This set of Strength of Materials Multiple Choice Questions on “Deflection of Propped Cantilever”.
1. The upward deflection caused by the prop is _____________
a) Pl3/2EI
b) Pl2/3EI
c) Pl3/3EI
d) Pl4/3EI
Answer: c
Clarification: The deflection developed by proper reaction at free end “y” = Pl3/3EI. A cantilever beam which is supported by an extra support when length of beam increases beyond limit is termed as propped cantilever in order to reduce the excessive deflection.
2. Stiffness of the propped cantilever is _________
a) 4EI/l
b) 6EI/l
c) 8EI/I
d) 5EI/l
Answer: a
Clarification: When is a structural member of uniform section is subjected to moment at one end then the moment develops which is required so as to rotate the end to produce unit slope. This is known as of the member. For propped cantilever, the stiffness is 4EI /l.
3. The major losses of energy due to friction are calculated by using _________
a) Ingli’s formulae
b) Emperical notations
c) Chezy’s Equation
d) Lacey’s Theory
Answer: c
Clarification: The major loss of energy is caused by friction and it is calculated by using either Darcy – Weisbach equation or chezy’s formula. The chezy’s formula V = C(mi)1/2. Formula for Darcy’s Weisbach equation is = 4fLV2 / 2gd.
4. The ratio of A/P is ___________
a) Hydraulic radius
b) Arbitrary datum
c) T E L
d) H G L
Answer: a
Clarification: The ratio to the cross sectional area and wetted perimeter is called hydraulic radius. It is also known as hydraulic mean depth. It is denoted by m.
5. Determine the velocity of flow in a pipe if the discharge capacity is 270 litres per second and cross sectional area is 5 cm2.
a) 4.5 m/s
b) 5.4 m/s
c) 3.4 m/s
d) 2.5 m/s
Answer: b
Clarification: Discharge (Q) = 270 lit/sec = 270 × 10-3 = 0.27 m3/ s.
Velocity of flow in narrow pipe = Q / A
= 0.27/ 0.05 = 5.4 m/s.
6. Calculate the reaction at prop of cantilever, if the span of beam is 5m and load is 20 kN.
a) 4.25 kN
b) 5 kN
c) 6.25 kN
d) 8 kN
Answer: c
Clarification: For analysing the prop reaction for a cantilever beam at free end = P = 5W/16
P = 5 × 20 / 16
P = 6.25 kN.
7. The highest point on syphon is known as ____
a) Summit
b) Crown
c) Limb
d) Tread
Answer: a
Clarification: A siphon is a long bent pipe used to transfer water from one reservoir to the other reservoir which is located at different elevations. The highest point of the siphon is known as Summit.
8. The position between the summit and the lower reservoir is known as ___________
a) Inlet leg
b) Outlet leg
c) Pressure head
d) Datum
Answer: b
Clarification: The portion of the syphon which lies above the HGL has negative pressures and the portion between the summit and the lower reservoir is known as out let leg. At the summit the pressure is minimum.
9. Full form of TEL is _________
a) Total Emission Line
b) Thermal Electro Light
c) Total Energy Line
d) Total Electro Light
