[Physics Class Notes] on Free Fall Pdf for Exam

Physics is one of the subjects which enjoys a diversity of opinions. There are students who just love physics and there are those who find it a little bit hard to understand. No matter which category you fall, the concept of Free Fall will surely stand before you in the exam. 

Free fall is one of the topics which can’t be ignored from the examination point of view. Examiners tend to test students’ capabilities through this topic on a recurrent basis. This means, having good command on Free Fall would give one good return. Students must read this topic in a comprehensive way and try to grasp all the important details on Free Fall. Making revision notes which is imperative should not be missed since they enhance our preparation for the same. Students are advised not to use unreliable sources that could hamper their score in the exams. 

Say goodbye to doubts and worries because has come up with an article Free Fall – Definition, Newtonian Mechanics and Solved Examples The article is prepared by expert teachers who have a good deal of teaching experience. The PDF of the article is also available on ‘s website which could be downloaded for free. It could be accessed on any device and doesn’t require any registration fee. Now the preparation of the student would never be hampered since she can study from anywhere at any time. 

 

Definition of Free Fall

Free fall is the movement of an object or body only under the influence of gravity. The acceleration is caused by this external force on the object, hence the motion of the object will be accelerated. Thus, free-fall motion is also popularly known as acceleration due to gravity. The acceleration in this motion is constant because the gravitational force rather than the pull is downwards and has a constant value. And the scenario will even be the same when a body has zero gravity. For example, say that the body is thrown upwards. Hence, the term acceleration due to gravity means that the motion of an object under free fall with constant acceleration (g) towards the Earth can be calculated as, 

 

g = 9.8m/s²

 

Motion Under Gravity Free Fall (Newtonian Mechanics)

The uniform gravitational field with zero air resistance: A small vertical distance close to the surface of the Earth where an object falls. As long as the air resistance is lower than the force of gravity on the body, or equivalently the terminal velocity of the body is much greater than the body’s velocity.

The initial velocity is v₀

The vertical velocity with respect to time is v(t)

The initial altitude is y₀

The altitude with respect to time is y(t)

The time elapsed is represented by t

The acceleration due to gravity (9.8 ms²near Earth’s surface) is denoted by g

v(t) = v0 – gt 

y(t) = v0t + y0 – [frac{1}{2}] gt2 

The uniform gravitational field in the presence of air resistance: In the case of the uniform gravitational the mass of an object be considered as m, and the cross-sectional area be A, and if the Reynolds number is above the critical limit such that the v of the square of the fall velocity is proportional to the air resistance, has an equation of motion under gravity free fall

[ mfrac{dv}{dt} = mg – frac{1}{2} rho]CDAv2

 

[where the air density is represented by ρ, and the drag coefficient is represented with CD, which even though depends on the Reynolds number yet commonly popular as a constant].

 

Let us think of a body that was at rest but now falling with no change In the density of the air with altitude, then the equation will be

v(t) = [v_{infty} tanh begin{pmatrix} frac{gt}{v_{infty}} end{pmatrix}],

 

Now when the terminal speed is provided, the equation will be,

 

[v_{infty} = sqrt{frac{2mg}{rho C_{D}A}}]

 

The vertical position of the body as a function of time can be found if the speed of the body against time can be integrated over time,

 

y = y0 – [v_{infty}^{2} ln cos h begin{pmatrix} frac{gt}{v_{infty}} end{pmatrix}],

The uniform gravitational field with air resistance applies to parachutists and skydivers’ motion while doing the activity and falling from a height.
 

Solved Examples

Question: Is the acceleration due to gravity or the value of ‘g’ a constant?

Let an object (say a ball) be dropped from a height on the surface of the Earth, but that height is minimal in comparison to the radius of the Earth (almost negligible). 

 

The force acting during free fall motion is equal to the force of gravitation between the falling body and the Earth

 

Therefore we can put this in the form of an equation,

 

F = [frac{GMm}{(R + h)^{2}} ]

 

where R = radius of the Earth 

where M = mass of the Earth ,and 

G = the universal gravitation constant, and

we also assume that (R+h) is almost equal as R, 

where R = radius of the Earth

 

∴F = [frac{GMm}{R^{2}}] Equation(1)

 

And according to Newton’s second law, F = ma 

 

And the acceleration due to gravity which is represented by g is also calculated by force per unit mass, then 

 

F = mg Equation(2)

 

From equations (1) and (2) we can equate,

 

mg = [G frac{Mm}{R^2} ] or 

 

g = [G frac{M}{R^2} ]  Equation(2)

Therefore, from equation number 3, we can see that the value of ‘g’ is not as constant as indifferent to G’s value, which is a universal constant. The value of the due to gravity depends upon the mass and radius of the object, and from which we can conclude that it will not be the same everywhere. But the freefall acceleration remains constant during the free fall motion. Therefore the equation of motion can be easily used if only the acceleration value is replaced by ‘g’ in all those equations.

 

Fun Facts

The motion of an object under free-fall: Long ago, Galileo discovered that all objects would experience the same ‘g,’ i.e., the acceleration due to gravity when the air resistance was not present. Later in 1971, astronaut D. Scott tried to experiment with this theory with practical proof as he on the Moon’s surface released a feather and a hammer from the same vertical length or height. The result was that the feather and the hammer both reached the ground of the Moon at the same time. This happened because, on the Moon, the gravitational pull is only one-sixth compared to that of Earth’s.

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Gearing up for the Finals 

Final examinations are the reelection of one’s preparation and organizational abilities. The student must keep some of the tips in mind before going for the exams. These tips will keep them ahead of others. 

A student must have gone through the previous year question before going for the previous year question papers and practice them thoroughly. One should ensure that the syllabus is complete, however, it doesn’t hurt if the students leave out the unimportant part from the syllabus.  Have a time management plan to tackle the question paper and remember to sleep well before the exam.