because of its uniform density, has its centre of mass corresponding to that of the Earth. Nonetheless, if the layer has a small patch of higher density material, the centre of the mass is shifted towards the patch, decreasing r, and thereby increasing g.

The Table Below Shows the Value of g at Various Locations from Earth’s Centre.

As can be seen from both the equation and table above, the value of g varies inversely with the distance from the centre of the earth. In fact, the variation in g with distance follows an inverse square law, where g is inversely proportional to the distance from the centre of the earth. This inverse square equation means that, if the gap is doubled, the value of g decreases by a factor of 4. As the distance is tripled, the value of g is reduced by a factor of 9. And so on, too. This inverse square relationship is shown in the right-hand graphic.

The value of G that is gravitation is the most basic concept taught in science classes. Students learn about gravitation in earlier classes starting from sixth grade.

This article explains in-depth about the value of G inFPS, acceleration due to the gravity of the moon, the acceleration due to gravity also follows the unit of acceleration, lays out the value of G at various locations from Earth Centre. It is a very informative article and students who want to get a good score and want to get a clear understanding of the concept of the value of G should definitely read and learn this article in depth.

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More on Gravity

We all know that gravity is an invisible pulling force that pulls things towards the object’s centre. The gravitational force is studied as inherently linked to Mass. we all know that there is a gravitational force of attraction that is present in between every object. The gravitational force is proportional to the mass of the object and as the distance increases between them, the force weakens. Both the objects keep exerting an equal and attractive force on each other. A falling object attracts the earth with the same force as the earth attracts it.

The acceleration due to gravity on earth is also known as the value of g on earth is 9.8 m/s2. This indicates that if an object is falling freely, the velocity of that object will keep increasing by 9.8 every second.

The acceleration due to gravity on the moon, also known as the magnitude of g on the moon, is 1,625 m / s2. The formula of gravity is indicated by G = GM / R². The mass of the moon is 7.35 × 10²²Kg.

The radius of the moon is 1.74×10⁶m

Substituting the values in the formula we get-

g= 6.67×10⁻¹¹ × 7.35 × 10²² / (1.74×10⁶)²

Thus, the value of g on the moon is g=1.625m/s².