250+ TOP MCQs on Types of Polymerisation Reactions and Answers

Chemistry Multiple Choice Questions for IIT JEE Exam on “Types of Polymerisation Reactions – 2”.

1. What is the polymer obtained from the condensation of NH₂-(CH₂)₆-NH₂ and COOH-(CH₂)₈-COOH?
a) Nylon-6,6
b) Nylon-6
c) Nylon-6,10
d) Terylene
Answer: c
Clarification: Nylons are polyamides obtained from the condensation between amines and dicarboxylic acids. The have amide linkages (NHCO). Hexamethylenediamine and sebacic acid from the polymer nylon-6,10.

2. Cyclohexanone on treatment with hydroxylamine gives P, which on treatment with sulphuric acid gives Q. When Q is heated with water at high temperature, R is obtained. Identify R.
a) Nylon-6
b) Caprolactam
c) Amino caproic acid
d) Nylon-6,6
Answer: a
Clarification: Nylon-6 is the polymer of caprolactam (Q), which is obtained from the oxidation of cyclohexane to give cyclohexanone(P), followed by treatment with H₂SO₄. Caprolactam on heating with water gives amino caproic acid which polymerises to nylon-6.

3. Glyptal is obtained from the condensation polymerisation of ethylene glycol with _______
a) terephthalic acid
b) phthalic acid
c) isophthalic acid
d) trimesic acid
Answer: b
Clarification: Glyptal is a polyester (containing COO linkages) obtained from the polycondensation reaction of ethane-1,2-diol and benzene-1,2-dicarboxylic acid (phthalic acid). It is cross-linked polymer.

4. Which of the following is not required for the production of dacron?
a) 450K temperature
b) Ethylene glycol
c) Terephthalic acid
d) Triethylaluminium-titanium tetrachloride
Answer: d
Clarification: Dacron or terylene is a polyester of ethylene glycol and terephthalic acid. It is produced by heating the two at 420-460K and in the presence of zinc acetate-antimony trioxide, which acts as a catalyst. On the other hand, triethylaluminium-tetrachloride is used in the synthesis of HDPE.

5. Identify the polymer generated by the reaction of methanal with the shown compound.

a) Melamine-formaldehyde
b) Novolac
c) Bakelite
d) Phenol-formaldehyde
Answer: a
Clarification: The compound shown is a heterocyclic triamine called melamine. It reacts with methanal to form a resin intermediate which polymerises to form a melamine-formaldehyde polymer.

6. Bakelite is a cross-linked polymer.
a) True
b) False
Answer: a
Clarification: Phenol-formaldehyde condensation initially forms a linear polymer, Novolac. This on further heating with formaldehyde undergoes cross-linking through CH₂ groups to form bakelite.

7. Which of the following phenols are able to form Novolac?
a) m-Hydroxybenzyl alcohol
b) o-Hydroxybenzyl alcohol and p-hydroxybenzyl alcohol
c) 2,4-(Dihydroxymethyl)phenol
d) 2,4,6-(Trihydroxymethyl)phenol
Answer: b
Clarification: Novolac is a linear chain phenol-formaldehyde polymer. The ortho and para hydroxy derivatives of benzyl alcohol, initially formed by the reaction of phenol with HCHO, further react with phenol to form compounds having benzene rings joined together by -CH₂– links (Novolac).

8. The compound shown is a ________

a) chain growth copolymer
b) step growth copolymer
c) chain growth homopolymer
d) step growth homopolymer
Answer: a
Clarification: The polymer shown is butadiene-styrene copolymer which is formed by the addition polymerisation of two different unsaturated compounds, 1,3-butadiene and styrene. It is tough and used as a substitute for natural rubber.

9. The polymer of type [-AAAABBBAAAABBB-]_n, where A and B are two different monomers, is called a ______ copolymer.
a) alternating
b) block
c) graft
d) random
Answer: b
Clarification: Bock copolymers are those in which blocks of each type of monomer alternate with each other. In this case, the block AAAA and block BBB are alternatively repeated after each other.

10. Which of the following is the monomer of natural rubber?
a) Neoprene
b) Isoprene
c) Chloroprene
d) Butadiene
Answer: b
Clarification: Isoprene (or 2-methyl-1,3-butadiene) repeats itself in a linear chain to form natural rubber. This is also called as cis-1,4-polyisoprene, in which the monomers are linked by weak van der Waals forces, thus making it elastic in nature.

11. Which of the following is incorrect regarding natural rubber?
a) Shows thermoplastic behaviour
b) Soluble in benzene
c) Resistant to attack by oxidising agents
d) Shows high water absorption capacity
Answer: c
Clarification: Natural rubber becomes soft at temperatures above 335K and shows brittle character at temperatures below 283K. Hence, it shows thermoplastic behaviour. It is soluble in non-polar solvents like benzene, toluene, etc. and is not susceptible to attack by oxidising agents.

12. Vulcanization is carried out with which element?
a) Sulphur
b) Phosphorous
c) Oxygen
d) Chlorine
Answer: a
Clarification: Vulcanization is a process of improving the physical properties of natural rubber by introducing sulphur cross-links at the reactive sites of double bonds. This is done by heating the rubber with sulphur and an additive.

13. X on polymerisation gives neoprene. Identify X.
a) 1-Chloro-1,3-butadiene
b) 2-Chloro-1,3-butadiene
c) 1-Methyl-1,3-butadiene
d) 2-Methyl-1,3-butadiene
Answer: b
Clarification: Neoprene or polyisoprene is a synthetic rubber obtained from the addition polymerisation of chloroprene (2-chloro-1,3-butadiene) through free radical mechanism. It has a better stability towards oxidation than natural rubber.

14. Buna-N involves acrylonitrile as one of the monomers.
a) True
b) False
Answer: a
Clarification: Buna-N is a nitrile rubber formed by the copolymerisation of 1,3-butadiene and acrylonitrile. On the other hand, buna-S is a styrene rubber, with vinylbenzene as one monomer in place of acrylonitrile.

Chemistry Multiple Choice Questions for IIT JEE Exam,