250+ TOP MCQs on Mesh Analysis and Answers

Network Theory Multiple Choice Questions on “Mesh Analysis”.

1. Mesh analysis is applicable for non planar networks also.
A. true
B. false

Answer: B
Clarification: Mesh analysis is applicable only for planar networks. A circuit is said to be planar if it can be drawn on a plane surface without crossovers.

2. A mesh is a loop which contains ____ number of loops within it.
A. 1
B. 2
C. 3
D. no loop

Answer: D
Clarification: A loop is a closed path. A mesh is defined as a loop which does not contain any other loops within it.

3. Consider the circuit shown below. The number mesh equations that can be formed are?

A. 1
B. 2
C. 3
D. 4

Answer: B
Clarification: We know if there are n loops in the circuit, n mesh equations can be formed. So as there are 2 loops in the circuit. So 2 mesh equations can be formed.

4. In the figure shown below, the current through loop 1 be I₁ and through the loop 2 be I₂, then the current flowing through the resistor R₂ will be?

A. I₁
B. I₂
C. I₁-I₂
D. I₁+I₂

Answer: C
Clarification: Through the resistor R₂ both the currents I₁, I₂ are flowing. So the current through R₂ will be I₁-I₂.

5. If there are 5 branches and 4 nodes in graph, then the number of mesh equations that can be formed are?
A. 2
B. 4
C. 6
D. 8

Answer: A
Clarification: Number of mesh equations = B-(N-1). Given number of branches = 5 and number of nodes = 4. So Number of mesh equations = 5-(4-1) = 2.

6. Consider the circuit shown in the figure. Find voltage V_x.

A. 1
B. 1.25
C. 1.5
D. 1.75

Answer: B
Clarification: Consider current I₁ (CW) in the loop 1 and I₂ (ACW) in the loop 2. So, the equations will be V_x+I₂-I₁=0. I₁=5/2=2.5A. I₂=4Vx/4= V_x. V_x+V_x-2.5=0. V_x = 1.25V.

7. Consider the circuit shown below. Find the current I₁.

A. 3.3
B. 4.3
C. 5.3
D. 6.3

Answer: B
Clarification: According to mesh analysis, (1+3+6)I₁ – 3(I₂) – 6(I₃) = 10
-3(I₁) + (2+5+3)I₂ = 4 -6(I₁) + 10(I₃) = -4 +20 On solving the above equations, I₁=4.3A.

8. Consider the following figure. Find the current I₂ (A..

A. 1.7
B. 2.6
C. 3.6
D. 4.6

Answer: A
Clarification: According to mesh analysis, (1+3+6)I₁ – 3(I₂) – 6(I₃) = 10. -3(I₁) + (2+5+3)I₂ = 4. -6(I₁1) + 10(I₃) = -4 + 20 On solving the above equations, I₂ =1.7A.

9. Consider the following figure. Find the current I₃ (A..

A. 4
B. 4.7
C. 5
D. 5.7

Answer: B
Clarification: According to mesh analysis, (1+3+6)I₁ – 3(I₂) – 6(I₃) = 10. -3(I₁) + (2+5+3)I₂ = 4. -6(I₁) + 10(I₃) = -4 + 20. On solving the above equations, I₃ = 4.7A.

10. Find current through R₂ resistor.

A. 3
B. 3.25
C. 3.5
D. 3.75

Answer: D
Clarification: Applying mesh analysis, 5(I₁) + 2(I₁-I₂) = 10. 10(I₂) + 2(I₂-I₁) + 40 = 0. On solving, I₁ = 0.5A, I₂ = -3.25A. So current through R₂ resistor is 0.5-(-3.25) = 3.75 A.