Environmental Engineering Multiple Choice Questions on “Filtration Hydraulics”.
1. The head loss through the bed of solids of the filter can be determined by __________
a) Carmen-Kozney equation
b) Rose equation
c) Carmen-Kozney and Rose equation
d) Charles equation
Answer: c
Clarification: The head loss through the bed of solids of the filter can be determined by both Carmen-Kozney and Rose equation where two cases are considered, one for homogeneous mixed bed and other for stratified bed.
2. Which of the following has the highest shape factor as stated by Carmen?
a) Ottawa sand
b) Pulverized coal
c) Rounded coal
d) Angular sand
Answer: a
Clarification: The shape factor as stated by Carmen is 0.95 for Ottawa sand, 0.73 for pulverized coal and angular sand and 0.82 for rounded sand.
3. Which of the following is the expression of the Carmen equation where symbols have their usual meanings?
a) hf = f* (L/(s *d)) * ((1-e)/e3) * (v2/g)
b) hf = f* (L/(s *d)) * ((1-e)/e3) * (v/g)
c) hf = f* (L/(s *d)) * ((1-e)/e) * (v2/g)
d) hf = f* (L/(s *d)) * ((1-e)/e2) * (v2/g)
Answer: a
Clarification: The expression of the Carmen equation is given by hf = f* (L/(s *d)) * ((1-e) /e3) * (v2/g) where hf =head loss, d= diameter of pipe. L= length of pipe and v=approach velocity.
4. Which of the following represents the correct relation between dimensionless friction factor f and Reynolds number?
a) f = 150* ((1-e) /R2) + 1.75
b) f = 150* ((1-e) /R) +1.75
c) f = 150* ((1-e) /R3) + 1.75
d) f = 150* ((1-e2) /R) + 1.75
Answer: b
Clarification: The correct relation between dimensionless friction factor and Reynolds number is given by f = 150* ((1-e) /R) + 1.75 Where R is the Reynolds number and the expression (1-e) represents the volume of solids.
5. Which of the following is the expression of the Rose equation where symbols have their usual meanings?
a) hf = f* (L/(s *d)) * ((1-e) /e3) * (v2/g)
b) hf = f* (L/(s *d)) * ((1-e) /e3) * (v/g)
c) hf = f* (L/(s *d)) * ((1-e) /e4) * (v2/g)
d) hf = f* (L/(s *d)) * ((1-e) /e2) * (v2/g)
Answer: a
Clarification: The expression of the Rose equation is given by hf = f* (L/(s *d)) * ((1-e4) /e3) * (v2/g) where hf = head loss, d = diameter of pipe. L = length of pipe and v=approach velocity and f = 1.067CD, Where CD is the coefficient of drag.
6. When the Reynolds number is greater than 1.9 but less than 500, the coefficient of drag CD is?
a) CD = 24/R
b) CD = R/24
c) CD = 18.5/R0.6
d) CD = R0.6/18.5
Answer: c
Clarification: When the Reynolds number is greater than 1.9 but less than 500, the coefficient of drag CD is CD = 18.5/R0.6 where R is the Reynolds number.
7. The value of Reynolds number R is 1.5. The coefficient of drag is?
a) 8
b) 10
c) 12
d) 16
Answer: d
Clarification: When R<1.9, the value of the coefficient of drag = 24/R
R=1.5, the coefficient of drag = 24/1.5 = 16.
8. Rose equation is valid for beds in which voids are clear and unobstructed.
a) True
b) False
