250+ TOP MCQs on Image Parameters and Answers

Network Theory Multiple Choice Questions on “Image Parameters”.

1. A network is said to be symmetrical if the relation between A and D is?
A. A = D
B. A = 2 D
C. A = 3 D
D. A = 4 D

Answer: A
Clarification: We know V₁=AV₂-BI₂ and I₁=CV₂-DI₂. If the network is symmetrical, then the relation between A and D is A = D.

2. The relation between Z₁₁ and Z₁₂ if the network is symmetrical is?
A. Z₁₁ = 2 Z₁₂
B. Z₁₁ = Z₁₂
C. Z₁₁ = 3 Z₁₂
D. Z₁₁ = 4 Z₁₂

Answer: B
Clarification: For a network to be symmetrical A=D. So the relation between Z₁₁ and Z₁₂ for the network is symmetrical is Z₁₁ = Z₁₂.

3. The relation between Z₁₂ and Z₁₁ and B and C parameters if the network is symmetrical is?
A. Z₁₁ = Z₁₂ = B/C
B. Z₁₁ = Z₁₂ = C/B
C. Z₁₁ = Z₁₂ = √(B/C.
D. Z₁₁ = Z₁₂ = √(C/B.

Answer: C
Clarification: For symmetrical network, A=D. On substituting this we get the relation between Z₁₂ and Z₁₁ and B and C parameters if the network is symmetrical is Z₁₁ = Z₁₂ = √(B/C..

4. Determine the transmission parameter A in the circuit shown below.
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A. 3/4
B. 4/3
C. 5/6
D. 6/5

Answer: D
Clarification: We know V₁=AV₂-BI₂ and I₁=CV₂-DI₂. A=(V₁/V₂) |I₂=0. On solving we get the transmission parameter A as A = 6/5.

5. Determine the transmission parameter B in the circuit shown below.

A. 17/5
B. 5/17
C. 13/5
D. 5/13

Answer: A
Clarification: The transmission parameter B is -V₁/I₂ |V₂=0. On short cicuiting the port 2, from the circuit we get -I₂ = (5/17)V₁ => -V₁/I₂ = 17/5. On substituting we get B = 17/5.

6. Determine the transmission parameter C in the circuit shown below.

A. 2/5
B. 1/5
C. 4/5
D. 3/5

Answer: B
Clarification: The transmission parameter C is I₁/V₂ |I₂=0. This parameter is obtained by open circuiting the port 2. So we get V₂ = 5I₁ => I₁/V₂ = 1/5. On substituting, we get C = 1/5.

7. Determine the transmission parameter D in the circuit shown below.
A. 3/5
B. 4/5
C. 7/5
D. 2/5

Answer: C
Clarification: The transmission parameter D is -I₁/I₂ |V₂=0. This is obtained by short circuiting the port 2. We get I₁ = (7/17)V₁ and -I₂ = (5/17)V₁. On solving, we get -I₁/I₂ = 7/5. On substituting we get D = 7/5.

8. The value of Z₁₁ in the circuit shown below is?
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A. 1.8
B. 2.8
C. 3.8
D. 4.8

Answer: C
Clarification: The relation between Z₁₁ and ABCD parameters is Z₁₁=√(AB/CD.. We know A = 6/5, B = 17/5, C = 1/5, D = 7/5. On substituting, Z₁₁ = √((6/5×17/5)/(1/5×7/5)) = 3.8Ω.

9. The value of Z₁₂ in the circuit shown below is?
A. 1.1
B. 2.2
C. 3.3
D. 4.4

Answer: D
Clarification: The relation between Z₁₂ and ABCD parameters is Z₁₂=√(BD/AC.. We got B = 17/5, D = 7/5, A = 6/5, C = 1/5. On substituting Z₁₂ = √(BD/AC. = √((17/5×7/5)/(6/5×1/5)) = 4.4Ω.

10. Determine the value of Ø in the circuit shown below.
A. 0.25
B. 0.5
C. 0.75
D. 1

Answer: C
Clarification: Ø is called image transfer constant and it is also used to describe reciprocal networks and this parameter is obtained from the voltage and current ratios. We know Ø = tanh^-1⁡√(BC/AD. = tanh^-1⁡√(17/42) = 0.75.