# 250+ TOP MCQs on Air Refrigerator Working on Reverse Carnot Cycle and Answers

Refrigeration Multiple Choice Questions on “Air Refrigerator Working on Reverse Carnot Cycle”.

1. Out of the following reasons which one is responsible for Carnot cycle not being used in practice?
a) It gives low COP
b) It gives high refrigeration effect
c) It gives low refrigeration effect
d) It has low theoretical efficiency

Clarification: Carnot cycle is not used in everyday practice and one of the many reasons is that because it has low refrigeration effect, even though it has the highest theoretical efficiency and also it is not possible to carry out isothermal heat transfer in practice.

2. What is the coefficient of performance of the refrigerant system working on reversed Carnot cycle, having Qa as heat absorbed by the air during isothermal expansion per kg of air and Qr as heat rejected during isothermal compression per kg of air?
a) COP=(frac{Q_a}{(Q_r – Q_a)})
b) COP=(frac{Q_r}{(Q_r – Q_a)})
c) COP=(frac{Q_a}{(Q_r + Q_a)})
d) COP=(frac{Q_a}{(Q_a – Q_r)})

Clarification: COP of refrigerator is COP of heat pump – 1
i.e. ([frac{Q_r}{Q_r – Q_a}] – 1 = frac{Q_a}{(Q_r – Q_a)}).

3. The COP of refrigerator may be improved by _________
a) decreasing the higher (T2) as well as the lower (T1) temperature
b) decreasing the higher (T2) temperature and increasing the lower (T1) temperature
c) increasing the higher (T2) as well as the lower (T1) temperature
d) keeping the higher (T2) temperature the same while decreasing the lower (T1) temperature

Clarification: The COP of refrigerator can be given by :
COP = (frac{T_1}{(T_2- T_1)}). Hence by decreasing the higher temperature T2 or by increasing the lower temperature T1 the COP may be improved.

4. What happens to the COP of a Carnot refrigerator in summer and in winter?
a) The COP is more in winter
b) The COP is more in summer
c) The COP remains unaffected
d) The COP fluctuates continuously during winter and summer

Clarification: As the higher temperature T2 will always be lower in winter when compared with that of summer i.e. the temperature of air available of heat rejection will be low, the COP in winter will be higher.

5. A refrigerating machine working on Carnot cycle operates between 300K and 250K. Determine the COP.
a) 5
b) 6
c) 4
d) 10

Clarification: The COP of refrigerating machine is given by
COP = (frac{T_1}{(T_2- T_1)} = frac{250}{(300-250)})=5.

6. The COPr of a Carnot refrigerating machine is 7.89. What will be the COPp of heat pump?
a) 10.3
b) 7.89
c) 8.89
d) 6.89

Clarification: Relation between COP of heat pump and COP of the refrigerating machine is
COPr = COPp-1
7.89 = COPp-1
COPp=7.89+1=8.89.

7. Which one is not a limitation of the Carnot cycle with air or gas as refrigerant?
a) It has low efficiency when working between two fixed temperature limits
b) Machine has to run at high and low speeds during adiabatic and isothermal process. Such variation of speed is not possible
c) Extreme pressure and large volume are developed
d) It is not possible to carry out isothermal heat transfer process in practice