[CLASS 8] Mathematics MCQs on Mensuration – Area of Trapezium – 1

Mathematics Multiple Choice Questions & Answers on “Mensuration – Area of Trapezium”.

1. Find the area of the given rectangle.

a) 16 cm²
b) 100 cm²
c) 625 cm²
d) 50 cm²
Answer: b
Clarification: Area of rectangle = l × b = 25 × 4 = 100 cm².

2. Calculate the area of the given figure.

a) 150cm²
b) 125cm²
c) 225cm²
d) 100cm²
Answer: c
Clarification: Area of square = (s)² = (15)² = 225cm².

3. Find the area of the given figure.

a) 20cm²
b) 50cm²
c) 15cm²
d) 25cm²
Answer: d
Clarification: Area of triangle = (frac{1}{2}) × b × h = (frac{1}{2}) × 10 × 5 = 25cm².

4. What is the area of the given circle? (π = 3.14)

a) 78.5cm²
b) 78cm²
c) 76.5cm²
d) 77cm²
Answer: a
Clarification: Area of circle = π(r)² = 3.14(5)² = 78.5cm².

5. Find the area of the given parallelogram.

a) 142cm²
b) 284cm²
c) 144cm²
d) 288cm²
Answer: d
Clarification: Area of parallelogram = b × h = 12 × 24 = 288cm².

6. Match the following: (π = (frac{22}{7}))

A (Figuers)	B (Area)
i)	a) 616cm2
ii)	b) 143cm2
iii)	c) 121cm2
iv)	d) 5cm2

a) i – c; ii – d; iii – b; iv – d
b) i – c; ii – d; iii – b; iv – b
c) i – c; ii – d; iii – b; iv – c
d) i – c; ii – d; iii – b; iv – a
Answer: d
Clarification: i) Area of parallelogram = b × h = 11 × 11 = 121cm²
ii) Area of triangle = (frac{1}{2}) × b × h = (frac{1}{2}) × 2 × 5 = 5cm²
iii) Area of rectangle = l × b = 11 × 13 = 143cm²
iv) Area of circle = π(r)² = (frac{22}{7}) (14)² = 616cm².

7. Which of the following option is correct if a,b and c are the areas of the given figures (i), (ii) and (iii) respectively? (π = 22/7)

a) a < b < c
b) a > b > c
c) a < b > c
d) b < c > a
Answer: a
Clarification: Area of triangle = (frac{1}{2}) × b × h = (frac{1}{2}) × 2 × 5 = 5cm²
Area of rectangle = l × b = 5 × 2 = 10cm²
Area of circle = π(r)² = (frac{22}{7}) (7)² = 154cm².

8. Find the area of the given figure.

a) 3.14cm²
b) 31.4cm²
c) 3140cm²
d) 314cm²
Answer: d
Clarification: Area of semicircle = π (frac{(r)^2}{2}) = 3.14(10)² = 314cm².

9. Find the area of the Lawn.

a) 500m²
b) 101m²
c) 505m²
d) 504m²
Answer: c
Clarification: Area of lawn can be found by subtracting the area of inner rectangle from square.
Hence, Area of lawn = Area of square – Area of rectangle = (25)² – (15)(8) = 505m².

10. Calculate the area of the given figure.

a) 14.28cm²
b) 12.28cm²
c) 7.14cm²
d) 15cm²
Answer: a
Clarification: Area of the given figure = Area of semicircle – Area of triangle = π (frac{(r)^2}{2} + frac{1}{2}) × b × h
= π(frac{(2)^2}{2} + frac
{1}{2}) × 4 × 4 = 14.28cm².