MCQs on Class 9 Quadrilaterals
1) The quadrilateral whose all its sides are equal and angles are equal to 90 degrees, it is called:
a. Rectangle
b. Square
c. Kite
d. Parallelogram
Answer: b
2) The sum of all the angles of a quadrilateral is equal to:
a. 180°
b. 270°
c. 360°
d. 90°
Answer: c
3) A trapezium has:
a. One pair of opposite sides parallel
b. Two pair of opposite sides parallel to each other
c. All its sides are equal
d. All angles are equal
Answer: a
Explanation: A trapezium has only one pair of opposite sides parallel to each other, and the other two sides are non-parallel.
4) A rhombus can be a:
a. Parallelogram
b. Trapezium
c. Kite
d. Square
Answer: d
5) A diagonal of a parallelogram divides it into two congruent:
a. Square
b. Parallelogram
c. Triangles
d. Rectangle
Answer: c
6) In a parallelogram, opposite angles are:
a. Equal
b. Unequal
c. Cannot be determined
d. None of the above
Answer: a
7) The diagonals of a parallelogram:
a. Equal
b. Unequal
c. Bisect each other
d. Have no relation
Answer: c
Explanation: The diagonals of a parallelogram intersect each other at 90 degrees.
8) Each angle of the rectangle is:
a. More than 90°
b. Less than 90°
c. Equal to 90°
d. Equal to 45°
Answer: c
Explanation: Let ABCD is a rectangle, and ∠A = 90°
AD || BC and AB is a transversal
∠ A + ∠ B = 180° (Interior angles on the same side of the transversal)
∠ A = 90°
So, ∠ B = 180° – ∠ A = 180° – 90° = 90°
Now, ∠ C = ∠ A and ∠ D = ∠ B (Opposite angles of the parallelogram)
So, ∠ C = 90° and ∠ D = 90°
Hence all sides are equals to 90°.
9) The angles of a quadrilateral are in the ratio 4: 5: 10: 11. The angles are:
a. 36°, 60°, 108°, 156°
b. 48°, 60°, 120°, 132°
c. 52°, 60°, 122°, 126°
d. 60°, 60°, 120°, 120°
Answer: b
Explanation: Let x be the common angle among all the four angles of a quadrilateral.
As per angle sum property, we know:
4x+5x+10x+11x = 360°
30x = 360°
x = 12°
Hence, angles are
4x = 4 (12) = 48°
5x = 5 (12) = 60°
10x = 10 (12) = 120°
11x = 11 (12) = 132°
10) If ABCD is a trapezium in which AB || CD and AD = BC, then:
a. ∠A = ∠B
b. ∠A > ∠B
c. ∠A < ∠B
d. None of the above
Answer: a
Explanation: Draw a line through C parallel to DA intersecting AB produced at E.
CE = AD (Opposite sides)
AD = BC (Given)
BC = CE
⇒ ∠CBE = ∠CEB
also,
∠A + ∠CBE = 180° (Angles on the same side of transversal and ∠CBE = ∠CEB)
∠B + ∠CBE = 180° ( As Linear pair)
⇒ ∠A = ∠B