250+ TOP MCQs on Universal Gates and Answers

Computer Fundamentals Multiple Choice Questions on “Universal Gates”.

1. A ____________ is a circuit with only one output but can have multiple inputs.
a) Logic gate
b) Truth table
c) Binary circuit
d) Boolean circuit

Answer: a
Clarification: A logic gate is used to evaluate a Boolean expression.
It can have multiple inputs but can have only one output.
The different types of logic gates are AND, OR, NOT etc.

2. There are 5 universal gates.
a) True
b) False

Answer: b
Clarification: There are only 2 main universal gates: NAND and NOR.
A NAND gate as well as the NOR gate can be used to implement any other Boolean expression thus it is called as a universal gate.

3. The Output is LOW if any one of the inputs is HIGH in case of a _________ gate.
a) NOR
b) NAND
c) OR
d) AND

Answer: b
Clarification: In case of a NAND gate the output is LOW if any one of the inputs is HIGH (i.e. 1).
It gives a HIGH output only in one case when all the inputs given to it are LOW.

4. Which of the following correctly describes the distributive law.
a)( A+B)(C+D)=AB+CD
b) (A+B).C=AC+BC
c) (AB)(A+B)=AB
d) (A.B)C=AC.AB

Answer: b
Clarification: The second option correctly describes the distributive law.
(A+B).C =AC+BC.
Boolean Laws are used to implementing and simplifying Boolean expression.

5. The complement of the input given is obtained in case of:
a) NOR
b) AND+NOR
c) NOT
d) EX-OR

Answer: c
Clarification: The NOT gate, also called as the inverter gate is used to reverse the input which is given.
It gives an inverted output, thus gives the complement.
Expression for NOT gate: Y=A’, where A is the input.

6. How many AND gates are required to realize the following expression Y=AB+BC?
a) 4
b) 8
c) 1
d) 2

Answer: d
Clarification: 2 AND gates are required to realize the expression.
1 AND gate will be used to connect the inputs A and B whereas the other will be used to connect the inputs B and C.

7. Number of outputs in a half adder _____________
a) 1
b) 2
c) 3
d) 0

Answer: b
Clarification: A half adder gives two outputs.
One is called the sum and the other is carry.
Half adder can be implemented using an EXOR gate and an AND gate.

8. The ________ gate is an OR gate followed by a NOT gate.
a) NAND
b) EXOR
c) NOR
d) EXNOR

Answer: c
Clarification: A NOR gate is a universal gate which is an OR gate followed by a NOT gate.
It therefore reverses the output obtained by an OR gate.
It can be used to implement any Boolean expression.

9. The expression of a NAND gate is_______
a) A.B
b) A’B+AB’
c) (A.B)’
d) (A+B)’

Answer: c
Clarification: A NAND gate is an AND gate followed by a NOT gate.
It therefore inverts the output of an AND gate.
NAND gate is also a universal gate.

Leave a Reply

Your email address will not be published. Required fields are marked *