Computer Organization and Architecture Multiple Choice Questions on “Multiplication”.
1. The product of 1101 & 1011 is ______
a) 10001111
b) 10101010
c) 11110000
d) 11001100
Answer: a
Clarification: The above operation is performed using binary multiplication.
2. We make use of ______ circuits to implement multiplication.
a) Flip flops
b) Combinatorial
c) Fast adders
d) None of the mentioned
Answer: c
Clarification: The fast adders are used to add the multiplied numbers.
3. The multiplier is stored in ______
a) PC Register
b) Shift register
c) Cache
d) None of the mentioned
Answer: b
Clarification: The value is stored in a shift register so that each bit can be accessed separately.
4. The ______ is used to coordinate the operation of the multiplier.
a) Controller
b) Coordinator
c) Control sequencer
d) None of the mentioned
Answer: c
Clarification: This performs the required sequencing of the various parts of the circuit.
5. The multiplicand and the control signals are passed through to the n-bit adder via _____
a) MUX
b) DEMUX
c) Encoder
d) Decoder
Answer: a
Clarification: None.
6. The product of -13 & 11 is ______________
a) 1100110011
b) 1101110001
c) 1010101010
d) 1111111000
Answer: b
7. The method used to reduce the maximum number of summands by half is _______
a) Fast multiplication
b) Bit-pair recording
c) Quick multiplication
d) None of the mentioned
Answer: b
Clarification: It reduces the number of summands by concatenating them.
8. The bits 1 & 1 are recorded as _______ in bit-pair recording.
a) -1
b) 0
c) +1
d) both -1 and 0
Answer: d
Clarification: Its ‘-1’ when the previous bit is 0 and ‘0’ when the previous bit is 1.
9. The multiplier -6(11010) is recorded as _______
a) 0-1-2
b) 0-1+1-10
c) -2-10
d) None of the mentioned
Answer: a
10. CSA stands for?
a) Computer Speed Addition
b) Carry Save Addition
c) Computer Service Architecture
d) None of the mentioned
Answer: a
Clarification: The CSA is used to speed up the addition of multiplicands.