250+ TOP MCQs on Python Exception Handling and Answers

Python Multiple Choice Questions on “Exception Handling – 2”.

1. The following Python code will result in an error if the input value is entered as -5.

a) True
b) False
Answer: a
Clarification: The code shown above results in an assertion error. The output of the code is:
Traceback (most recent call last):
File “”, line 1, in
assert False, ‘Spanish’
AssertionError: Spanish
Hence, this statement is true.

2. What will be the output of the following Python code?

x=10
y=8
assert x>y, 'X too small'

a) Assertion Error
b) 10 8
c) No output
d) 108
Answer: c
Clarification: The code shown above results in an error if and only if xy, there is no error. Since there is no print statement, hence there is no output.

3. What will be the output of the following Python code?

#generator
def f(x):
    yield x+1
g=f(8)
print(next(g))

a) 8
b) 9
c) 7
d) Error
Answer: b
Clarification: The code shown above returns the value of the expression x+1, since we have used to keyword yield. The value of x is 8. Hence the output of the code is 9.

4. What will be the output of the following Python code?

def f(x):
    yield x+1
    print("test")
    yield x+2
g=f(9)

a) Error
b) test
c)

test
10
12

d) No output
Answer: d
Clarification: The code shown above will not yield any output. This is because when we try to yield 9, and there is no next(g), the iteration stops. Hence there is no output.

5. What will be the output of the following Python code?

def f(x):
    yield x+1
    print("test")
    yield x+2
g=f(10)
print(next(g))
print(next(g))

a) No output
b)

11
test
12

c)

11
test

d) 11
Answer: b
Clarification: The code shown above results in the output:
11
test
12
This is because we have used next(g) twice. Had we not used next, there would be no output.

6. What will be the output of the following Python code?

def a():
    try:
        f(x, 4)
    finally:
        print('after f')
    print('after f?')
a()

a) No output
b) after f?
c) error
d) after f
Answer: c
Clarification: This code shown above will result in an error simply because ‘f’ is not defined. ‘try’ and ‘finally’ are keywords used in exception handling.

7. What will be the output of the following Python code?

def f(x):
    for i in range(5):
        yield i
g=f(8)
print(list(g))

a) [0, 1, 2, 3, 4]
b) [1, 2, 3, 4, 5, 6, 7, 8]
c) [1, 2, 3, 4, 5]
d) [0, 1, 2, 3, 4, 5, 6, 7]
Answer: a
Clarification: The output of the code shown above is a list containing whole numbers in the range (5). Hence the output of this code is: [0, 1, 2, 3, 4].

8. The error displayed in the following Python code is?

import itertools
l1=(1, 2, 3)
l2=[4, 5, 6]
l=itertools.chain(l1, l2)
print(next(l1))

a) ‘list’ object is not iterator
b) ‘tuple’ object is not iterator
c) ‘list’ object is iterator
d) ‘tuple’ object is iterator