Chemical Process Calculation Problems focuses on “Material balances for Multi-Unit System-Sequetial Multiunit System-I”.
For the given process, If the values of Feed 1, 2, 3, 4, 5 are 10, 20, 30, 40, 50 moles respectively.
1. What is the value of D?
a) 100
b) 120
c) 130
d) 150
Answer: d
Clarification: D = Feed (1 + 2 + 3 + 4 + 5).
2. What would be the value of D when feed 5 is inverted?
a) 50
b) 100
c) 150
d) 200
Answer: a
Clarification: D = Feed (1 + 2 + 3 + 4 – 5).
3. What would be the value of D when feed 4 is inverted?
a) 100
b) 110
c) 120
d) 130
Answer: b
Clarification: D = Feed (1 + 2 + 3 – 4 + 5).
4. What would be the value of D when feed 3 is inverted?
a) 90
b) 100
c) 150
d) 200
Answer: a
Clarification: D = Feed (1 + 2 – 3 + 4 + 5).
5. What would be the value of D when feed 2 is inverted?
a) 100
b) 110
c) 120
d) Not possible
Answer: d
Clarification: It is not a possible case.
6. What would be the value of D when feed 1 is inverted?
a) 100
b) 110
c) 120
d) 130
Answer: d
Clarification: D = Feed (-1 + 2 + 3 + 4 + 5).
7. What is the value of D when feed 3 is inverted?
a) 70
b) 80
c) 90
d) 100
Answer: c
Clarification: D = Feed (1 + 2 – 3 + 4 + 5).
8. What is the value of C when feed 3 is inverted?
a) 0
b) 80
c) 90
d) 100
Answer: c
Clarification: C = Feed (1 + 2 – 3).
9. What is the value of B when feed 3 is inverted?
a) 40
b) 80
c) 90
d) 100
Answer: d
Clarification: B = Feed (1 + 2 – 3 + 4).
10. What is the value of A when feed 3 is inverted?
a) 30
b) 80
c) 90
d) 100
Answer: a
Clarification: A is not depended on feed 3.
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