Network Theory Multiple Choice Questions on “Inter Connection of Two-Port Networks”.
A. 1
B. 2
C. 3
D. 4
Answer: C
Clarification: The Z –parameter Z11 is V1/I1, port 2 is open circuited. V1 = (1+2)I1 => V1/I1 = 3 and on substituting, we get Z11 = 3Ω.
2. In the circuit shown below, find the Z-parameter Z12.
A. 4
B. 3
C. 2
D. 1
Answer: C
Clarification: The Z-parameter Z12 is V2/I1 |I2=0. On open circuiting port 2 we obtain the equation, V1 = (2) I2 => V1/I1 = 2. On substituting we get Z12 = 2Ω.
3. In the circuit shown below, find the Z-parameter Z21.
A. 2
B. 4
C. 1
D. 3
Answer: A
Clarification: The Z-parameter Z21 is V2/I1 |I2=0. On open circuiting port 2, we get V2 = (2)I1 => V2/I1 = 2. On substituting we get Z21 = 2Ω.
4. In the circuit shown below, find the Z-parameter Z22.
A. 3
B. 2
C. 4
D. 1
Answer: A
Clarification: The Z-parameter Z21 is V2/I2 |I1=0. This parameter is obtained by open circuiting port 1. So we get V2 = (2 + 1)I2 => V2 = 3(I2) => V2/I2 = 3. On substituting Z21 = 3Ω.
5. In the circuit shown below, find the Z-parameter Z11.
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A. 10
B. 15
C. 20
D. 25
Answer: B
Clarification: The Z –parameter Z11 is V1/I1, port 2 is open circuited. V1 = (10 + 5)I1 => V1/I1 = 15 and on substituting, we get Z11 = 2.5Ω.
6. In the circuit shown below, find the Z-parameter Z12.
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A. 15
B. 10
C. 5
D. 1
Answer: C
Clarification: The Z-parameter Z12 is V2/I1 |I2=0. On open circuiting port 2 we obtain the equation, V1 = (5) I2 => V1/I1 = 5. On substituting we get Z12 = 5Ω.
7. From the circuits shown below, find the combined Z-parameter Z11.
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A. 8
B. 18
C. 28
D. 38
Answer: B
Clarification: The Z-parameter Z11 is Z11 = Z11x + Z11y and Z11x = 3, Z11y = 15. On substituting we get Z11 = 3 +15 = 18Ω.
8. From the circuits shown below, find the combined Z-parameter Z12.
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A. 4
B. 5
C. 6
D. 7
Answer: D
Clarification: The Z-parameter Z12 is Z12 = Z12x + Z12y and we have Z12x = 2, Z12y. On substituting we get Z12 = 2 + 5 = 7Ω.
9. From the circuits shown below, find the combined Z-parameter Z21.
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A. 7
B. 6
C. 5
D. 4
Answer: A
Clarification: The Z-parameter Z21 is Z21 = Z21x + Z21y and we have Z21x = 2, Z21y = 5. On substituting we get Z21 = 2 + 5 = 7Ω.
10. From the circuits shown below, find the combined Z-parameter Z22.
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A. 38
B. 28
C. 18
D. 8
Answer: B
Clarification: The Z-parameter Z22 is Z22 = Z22x + Z22y and we have Z22x = 3, Z22y = 25. On substituting we get Z22 = 3 +25 = 28Ω.
