Genetic Engineering Multiple Choice Questions on “Transformation and Hosts”.
1. How will we choose which transformation method is to be used?
a) It depends on the available conditions for the reaction to take place
b) It depends on the efficiency which is required to be obtained
c) All the transformation methods can be used equivalently
d) Each reaction has been assigned a particular transformation method
Answer: b
Explanation: The choice of transformation method to be used is based upon the efficiency which is desired in the reaction which has to take place.
2. The cell in which the recombinant molecules are propagated is termed as __________
a) host
b) vector
c) plasmid
d) carrier
Answer: a
Explanation: Hosts are the cells which are used for propagation of recombinant molecules. The choice of a correct host is very important.
3. Some mutations are present which assist the uptake of DNA. Which of the statement is incorrect for it?
a) deoR is such a mutation which assists the uptake of DNA
b) It is a transcriptional regulator
c) It is having DNA binding activity
d) It controls the expression of a set of genes involved ribonucleoside catabolism
Answer: d
Explanation: There are various factors which affect the uptake of DNA by the cells. deoR is an example of such a mutation which assists the uptake of DNA. It is a transcriptional regulator and is having DNA binding activity. It controls the expression of a set of genes involved in deoxyribonucleoside catabolism.
4. Endogenous DNA-degrading system is not essential in determining transformation efficiency.
a) True
b) False
Answer: b
Explanation: Endogenous DNA-degrading system is essential in determining the transformation efficiency.
5. Which of the following is true for K strain for E. coli?
a) It contains restriction-modification system which is encoded by hsDMRS locus
b) hsDR encodes for endonuclease which is responsible for cleaving the DNA sequence containing –AACGCNNTGC-
c) Cleavage is carried out when the second A is non methylated
d) hsDR mutation can be used for cleavage of incoming unprotected DNA
Answer: a
Explanation: It consists of K restriction-modification system which is encoded by hsDMRS locus. hsDR encodes for endonuclease which is responsible for cleaving the DNA sequencing containing –AACNNNNNNGTGC-. Cleavage takes place only in the case when the second A and the A opposite to T in the second strand is methylated. This mutation can be used to avoid cleavage of incoming unprotected DNA.
6. Methylation dependent restriction system (MDRS) are included in which class of restriction enzymes?
a) Type I
b) Type II
c) Type III
d) They are the product of mcrA, mcrB or mrr loci
Answer: d
Explanation: MDRS don’t come under the general classification of type I-III. They are the product of mcrA, mcrB and mrr loci. It would degrade DNA containing methylcytosine (mcrA, mcrB) or methyladenine (mrr).
7. Choose the incorrect statement with respect to dam and dcm genes?
a) Their enzymes are responsible for methylation of DNA
b) Dam protein methylates cytosine in –GATC-
c) Dcm methylates cytosine in-CCAGG- and –CCTGG- sequences
d) The extent of methylation also has effects on the efficiency with which the other restriction enzymes cleave the DNA in vitro
