Python Multiple Choice Questions on “Formatting – 2”.
1. What will be the output of the following Python code snippet?
'%d %s %g you' %(1, 'hello', 4.0)
a) Error
b) 1 hello you 4.0
c) 1 hello 4 you
d) 1 4 hello you
Answer: c
Clarification: In the snippet of code shown above, three values are inserted into the target string. When we insert more than one value, we should group the values on the right in a tuple. The % formatting expression operator expects either a single item or a tuple of one or more items on its right side.
2. The output of which of the codes shown below will be: “There are 4 blue birds.”?
a) ‘There are %g %d birds.’ %4 %blue
b) ‘There are %d %s birds.’ %(4, blue)
c) ‘There are %s %d birds.’ %[4, blue]
d) ‘There are %d %s birds.’ 4, blue
Answer: b
Clarification: The code ‘There are %d %s birds.’ %(4, blue) results in the output: There are 4 blue birds. When we insert more than one value, we should group the values on the right in a tuple.
3. What will be the output of the python code shown below for various styles of format specifiers?
x=1234 res='integers:...%d...%-6d...%06d' %(x, x, x) res
a) ‘integers:…1234…1234 …001234’
b) ‘integers…1234…1234…123400’
c) ‘integers:… 1234…1234…001234’
d) ‘integers:…1234…1234…001234’
Answer: a
Clarification: The code shown above prints 1234 for the format specified %d, ‘1234 ’ for the format specifier %-6d (minus ‘-‘ sign signifies left justification), and 001234 for the format specifier %06d. Hence the output of this code is: ‘integers:…1234…1234 …001234’
4. What will be the output of the following Python code snippet?
x=3.3456789 '%f | %e | %g' %(x, x, x)
a) Error
b) ‘3.3456789 | 3.3456789+00 | 3.345678’
c) ‘3.345678 | 3.345678e+0 | 3.345678’
d) ‘3.345679 | 3.345679e+00 | 3.34568’
Answer: d
Clarification: The %f %e and %g format specifiers represent floating point numbers in different ways. %e and %E are the same, except that the exponent is in lowercase. %g chooses the format by number content. Hence the output of this code is: ‘3.345679 | 3.345679e+00 | 3.34568’.
5. What will be the output of the following Python code snippet?
x=3.3456789 '%-6.2f | %05.2f | %+06.1f' %(x, x, x)
a) ‘3.35 | 03.35 | +003.3’
b) ‘3.3456789 | 03.3456789 | +03.3456789’
c) Error
d) ‘3.34 | 03.34 | 03.34+’
Answer: a
Clarification: The code shown above rounds the floating point value to two decimal places. In this code, a variety of addition formatting features such as zero padding, total field width etc. Hence the output of this code is: ‘3.35 | 03.35 | +003.3’.
6. What will be the output of the following Python code snippet?
x=3.3456789 '%s' %x, str(x)
a) Error
b) (‘3.3456789’, ‘3.3456789’)
c) (3.3456789, 3.3456789)
d) (‘3.3456789’, 3.3456789)
Answer: b
Clarification: We can simply convert strings with a %s format expression or the str built-in function. Both of these methods have been shown in this code. Hence the output is: ) (‘3.3456789’, ‘3.3456789’)
7. What will be the output of the following Python code snippet?
'%(qty)d more %(food)s' %{'qty':1, 'food': 'spam'}
a) Error
b) No output
c) ‘1 more foods’
d) ‘1 more spam’
Answer: d
Clarification: String formatting also allows conversion targets on the left to refer to the keys in a dictionary coded on the right and fetch the corresponding values. In the code shown above, (qty) and (food) in the format string on the left refers to keys in the dictionary literal on the right and fetch their assorted values. Hence the output of the code shown above is: 1 more spam.
8. What will be the output of the following Python code snippet?
a) {‘a’ : ‘hello’, ‘q’ : 10, ……..plus built-in names set by Python….}
b) {……Built in names set by Python……}
c) {‘a’ : ‘hello’, ‘q’ : 10}
d) Error
Answer: a
Clarification: The built in function vars() returns a dictionary containing all the variables that exist in the place. Hence the output of the code shown above is: {‘a’ : ‘hello’, ‘q’ : 10, ……..plus built-in names set by Python….}
9. What will be the output of the following Python code?
s='{0}, {1}, and {2}' s.format('hello', 'good', 'morning')
a) ‘hello good and morning’
b) ‘hello, good, morning’
c) ‘hello, good, and morning’
d) Error
Answer: c
Clarification: Within the subject string, curly braces designate substitution targets and arguments to be inserted either by position or keyword. Hence the output of the code shown above:’hello, good,and morning’.
10. What will be the output of the following Python code?
s='%s, %s & %s' s%('mumbai', 'kolkata', 'delhi')
a) mumbai kolkata & delhi
b) Error
c) No output
d) ‘mumbai, kolkata & delhi’
Answer: d
Clarification: In the code shown above, the format specifier %s is replaced by the designated substitution. Hence the output of the code shown above is: ‘mumbai, kolkata & delhi’.
11. What will be the output of the following Python code?
t = '%(a)s, %(b)s, %(c)s' t % dict(a='hello', b='world', c='universe')
a) ‘hello, world, universe’
b) ‘hellos, worlds, universes’
c) Error
d) hellos, world, universe
Answer: a
Clarification: Within the subject string, curly braces represent substitution targets and arguments to be inserted. Hence the output of the code shown above:
‘hello, world, universe’.
12. What will be the output of the following Python code?
'{a}, {0}, {abc}'.format(10, a=2.5, abc=[1, 2])
a) Error
b) ‘2.5, 10, [1, 2]’
c) 2.5, 10, 1, 2
d) ’10, 2.5, [1, 2]’
Answer: b
Clarification: Since we have specified that the order of the output be: {a}, {0}, {abc}, hence the value of associated with {a} is printed first followed by that of {0} and {abc}. Hence the output of the code shown above is: ‘2.5, 10, [1, 2]’.
13. What will be the output of the following Python code?
a) ‘1’
b) ‘1.234’
c) ‘1.23’
d) ‘1.2’
Answer: c
Clarification: The code shown above displays the string method to round off a given decimal number to two decimal places. Hence the output of the code is: ‘1.23’.
14. What will be the output of the following Python code?
a) ‘ff, 255’
b) ‘255, 255’
c) ‘15f, 15f’
d) Error
Answer: a
Clarification: The code shown above converts the given arguments to hexadecimal and decimal values and prints the result. This is done using the format specifiers %x and %d respectively. Hence the output of the code shown above is: ‘ff, 255’.
15. The output of the two codes shown below is the same.
i. '{0:.2f}'.format(1/3.0) ii. '%.2f'%(1/3.0)
a) True
b) False
Answer: a
Clarification: The two codes shown above represent the same operation but in different formats. The output of both of these functions is: ‘0.33’. Hence the statement is true.