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PHP Technical Interview Questions & Answers on “Variables – 2”.
1. What will be the output of the following PHP code?
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one = 1;
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two = 2;
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three = 3;
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four = 4;
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echo "one / two + three / four";
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?>
a) 0.75
b) 0.05
c) 1.25
d) Error
Answer: d
Clarification: Variables should start with a $ symbol, since one, two, three, four don’t begin with $ symbol we’ll get an error.
2. What will be the output of the following PHP code?
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$on$e = 1;
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$tw$o = 2;
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$thre$e = 3;
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$fou$r = 4;
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echo "$on$e / $tw$o + $thre$e / $fou$r";
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?>
a) 0.75
b) 0.05
c) 1.25
d) Error
Answer: d
Clarification: You can not use the $ in between the variable name.
3. What will be the output of the following PHP code?
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$on_e = 1;
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$tw_o = 2;
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$thre_e = 3;
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$fou_r = 4;
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echo $on_e / $tw_o + $thre_e / $fou_r;
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?>
a) 0.75
b) 0.05
c) 1.25
d) Error
Answer: c
Clarification: You can use _ in a variable name.
4. What will be the output of the following PHP code?
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$On_e = 1;
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$tw_o = 2;
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$thre_e = 3;
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$fou_r = 4;
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echo $on_e / $tw_o + $thre_e / $fou_r;
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?>
a) 0.75
b) 0.05
c) 1.25
d) Error
Answer: a
Clarification: Since the variable initialised is $On_e and the variable in the echo statement is $on_e the echo statement treats $on_e as 0;
5. What will be the output of the following PHP code?
a) 0
b) Nothing
c) True
d) Error
Answer: b
Clarification: There will no output returned as the variable $red does not hold any value.
6. What will be the output of the following PHP code?
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$four4 = 4;
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$three3 = 3;
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$two2 = 2;
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echo $four4 + $three3 / $two2 - 1;
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?>
a) 4.5
b) 7
c) 3.5
d) Error
Answer: a
Clarification: You can use numbers in a variable name.
7. What will be the output of the following PHP code?
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$4four = 4;
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$3three = 3;
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$2two = 2;
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echo $4four + $3three / $2two - 1;
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?>
a) 4.5
b) 7
c) 3.5
d) Error
Answer: d
Clarification: A variable name can not start with a numeric value.
8. What will be the output of the following PHP code?
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int $one = 1;
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echo "$one";
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?>
a) 0
b) 1
c) $one
d) Error
Answer: d
Clarification: Unlike other programming languages there are no data types in PHP.
9. What will be the output of the following PHP code?
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var $one = 1;
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var $two = 2;
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echo $one / $two * $one / $two * $two;
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?>
a) 1
b) 0
c) 0.5
d) Error
Answer: d
Clarification: You can not use var before a variable name.
10. What will be the output of the following PHP code?
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$hello = "Hello World";
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$bye = "Bye";
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echo $hello;"$bye";
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?>
a) Hello World
b) Bye
c) Hello worldBye
d) Error
Answer: a
Clarification: Since there is a semi-colon in between $hello and $bye, the line ends at $hello. However $bye would have printed if a echo was present before “$bye”.
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