250+ TOP MCQs on System Classification and Properties – 2 and Answers

Signals & Systems Interview Questions on “System Classification and Properties – 2”.

1. Amplifiers, motors, filters etc. are examples for which type of system?
A. Distributed parameter systems
B. Unstable systems
C. Discrete time systems
D. Continuous time systems

Answer: D
Clarification: Amplifiers, motors, filters etc. are examples of continuous time systems as these systems operate on a continuous time input signal and produce a continuous time output signal. Whereas discrete time systems operate on discrete time signals, distributed parameter systems have signals which are functions of space as well as time and unstable systems produce unbounded output from bounded or unbounded input.

2. Which among the following systems are described by partial differential functions?
A. Causal Systems and Dynamic systems
B. Distributed parameter systems and linear systems
C. Distributed parameter systems and Dynamic systems
D. Causal systems and linear systems

Answer: C
Clarification: In distributed parameter systems, signals are functions of space as well as time. In dynamic systems the output depends on past, present and future values of input, hence, both of these systems are described by differential functions.

3. Which one of the following systems is causal?
A. y(t)=x(t)+x(t-3)+x(t²)
B. y(n)=x(n+2)
C. y(t)=x(t-1)+x(t-2)
D. y(n)=x(2n²)

Answer: C
Clarification: A causal system is one in which the output depends on the present or past values of the input, not future. If it depends on future values then it is non-causal. For y(t)=x(t)+x(t-3)+x(t²), y(n)=x(n+2), and y(n)=x(2n²), the output depends on future values i.e., x (t²), x (n + 2) and x (2n²) respectively. Whereas in y(t)=x(t-1)+x(t-2), the output y(t) depends on past values only i.e., x(t – 1) and x(t – 2).

4. Which among the following is not a linear system?
Answer: A

6. Which one of the following is an example of a bounded signal?
A. e^t coswt
B. e^t sinw(-t)
C. e^-t coswt
D. e^t cosw(-t)

Answer: C
Clarification: A bounded signal is the one which satisfies the condition |x(t)|< M < ∞ for all t.
Clearly, the signals e^t coswt, e^t sinw(-t) and e^t cosw(-t) are exponentially growing signals as the power of the function is positive i.e., the signals will grow beyond infinity. Whereas the signal e^-t coswt is an exponentially decaying signal, hence it will decay to zero and will always be less than infinity. Therefore, it is bounded.

7. A system produces zero output for one input and same gives the same output for several other inputs. What is the system called?
A. Non – invertible System
B. Invertible system
C. Non – causal system
D. Causal system

Answer: A
Clarification: A system is said to be invertible if the input fed to the system can be retrieved from the output of the system. Otherwise the system is non-invertible. Also, if a system gives zero output for any input and gives the same output for many inputs, then the system is non-invertible.

8. Which among the following is a LTI system?
A. dy(t)/dt+ty(t)=x(t)
B. y(t)=x(t)cosπt
C. y(n)=x(n)+nx(n-1)
D. y(n)=x³ (n+1)

Answer: D
Clarification: A system is said to be linear time invariant (LTI) if the input-output characteristics do not change with time.
This expression has a coefficient which is a function of time. ∴ the system is time variant.
Output when input is delayed by T, y(t,T)=x(t-T)cosπt
If the output is delayed by T, y(t-T)=x(t-T)cosπ(t-T)
Clearly, both expressions are not equal ∴ The system is time variant.
Output when input is delayed by N, y(n,N)=x(n-N)+nx(n-1-N)
If the output is delayed by N, y(n-N)=x(n-N)+(n-N)x(n-1-N)
Clearly, both expressions are not equal ∴ The system is time variant.
Output when input is delayed by N, y(n,N)=x³ (n+1-N)
If the output is delayed by N, y(n-N)= x³ (n+1-N)
Clearly, both expressions are equal. ∴ The system is time invariant.