250+ TOP MCQs on Cascade Stages and Answers

Mass Transfer Multiple Choice Questions on “Cascade Stages”.

1. A device where two insoluble phases are brought into contact is known as
a) Trays
b) Stage
c) Cascade
d) Sieves
Answer: b
Clarification: The stage is a single device where the phases are allowed to contact each other.

2. Ideal stages are also known as
a) Equilibrium or Theoretical stages
b) Equilibrium or Actual stages
c) Differential or Theoretical stages
d) Differential or Actual stages
Answer: a
Clarification: Ideal stages are always equilibrium stages. Actual stages are practical stages hence theoretical stages are Ideal stages.

3. More than one stages are interconnected to form
a) Trays
b) Sieves
c) Cascades
d) Multiple stage
Answer: c
Clarification: More than one stage is cascades.

4. The main purpose of cascades is
a) To get maximum conversion
b) To increase mass transfer rates
c) To get more efficiency
d) None of the mentioned
Answer: b
Clarification: Though all the above mention is applicable, the main purpose is to increase the extent of mass transfer.

5. (Yn- Yn-1)/ (Yn*-Yn-1) is
a) Fractional overall
b) Murphree stage
c) Stage
d) Tray
Answer: b
Clarification: The leaving stream is in equilibrium with its actual concentration. It is known as Murphree stage efficiency.

6. Find the number of stage(s)

Where,
Y- Mole Ratio of gas phase
X- Mole Ratio of liquid phase
a) 1
b) 2
c) 1 to 2
d) No stage
Answer: a
Clarification: one operating line = one stage.

7. Murphree efficiency is defined as the number of equilibrium stages to the number of real stages.
a) True
b) False
Answer: b
Clarification: Fractional overall efficiency gives the ratio of equilibrium stage to real stage.

8. Find the value of y in an ideal single stage absorber is used to remove ammonia from gas with water as solvent. Its representation is given below

Here,
y0=0.2, the molar gas flow rates of liquid and gas mixture in (moles/sec) are 4 and 2. The equilibrium relation between y and x is given by y = 0.2x. The solvent water is pure.
a) 1/10
b) 1/20
c) 2/110
d) 2/220
Answer: b
Clarification:
2 (0.2) + 4(0) = 2 (y*) + 4(x)
As y= 0.2x
0.4= 0.4x + 4x
x= (1/11)
y= 2/110.

9. ______________ is defined as the number of equilibrium stages to the number of real stages.
a) Murphree stage efficiency
b) Fractional overall efficiency
c) Stage efficiency
d) Overall efficiency
Answer: b
Clarification: Fractional overall efficiency gives the ratio of equilibrium stage to real stage.

10. Find the Murphree stage efficiency for the following co-current operation with equilibrium leaving gas phase concentration Y*= 0.8.

Where,
G and L are gas and liquid flow rates
Y and X are concentration in mole ratio (Y1=0.2, Y2=0.4, X1= 0.6, X2=0.8)
a) 25%
b) 50%
c) 75%
d) 100%
Answer: a
Clarification: Murphree stage efficiency is= (Y2- Y1)/(Y2*- Y1)
Given gas phase leaving stream in equilibrium Y2*= 0.8
Then, Murphree stage efficiency is (0.2/0.8) x 100
Murphree stage efficiency is 25%.