Analog Communications Questions and Answers for Entrance exams focuses on “Generation of AM Using Amplifiers”.
1. Consider a wave, v = 15 sin (3πt + 5sin1300t), what is the carrier and signal frequency?
a) 2.5Hz and 200Hz
b) 1.5Hz and 100Hz
c) 1.5Hz and 207Hz
d) 5.5Hz and 500Hz
Clarification: Comparing with the general FM equation,
FM(t) = Ac sin(2πfct + βsin(2πfmt)),
Signal and Carrier frequency are respectively
2. SWR is 1 for ________
a) Open or Short Circuit
b) Open circuit only
c) Short circuit only
d) Series or Parallel Circuit
Clarification: Standing Wave Ratio (SWR) is defined as the ratio of the maximum radio-frequency (RF) voltage to the minimum RF voltage along the line. If the line is open or short circuited, SWR is always 1.
3. The resonance frequency of an amplifier is 7MHz and it is having a bandwidth of 10KHz. What is its Q factor?
Clarification: Q factor = Frequency/Bandwidth
= 7MHz/10KHz = 700.
4. Which chart is used for calculations of transmission lines?
a) Andre chart
b) Smith chart
c) Wilson chart
d) Federer chart
Clarification: Smith chart is highly used in radio frequency engineering. Because it is highly useful in solving problems related with transmission lines and matching circuits. It is highly useful for displaying multiple parameters like impedance, admittance etc simultaneously.
5. What is the effective power if the transmitted power of 5W is increased to 50dB?
Clarification: According to given problem, 10log10 (P/Pt) = 50,
10log10 (P/5) = 50.
So, P = 500KW.
Where, P = Effective Power, Pt = Transmitted Power.
6. Field intensity follows ________
a) Bragg’s law
b) Inverse square law
c) Coulomb’s law
d) Gauss’s law
Clarification: Strength of an electric field due to a charge Q is inversely proportional to the square of the distance from the source. In electrostatics, inverse square law is also known as Coulomb’s Law.
7. If the power density at a given distance ‘R’ is one microwatt per square meter and the effective area of antenna is one square meter then the power captured by antenna is one microwatt.
Clarification: The above statement is true because power density is equal to
Power Density = 1 mW
Pt = Power captured by antenna,
Area of antenna = 4πR2 = 1m2.