250+ TOP MCQs on The group by & having Clause and Answers

MySQL Multiple Choice Questions on “The group by & having Clause”.

1. What is the meaning of “GROUP BY” clause in Mysql?
a) Group data by column values
b) Group data by row values
c) Group data by column and row values
d) None of the mentioned

Answer: a
Clarification: None.

2. Which clause is similar to “HAVING” clause in Mysql?
a) SELECT
b) WHERE
c) FROM
d) None of the mentioned

Answer: b
Clarification: “WHERE” is also used to filter the row values in Mysql.

3. What is the meaning of “HAVING” clause in Mysql?
a) To filter out the row values
b) To filter out the column values
c) To filter out the row and column values
d) None of the mentioned

Answer: a
Clarification: None.

4. “COUNT” keyword belongs to which categories in Mysql?
a) Aggregate functions
b) Operators
c) Clauses
d) All of the mentioned

Answer: a
Clarification: None.

5. Which among the following belongs to an “aggregate function”?
a) COUNT
b) UPPER
c) LOWER
d) All of the mentioned

Answer: a
Clarification: None.

6. Which of the following belongs to an “aggregate function”?
a) COUNT
b) SUM/AVG
c) MIN/MAX
d) All of the mentioned

Answer: d
Clarification: None.

7. Which clause is used with an “aggregate functions”?
a) GROUP BY
b) SELECT
c) WHERE
d) Both GROUP BY and WHERE

Answer: a
Clarification: “GROUP BY” is used with aggregate functions.

8. What is the significance of the statement “GROUP BY d.name” in the following MySQL statement?

SELECT d.name, COUNT (emp_id) emp_no
FROM department d INNER JOIN Employee e
ON d.dept_id=e.emp_id
GROUP BY d.name

a) Aggregation of the field “name” of both table
b) Aggregation of the field “name” of table “department”
c) Sorting of the field “name”
d) None of the mentioned

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Answer: b
Clarification: “GROUP BY” clause s used for aggregation of field.

9. What is the significance of the statement “HAVING COUNT (emp_id)>2” in the following MySQL statement?

SELECT d.name, COUNT (emp_id) emp_no
FROM department d INNER JOIN Employee e
ON d.dept_id=e.emp_id
GROUP BY d.name
HAVING COUNT (emp_id)>2

a) Filter out all rows whose total emp_id below 2
b) Selecting those rows whose total emp_id>2
c) Filter out all rows whose total emp_id below 2 & Selecting those rows whose total emp_id>2
d) None of the mentioned

Answer: c
Clarification: “HAVING” clause are worked similar as “WHERE” clause.

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